a. Formulation of LP: Given that x 1 is the number of dollars bought and x 2 as the number of francs bought. Here, 3 franc is needed to buy a dollar and 0.25 dollar is needed to buy franc. Suppose it simultaneous transactions are taken place and there will be only one constraint then for maximizing the resultant number of dollars after all transactions. Set the objective function as below, Maximize, z = x 1 + x 2 / 4

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The images I have uploaded are the part 1 to 4 and questions below are continue on the questions uploaded 5. C++ Class Template with Method Stubs #pragma once #include <iostream> #include <string> #include <stdexcept> #include <vector> template <typename T> class HashTable { private: struct Entry { std::string key; T value; bool isOccupied; bool isDeleted; Entry() : key(""), value(), isOccupied(false), isDeleted(false) {} }; Entry* table; size_t capacity; size_t size; double loadFactorThreshold; size_t customHash(const std::string& key) const { size_t hash = 5381; for (char c : key) { hash = ((hash << 5) + hash) + c; } return hash; } size_t probe(const std::string& key, bool forInsert = false) const; void resize(); public: // Constructor HashTable(size_t initialCapacity = 101); // Big…

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Chapter 3.3, Problem 10P

Explanation of Solution

a.

Formulation of LP:

Given that x1 is the number of dollars bought and x2 as the number of francs bought.

Here, 3 franc is needed to buy a dollar and 0.25 dollar is needed to buy franc.

Suppose it simultaneous transactions are taken place and there will be only one constraint then for maximizing the resultant number of dollars after all transactions. Set the objective function as below,

Maximize, z=x1+x2/4

Explanation of Solution

b.

Graphical solution:

The graph for LP is given below,

So, it is clear that there is no optimum solution for LPP of given situation because of unbounded region in graph...

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The images I have uploaded are the part 1 to 4 and questions below are continue on the questions uploaded 5. C++ Class Template with Method Stubs #pragma once #include <iostream> #include <string> #include <stdexcept> #include <vector> template <typename T> class HashTable { private: struct Entry { std::string key; T value; bool isOccupied; bool isDeleted; Entry() : key(""), value(), isOccupied(false), isDeleted(false) {} }; Entry* table; size_t capacity; size_t size; double loadFactorThreshold; size_t customHash(const std::string& key) const { size_t hash = 5381; for (char c : key) { hash = ((hash << 5) + hash) + c; } return hash; } size_t probe(const std::string& key, bool forInsert = false) const; void resize(); public: // Constructor HashTable(size_t initialCapacity = 101); // Big…

this project is NOT for graded(marks) purposes, please help me with the introduction. give me answers for the project. i will include an image explaining everything about the project.

Java Graphics (Bonus In this lab, we'll be practicing what we learned about GUIs, and Mouse events. You will need to implement the following: A GUI with a drawing panel. We can click in this panel, and you will capture those clicks as a Point (see java.awt.Point) in a PointCollection class (you need to build this). The points need to be represented by circles. Below the drawing panel, you will need 5 buttons: O о о ○ An input button to register your mouse to the drawing panel. A show button to paint the points in your collection on the drawing panel. A button to shift all the points to the left by 50 pixels. The x position of the points is not allowed to go below zero. Another button to shift all the points to the right 50 pixels. " The x position of the points cannot go further than the You can implement this GUI in any way you choose. I suggest using the BorderLayout for a panel containing the buttons, and a GridLayout to hold the drawing panel and button panels. Regardless of how…