Degarmo's Materials And Processes In Manufacturing
13th Edition
ISBN: 9781119492825
Author: Black, J. Temple, Kohser, Ronald A., Author.
Publisher: Wiley,
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Chapter 34, Problem 12RQ
In Figure 34.6. what is a G70 finish cycle (see Chapter 26)?
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In a production turning operation, the workpart is 60 mm in diameter and 500 mm long. A feed of 0.75 mm/rev is used in the operation. If cutting speed=9 m/s, the tool must be changed every 4 workparts; But if cutting speed=5 m/s, the tool can be used to produce 50 pieces between tool changes. Determine the Taylor tool life equation for this job. (use the equations given below for solution)
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Chapter 34 Solutions
Degarmo's Materials And Processes In Manufacturing
Ch. 34 - Prob. 1RQCh. 34 - Give an everyday example of a household device or...Ch. 34 - Prob. 3RQCh. 34 - Prob. 4RQCh. 34 - Prob. 5RQCh. 34 - Prob. 6RQCh. 34 - How is a machining center different from a milling...Ch. 34 - Prob. 8RQCh. 34 - What makes an NC machine a machining center?Ch. 34 - At what level of automation is your typical...
Ch. 34 - Figure 24.6 shows tool paths to rough and finish...Ch. 34 - In Figure 34.6. what is a G70 finish cycle (see...Ch. 34 - Prob. 13RQCh. 34 - Prob. 14RQCh. 34 - Prob. 15RQCh. 34 - Prob. 16RQCh. 34 - What is the difference between an FMS and an FMC?Ch. 34 - What does the A(5) level of automation require...Ch. 34 - Prob. 19RQCh. 34 - Prob. 20RQCh. 34 - Prob. 21RQCh. 34 - Prob. 22RQCh. 34 - Prob. 23RQCh. 34 - FMSs use CNC machines for processing and AGVs,...Ch. 34 - Why are transfer lines replacing relay logic with...Ch. 34 - Prob. 26RQCh. 34 - Prob. 27RQCh. 34 - Prob. 28RQCh. 34 - Prob. 29RQCh. 34 - Prob. 30RQCh. 34 - Prob. 31RQCh. 34 - Compare a human worker in a manned cell to the...Ch. 34 - Prob. 33RQCh. 34 - What is a teach pendant?Ch. 34 - Prob. 35RQCh. 34 - Prob. 1PCh. 34 - Prob. 2PCh. 34 - Prob. 3P
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- A cemented carbide tool is used to turn a part with length = 18.0 in and diameter = 3.0 in. The parameters in the Taylor equation are: n = 0.27 and C = 1200. The rate for the operator and machine tool = $33.00/hr, and the tooling cost per cutting edge = $2.00. It takes 3.0 min to load and unload the workpart and 1.50 min to change tools. The feed = 0.013 in/rev. Determine: Cutting speed for maximum production rate, Tool life in min of cutting, and Cycle time and cost per unit of product.arrow_forwardE Expert Q&A 1. Shaper (#X) Machine function and design requirements: The main function of this machine is to make surface more smooth; The required movements are: Reciprocating movement of planer knife and feed movement of the bow. It is required that the cutting speed is uniform, while the quirkily return is included. The basic data is: principal axis rotation speed is 60 r/min, the max length is less than 450 mm, the distance between working surface and the floor is 800 mm. Travel speed ratio co-efficient is 1.5, allowable pressure angle 15°, cutting quantity is 0.1~0.5 mm. Requirements: 1. Freedom calculations; 2. Force analysis; 3. Make this machine, and display; please give a solution with given condition.arrow_forwardthickness is HW3.A block of steel has a length L-600mm and a width W-450mm. The Machined 10mm, once by Peripheral Milling and once by planing Machine.Calculate :Machining time for each operation if you know the following For peripheral milling: cutting speed V =80 m/min, Feed f-0.15mm/rev, the cutter .1 diameter D =50 mm with five teeth and depth of cut d =3mm For planing: clearance on both sides c =25mm, cutting speed V =36.56 m/min, retum to .2 cutting ratio m =0.25, feed f=5 mm/stroke and depth of cut d =5 mm .Calculate Material removal rate in both processes .3 Solutionarrow_forward
- In a production turning operation, the workpart is 60 mm in diameter and 500 mm long. A feed of 0.75 mm/rev is used in the operation. If cutting speed-9 m/s, the tool must be changed every 4 workparts; But if cutting speed=5 m/s, the tool can be used to produce 50 pieces between tool changes. Determine the Taylor tool life equation for this job. (use the equations given below for solution) L Tm- 1,= Nf N AD, vT" = C %3| AD,L Tm fvarrow_forwardIn a production turning operation, the workpart is 60 mm in diameter and 500 mm long. A feed of 0.75 mm/rev is used in the operation. If cutting speed=9 m/s, the tool must be changed every 4 workparts; But if cutting speed=5 m/s, the tool can be used to produce 50 pieces between tool changes. Determine the Taylor tool life equation for this job. (use the equations given below for solution)arrow_forwardSketch and explain any four Shaper operations?arrow_forward
- Q1:- Put a mark of True or false for below:- (a):- The milling cutting tool has a single cutting edge? (b):- At the break-even point, the total revenue equals the total cost? (c):- The right-hand rule is used to define machine axes? (d):- Design error is a simple mistake? (e):- The quality of products is poor in mass production? (f):- Allowances must be left before turning? (g):- Up-ward milling is better than down-ward milling?arrow_forwardA workpiece of 2000 mm length and 300 mm width was machined by a planning operation with the feed set at 0.3 mm/stroke. If the machine tool executes 10 double strokes/min, What is the planning time for a single pass?arrow_forwardCalculate spindle RPM and machining time for cutting a 1.5" diameter 4" long at 225 SFPM using a feed rate of 0.004".arrow_forward
- Mention the difference between Shaper machine and planer machine?arrow_forward34 - The outside diameter of a cylinder made of titanium alloy is to be turned. The starting diameter is 400 mm and the length is 1100 mm. The feed is 0.35 mm/rev and the depth of cut is 2.5 mm. The cut will be made with a cemented carbide cutting tool whose Taylor tool life parameters are: n= 0.24 and C-450. Units for the Taylor equation are min for tool life and m/min for cutting speed. Compute the cutting speed that will allow the tool life to be just equal to the cutting time for this part. vT" = C . AD,L Tm %3D fv a) 325.8 m /min b) 275.8 m/min 226.6 m/min d) O 187.9 m/minarrow_forwardWhat is the working principle of shaper machine?arrow_forward
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