The reason that D- glucose and L- glucose bind differently to enzymes. Introduction: Isomers are molecules with the same chemical formula but different structure. Different structures lead to different biological activity. Isomers are grouped into two categories: structural isomers and stereoisomers. Stereoisomers have the same bond relation but the spatial location of the atoms is different from the isomers. They are further of two types: cis and trans isomers. Other types of stereoisomers that exist are enantiomers that exist as of a pair of molecules that are mirror images. Four different atoms can bind to a single carbon atom in two possible ways, designated as a left-handed and a right-handed structure. The resulting structures are not identical, but instead, are mirror images of each other.

Question

Want to see the full answer?

Answer 1

Question

Chapter 3.4, Problem 1CC

Summary Introduction

To explain: The reason that D- glucose and L- glucose bind differently to enzymes.

Introduction: Isomers are molecules with the same chemical formula but different structure. Different structures lead to different biological activity. Isomers are grouped into two categories: structural isomers and stereoisomers. Stereoisomers have the same bond relation but the spatial location of the atoms is different from the isomers. They are further of two types: cis and trans isomers. Other types of stereoisomers that exist are enantiomers that exist as of a pair of molecules that are mirror images. Four different atoms can bind to a single carbon atom in two possible ways, designated as a left-handed and a right-handed structure. The resulting structures are not identical, but instead, are mirror images of each other.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

19. On the diagram below a. Label the three pictures as: DNA; polypeptide; or RNA. b. Label the arrows as: translation or transcription/RNA processing. c. Add the following details to the diagram. Promoter region TATA box Transcription start site Transcription terminator Intron (A,B,C,D) Exons (1,2,3,4,5) Splice sites 5' cap 5' UTR (untranslated region) 3' poly A tail 3' UTR (untranslated region) Translational start (AUG) Translational stop (UGA, UAG, or UAA) N and C ends of polypeptide 0000

Match the letter labels in the figure below to the terms. Some letter labels are not used. MNNNNNNIN M C B A M D F E H K G 8

The diagram below illustrates a quorum sensing pathway from Staphylococcus aureus. Please answer the following questions. 1. Autoinduction is part of the quorum sensing system. Which promoter (P2 or P3) is critical for autoinduction? 2)This staphylococcus aureus grows on human wounds, causing severe infections. You would like to start a clinical trial to treat these wound infections. Please describe: a) What molecule do you recommend for the trial. Why? b) Your trial requires that Staphylococcus aureus be isolated from the wound and submitted to genome sequencing before admittance. Why? What are you testing for? 3) If a mutation arises where the Promoter P3 is constitutively active, how would that influence sensitivity to AIP? Please explain your rationale. 4) This pathway is sensitive to bacterial cell density. Describe two separate mutation that would render the pathway active independent of cell density. Briefly explain your rationale. Mutation 1 Mutation 2