An arrow representation of ∇ S .

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Chapter 3.4, Problem 11E

To determine

An arrow representation of ∇S.

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We can use Eq. 1.7 to find A A = 7 and B = 4) and the angle Then we get: 26. Find the angle between A = -5i - 3j + 2k and B -2j - 2k. [Ser4 7-20] Eq. 1.7 allows us to find the cosine of the angle between two vectors as long as we know their magnitudes and their dot product. The magnitudes of the vectors A and B are: (−5)² + (−3)² + (2)² = 6.164 B = and their dot product is: A B = AB cos = (7)(4) cos 60° = 14 A = A² + A² + A² = = which then gives A · B = AxBx+ AyBy + A₂B₂ = (−5)(0) + (−3)(−2) + (2)(−2) = 2 1.2. WORKED EXAMPLES √B²+ B²+ B² = √(0)² + (−2)² + (−2)² = 2.828 B. We have the magnitudes of the two vectors (namely between the two is = 130° 70° = 60°. Then from Eq. 1.7, if o is the angle between A and B, we have 2 (6.164) (2.828) This gives us: coso = From which we get by: A.B AB = 27. Two vectors a and b have the components, in arbitrary units, ax = 3.2, ay = 1.6, b = 0.50, by = 4.5. (a) Find the angle between the directions of a and b. (b) Find the components of a vector c that…

Electromagnetics