In Exercises 19 through 24, find the matrix B of the linear transformation T ( x → ) = A x → with respect to the basis = ( v → 1 , v → 2 ) . For practice, solve each problem in three ways: (a) Use the formula B = S − 1 A S , (b) use a commutative diagram (as in Examples 3 and 4), and (c) construct B “column by column.” 23. A = [ 5 − 3 6 − 4 ] ; v → 1 = [ 1 1 ] , v → 2 = [ 1 2 ]
In Exercises 19 through 24, find the matrix B of the linear transformation T ( x → ) = A x → with respect to the basis = ( v → 1 , v → 2 ) . For practice, solve each problem in three ways: (a) Use the formula B = S − 1 A S , (b) use a commutative diagram (as in Examples 3 and 4), and (c) construct B “column by column.” 23. A = [ 5 − 3 6 − 4 ] ; v → 1 = [ 1 1 ] , v → 2 = [ 1 2 ]
Solution Summary: The author explains how the matrix B of the linear transformation can be found by B=S-1AS where matrix S is obtained from basis vectors.
In Exercises 19 through 24, find the matrix B of the linear transformation
T
(
x
→
)
=
A
x
→
with respect to the basis
=
(
v
→
1
,
v
→
2
)
. For practice, solve each problem in three ways: (a) Use the formula
B
=
S
−
1
A
S
, (b) use a commutative diagram (as in Examples 3 and 4), and (c) construct B “column by column.”
23.
A
=
[
5
−
3
6
−
4
]
;
v
→
1
=
[
1
1
]
,
v
→
2
=
[
1
2
]
I want to learn this topic l dont know anything about it
Solve the linear system of equations attached using Gaussian elimination (not Gauss-Jordan) and back subsitution.
Remember that:
A matrix is in row echelon form if
Any row that consists only of zeros is at the bottom of the matrix.
The first non-zero entry in each other row is 1. This entry is called aleading 1.
The leading 1 of each row, after the first row, lies to the right of the leading 1 of the previous row.
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Linear Equation | Solving Linear Equations | What is Linear Equation in one variable ?; Author: Najam Academy;https://www.youtube.com/watch?v=tHm3X_Ta_iE;License: Standard YouTube License, CC-BY