Campbell Biology in Focus, Books a la Carte Edition; Modified Mastering Biology with Pearson eText - ValuePack Access Card - for Campbell Biology in Focus (2nd Edition)
2nd Edition
ISBN: 9780134433769
Author: Lisa A. Urry, Michael L. Cain, Steven A. Wasserman
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 32.3, Problem 2CC
Summary Introduction
To explain:
The negative feedback in thermoregulation differs from feedback inhibition in an enzyme catalyzed biosynthetic process.
Introduction:
Negative feedback occurs when the end product of an enzyme interferes or decreases the effect of the same enzyme that produced it. The feedback inhibition mechanism is the cellular process in which the end product of an enzyme inhibits the production of the same enzyme that produced it. By this process there is the maintenance of the amount of enzyme required. Both processes help in the regulation of the
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Q: Establish a correspondence between the items indicated by a number and a letter:
features of catalysis:-
Catalyzes the oxidative phosphorylation reaction.
Participates in the reaction of substrate phosphorylation. b)
Forms oxaloacetate in the mitochondria of the cell. d)
Enzyme:-
a) ATP synthase;
b) succinate thiokinase;
c) isocitrate dehydrogenase;
d) malate dehydrogenase;
e) citrate synthase.
How do both activation energy barriers and enzymes help maintain thestructural and metabolic order of life?
Q4Describe each component in glycolysis metabolic pathways involving the degradation of glucose.
Chapter 32 Solutions
Campbell Biology in Focus, Books a la Carte Edition; Modified Mastering Biology with Pearson eText - ValuePack Access Card - for Campbell Biology in Focus (2nd Edition)
Ch. 32.1 - What properties do all types of epithelia share?Ch. 32.1 - Prob. 2CCCh. 32.2 - Prob. 1CCCh. 32.2 - Prob. 2CCCh. 32.2 - Prob. 3CCCh. 32.3 - Is it accurate to define homeostasis as a constant...Ch. 32.3 - Prob. 2CCCh. 32.3 - Prob. 3CCCh. 32.4 - What is the function of the filtration step in...Ch. 32.4 - What advantage does uric acid offer as a...
Ch. 32.4 - WHAT IF? A camel standing in the sun requires much...Ch. 32.5 - Prob. 1CCCh. 32.5 - Prob. 2CCCh. 32.5 - WHAT IF? If blood pressure in the afferent...Ch. 32 - The body tissue that consists largely of material...Ch. 32 - Prob. 2TYUCh. 32 - Which process in the nephron is least selective?...Ch. 32 - Homeostasis typically relies on negative feedback...Ch. 32 - Prob. 5TYUCh. 32 - In which of the following species should natural...Ch. 32 - Prob. 7TYUCh. 32 - Prob. 8TYUCh. 32 - Prob. 9TYUCh. 32 - Prob. 10TYUCh. 32 - FOCUS ON ORGANIZATION In a short essay (100-150...Ch. 32 - SYNTHESIZE YOUR KNOWLEDGE These macaques (Macaca...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Q20arrow_forward← ASSIGNMENT #1: 8% → с X M Inbox (13) - s23.shrilkuma X Untitled document - Goog X ✰ classroom.google.com/w/NTE5NDE3MTQ5MzUx/tc/NTE5NDE3MTQ5MzYO body needs them. • Discuss the major metabolic pathways assigned to your group. Include rate-limiting steps and enzymes, how many ATPs are produced, and which steps. Groups 1,4 and 7- Carbohydrate Groups 2,5 and 8 - Protein Groups 3,6 and 9 - Lipid (Fat) Use Google Doc format Type here to search A E C Paraphrasing Tool - QuillB X The paper should be 2-3 pages in length excluding the required class front page and reference page. b Answered: Discuss the ma x + H 21°C » ENG T 3:27 PM 2023-06-04 X : 2arrow_forwardName two important outcomes of catabolism?arrow_forward
- The following diagram shows the biosynthesis of B12 coenzymes, starting with the vitamin. DMB is dimethylbenzimidazole. (a) What one additional substrate or cofactor is required by enzyme B?(b) Genetic deficiency in animals of enzyme C would result in excessiveurinary excretion of what compound?(c) Some forms of the condition described in (b) can be successfully treatedby injection of rather massive doses of vitamin B12. What kind ofgenetic alteration in the enzyme would be consistent with this result?