Explanation Given information : The tension in chain AB ( F A B ) is 450 lb. The tension in chain AC ( F A C ) is 480 lb. Show the free body diagram of the forces acting on chain as in Figure 1. Using Figure (1), Determine the weight of the engine by applying the equation of equilibrium. Along horizontal direction : ∑ F x = 0 − F A B + F A C cos θ A C = 0 F A B = F A C cos θ A C (I) Here, the angle for the tension force AC is θ A C . Along vertical direction : ∑ F y = 0 F A C sin θ A C − W = 0 F A C sin θ A C = W (II) Conclusion : Assume the chain AB reaches the maximum tension. Substitute 450 lb for F A B and 30 ° for θ A C in Equation (I)

Engineering Mechanics: Statics & Dynamics (14th Edition)

14th Edition

ISBN: 9780133915426

Author: Russell C. Hibbeler

Publisher: PEARSON

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Chapter 3.4, Problem 2RP

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The maximum weight (W) of the engine.

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Engineering Mechanics: Statics & Dynamics (14th Edition)

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The maximum weight ( W ) of the engine.

Solution Summary: The author shows the free body diagram of the forces acting on chain as in Figure 1.

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Chapter 3 Solutions