Explanation Given information: θ = θ M sin ( k t ) ...... ( 1 ) Calculation: Differentiate with respect to t, we get d θ d t = θ M cos ( k t ) × k d θ d t = θ M k cos ( k t ) Again, differentiate with respect to t, we get d 2 θ d t 2 = θ M k ( − sin ( k t ) × k ) <

Calculus: Special Edition: Chapters 1-5 (w/ WebAssign)

6th Edition

ISBN: 9781524908102

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Chapter 3, Problem 63SP

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Toproof: d2θdt2+k2θ=0

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Chapter 3, Problem 62SP

Chapter 3, Problem 64SP

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Chapter 3 Solutions

Calculus: Special Edition: Chapters 1-5 (w/ WebAssign)

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Toproof : d 2 θ d t 2 + k 2 θ = 0

Solution Summary: The author explains how to differentiate with respect to t.

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Toproof: d2θdt2+k2θ=0

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Chapter 3 Solutions