Degarmo's Materials And Processes In Manufacturing
13th Edition
ISBN: 9781119492825
Author: Black, J. Temple, Kohser, Ronald A., Author.
Publisher: Wiley,
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Chapter 34, Problem 15RQ
To determine
The prevention of widespread applications of FMS.
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Q4/ A compressor is driven motor by mean of a flat belt of thickness 10 mm and a width of
250 mm. The motor pulley is 300 mm diameter and run at 900 rpm and the compressor
pulley is 1500 mm diameter. The shaft center distance is 1.5 m. The angle of contact of
the smaller pulley is 220° and on the larger pulley is 270°. The coefficient of friction
between the belt and the small pulley is 0.3, and between the belt and the large pulley is
0.25. The maximum allowable belt stress is 2 MPa and the belt density is 970 kg/m³.
(a) What is the power capacity of the drive and (b) If the small pulley replaced by
V-grooved pulley of diameter 300 mm, grooved angle of 34° and the coefficient of
friction between belt and grooved pulley is 0.35. What will be the power capacity in this
case, assuming that the diameter of the large pulley remain the same of 1500 mm.
You are tasked with designing a power drive system to transmit power between a motor and a conveyor belt in a manufacturing facility as illustrated in figure.
The design must ensure efficient power transmission, reliability, and safety. Given the following specifications and constraints, design drive system for this application:
Specifications:
Motor Power: The electric motor provides 10 kW of power at 1,500 RPM.
Output Speed: The output shaft should rotate at 150 rpm.
Design Decisions:
Transmission ratio: Determine the necessary drive ratio for the system.
Shaft Diameter: Design the shafts for both the motor and the conveyor end.
Material Selection: Choose appropriate materials for the gears, shafts.
Bearings: Select suitable rolling element bearings.
Constraints:
Space Limitation:
The available space for the gear drive system is limited to a 1-meter-long section.
Attribute 4 of CEP
Depth of knowledge required
Fundamentals-based, first principles analytical approach…
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العنوان
In non-continuous dieless drawing process for copper tube as shown in Fig. (1), take the
following data: Do-20mm, to=3mm, D=12mm, ti/to=0.6 and v.-15mm/s. Calculate: (1)
area reduction RA, (2) drawing velocity v. Knowing that: ti: final thickness
V.
Fig. (1)
ofthre
Chapter 34 Solutions
Degarmo's Materials And Processes In Manufacturing
Ch. 34 - Prob. 1RQCh. 34 - Give an everyday example of a household device or...Ch. 34 - Prob. 3RQCh. 34 - Prob. 4RQCh. 34 - Prob. 5RQCh. 34 - Prob. 6RQCh. 34 - How is a machining center different from a milling...Ch. 34 - Prob. 8RQCh. 34 - What makes an NC machine a machining center?Ch. 34 - At what level of automation is your typical...
Ch. 34 - Figure 24.6 shows tool paths to rough and finish...Ch. 34 - In Figure 34.6. what is a G70 finish cycle (see...Ch. 34 - Prob. 13RQCh. 34 - Prob. 14RQCh. 34 - Prob. 15RQCh. 34 - Prob. 16RQCh. 34 - What is the difference between an FMS and an FMC?Ch. 34 - What does the A(5) level of automation require...Ch. 34 - Prob. 19RQCh. 34 - Prob. 20RQCh. 34 - Prob. 21RQCh. 34 - Prob. 22RQCh. 34 - Prob. 23RQCh. 34 - FMSs use CNC machines for processing and AGVs,...Ch. 34 - Why are transfer lines replacing relay logic with...Ch. 34 - Prob. 26RQCh. 34 - Prob. 27RQCh. 34 - Prob. 28RQCh. 34 - Prob. 29RQCh. 34 - Prob. 30RQCh. 34 - Prob. 31RQCh. 34 - Compare a human worker in a manned cell to the...Ch. 34 - Prob. 33RQCh. 34 - What is a teach pendant?Ch. 34 - Prob. 35RQCh. 34 - Prob. 1PCh. 34 - Prob. 2PCh. 34 - Prob. 3P
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