Concept explainers
(a)
Interpretation: The explosion of dynamite produces a mixture of gases. The balanced equation is to be interpreted for the explosive decomposition of liquid nitroglycerin to produce a mixture of gases-carbon dioxide, water vapor, nitrogen, and oxygen.
Concept Introduction: The transformation of reactant molecules into product molecules is represented by a
Chemical equations can be used to represent a chemical reaction. The conversion is represented by a single-headed arrow and the chemical formula of the reactant and product molecules.
(b)
Interpretation: In the self-contained breathing apparatus, solid potassium superoxide reacts with carbon dioxide to form oxygen gas and solid potassium carbonate. The balanced equation is to be interpreted for the given reaction.
Concept Introduction: The transformation of reactant molecules into product molecules is represented by a chemical reaction. It entails the forming and breaking of chemical compound bonds.
Chemical equations can be used to represent a chemical reaction. The conversion is represented by a single-headed arrow and the chemical formula of the reactant and product molecules.
(c)
Interpretation: In a blast furnace, solid iron (III) oxide reacts with carbon monoxide to form solid iron and carbon dioxide. The balanced equation is to be interpreted for the given reaction.
Concept Introduction: The transformation of reactant molecules into product molecules is represented by a chemical reaction. It entails the forming and breaking of chemical compound bonds.
Chemical equations can be used to represent a chemical reaction. The conversion is represented by a single-headed arrow and the chemical formula of the reactant and product molecules.

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Chapter 3 Solutions
LL CHEM: MOL NAT CHNG W/CNCT AC
- Imagine each of the molecules shown below was found in an aqueous solution. Can you tell whether the solution is acidic, basic, or neutral? molecule 0=0 H3N-CH-C-o HO CH2 OH The solution is... O acidic O basic O neutral O (unknown) H₂N acidic O basic O neutral ○ (unknown) + H3N O OH O acidic O basic O neutral O (unknown) H2N-CH-C-O CH3 O acidic O basic neutral ○ (unknown) X ? olo HEarrow_forwardRecognizing ampli Draw an a amino acid with a methyl (-CH3) side chain. Explanation Check Click and drag to start drawing a structure. X Carrow_forwardWrite the systematic name of each organic molecule: structure name × HO OH ☐ OH CI CI O CI OH OHarrow_forward
- く Check the box under each a amino acid. If there are no a amino acids at all, check the "none of them" box under the table. Note for advanced students: don't assume every amino acid shown must be found in nature. COO H3N-C-H CH2 HO CH3 NH3 O CH3-CH CH2 OH Onone of them Explanation Check + H3N O 0. O OH + NH3 CH2 CH3-CH H2N C-COOH H O HIC + C=O H3N-C-O CH3- - CH CH2 OH Х 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Accesarrow_forwardWrite the systematic name of each organic molecule: structure HO-C-CH2-CH3 O -OH CH3-CH2-CH2-CH2-CH2-C-OH CH3 CH3-CH-CH2-C-OH Explanation Check S namearrow_forwardtheres 2 productsarrow_forward
- Draw the major product of this solvolysis reaction. Ignore any inorganic byproducts. + CH3CH2OH Drawing Q Atoms, Bonds and Rings OCH2CH3 || OEt Charges OH 00-> | Undo Reset | Br Remove Done Drag To Pan +arrow_forwardDraw the major product of this SN1 reaction. Ignore any inorganic byproducts. CH3CO2Na CH3CO2H Drawing + Br Q Atoms, Bonds and Rings OAC Charges OH ОАс Na ဂ Br Undo Reset Remove Done Drag To Pan +arrow_forwardOrganic Functional Groups entifying positions labeled with Greek letters in acids and derivatives 1/5 ssible, replace an H atom on the a carbon of the molecule in the drawing area with a ce an H atom on the ẞ carbon with a hydroxyl group substituent. ne of the substituents can't be added for any reason, just don't add it. If neither substi er the drawing area. O H OH Oneither substituent can be added. Check D 1 Accessibility ado na witharrow_forward
- Differentiate between electrophilic and nucleophilic groups. Give examples.arrow_forwardAn aldehyde/ketone plus an alcohol gives a hemiacetal, and an excess of alcohol gives an acetal. The reaction is an equilibrium; in aldehydes, it's shifted to the right and in ketones, to the left. Explain.arrow_forwardDraw a Haworth projection or a common cyclic form of this monosaccharide: H- -OH H- OH H- -OH CH₂OHarrow_forward
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