(d) Genetic deficiency in animals of enzyme B will result in excessive urinaryexcretion of what amino acid?arrow_forwardB) Read the situations below and indicate which of the four methods of enzyme regulation is occurring for each. a) The energy-carrying molecule ATP is made by the enzyme ATP synthase. Muscle cells use a lot of energy and also have higher amounts of the ATP synthase enzyme than many ouier cem types. General mechanism of enzyme regulation: /1 b) Prostaglandins are messenger molecules involved in the inflammatory response, as well as th perception of pain. They are synthesized from polyunsaturated fatty acid substrates by an enzyn called cyclo-oxygenase. "Ibuprofen" is the active ingredient in a variety of anti-inflammatory medications such as Motrin® and Advil®. It reduces pain and swelling by binding to a hydrophobic channel in the active site of cyclo-oxygenase, blocking the polyunsaturated fatty acids from binding to the enzyme, and therefore stopping production of prostaglandins. General mechanism of enzyme regulation: a) In point form, describe the steps by which ATP is produced…arrow_forwardQ14:arrow_forward
- Helparrow_forwardDiscuss with reference to the biological role of glucose and oxygen, the process of aerobic cellular respiration.arrow_forwardDrink # Glucose Concentration in mM 1 2.455 mM 2 0.307 mM 3 3.750 mM 4 1.100 mM 5 1.500 mM From here, each group needs to convert the concentration of their drink from mM of the diluted drink into g/100mL of the undiluted drink. This is where you come in! The students are stuck at this point and really need your help! Main Goal: Convert the experimental glucose concentration (provided in the table below) from mM (millimolar) to g/100 mL. Hints & Tips Take the 1/100 dilution factor into consideration Molarity will open the doors for you to get to grams. Once at M assume 1L of solution. (Hint: this will help you when converting from M to moles) You will also need to calculate the molar mass of glucose which has the formula C6H12O6 There are 5 steps in total Task 1: Write a step-by-step guide with key words for the Chem 2 students on how to do these calculations. You can use diagrams, a table or just type the steps out. Ensure the steps…arrow_forward
- Drink # Glucose Concentration in mM 1 2.455 mM 2 0.307 mM 3 3.750 mM 4 1.100 mM 5 1.500 mM From here, each group needs to convert the concentration of their drink from mM of the diluted drink into g/100mL of the undiluted drink. This is where you come in! The students are stuck at this point and really need your help! Main Goal: Convert the experimental glucose concentration (provided in the table below) from mM (millimolar) to g/100 mL. Hints & Tips Take the 1/100 dilution factor into consideration Molarity will open the doors for you to get to grams. Once at M assume 1L of solution. (Hint: this will help you when converting from M to moles) You will also need to calculate the molar mass of glucose which has the formula C6H12O6 There are 5 steps in total Task 1: Write a step-by-step guide with key words for the Chem 2 students on how to do these calculations. You can use diagrams, a table or just type the steps out. Ensure the steps…arrow_forwardWhy would a larger surface-area-to-volume ratio decrease metabolicefficiency?arrow_forwardReview your understanding of glycolysis, the Krebs cycle, and oxidative phosphorylation by classifying each characteristic below according to its pathway for cellular energy transfer. Enzyme location: Mitochondrial matrix Final product: Pyruvate (under aerobic conditions) Entering substrates: Acetyl coenzyme A and some amino acid intermediates ATP production: 3 ATP from each NADH + H+ and 2 ATP from each FADH2 Entering substrates: glucose and other monosaccharides Final product 2 CO2 for each acetyl coenzyme A Final product: Intermediates used for amino acid/organic molecule synthesis Enzyme location: Cytosol Coenzyme production: 3 NADH + 3H- and 1 FADH2 Coenzyme production: 2 NADH + 2 H (under aerobic conditions) ATP production: 2 per glucose molecule ATP production: 1 GTP formed directly can be converted to ATP Entering substrates Hydrogen ions and molecular oxygen Final product H2O - one molecule for each pair of hydrogen ions Enzyme location: Inner mitochondrial membrane Final…arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Biology (MindTap Course List)BiologyISBN:9781337392938Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. BergPublisher:Cengage Learning
Biology (MindTap Course List)
Biology
ISBN:9781337392938
Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg
Publisher:Cengage Learning