Foundations of Materials Science and Engineering
6th Edition
ISBN: 9781259696558
Author: SMITH
Publisher: MCG
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Question
Chapter 3.15, Problem 71AAP
(a)
To determine
The crystal structure of the element.
(b)
To determine
The lattice constant of the element.
(c)
To determine
The element.
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Chapter 3 Solutions
Foundations of Materials Science and Engineering
Ch. 3.15 - Prob. 1KCPCh. 3.15 - Prob. 2KCPCh. 3.15 - Prob. 3KCPCh. 3.15 - Prob. 4KCPCh. 3.15 - Prob. 5KCPCh. 3.15 - Prob. 6KCPCh. 3.15 - Prob. 7KCPCh. 3.15 - Prob. 8KCPCh. 3.15 - Prob. 9KCPCh. 3.15 - Prob. 10KCP
Ch. 3.15 - Prob. 11KCPCh. 3.15 - Prob. 12KCPCh. 3.15 - Prob. 13KCPCh. 3.15 - Prob. 14KCPCh. 3.15 - Prob. 15KCPCh. 3.15 - Prob. 16KCPCh. 3.15 - Prob. 17KCPCh. 3.15 - Prob. 18KCPCh. 3.15 - Prob. 19KCPCh. 3.15 - Prob. 20KCPCh. 3.15 - Prob. 21KCPCh. 3.15 - Prob. 22KCPCh. 3.15 - Prob. 23KCPCh. 3.15 - Prob. 24AAPCh. 3.15 - Prob. 25AAPCh. 3.15 - Prob. 26AAPCh. 3.15 - Prob. 27AAPCh. 3.15 - Prob. 28AAPCh. 3.15 - Prob. 29AAPCh. 3.15 - Prob. 30AAPCh. 3.15 - Prob. 31AAPCh. 3.15 - Prob. 33AAPCh. 3.15 - A direction vector passes through a unit cube from...Ch. 3.15 - Prob. 36AAPCh. 3.15 - Prob. 37AAPCh. 3.15 - Prob. 38AAPCh. 3.15 - Prob. 41AAPCh. 3.15 - Prob. 42AAPCh. 3.15 - Prob. 43AAPCh. 3.15 - Prob. 44AAPCh. 3.15 - Prob. 45AAPCh. 3.15 - Prob. 46AAPCh. 3.15 - Prob. 47AAPCh. 3.15 - Rodium is FCC and has a lattice constant a of...Ch. 3.15 - Prob. 49AAPCh. 3.15 - Prob. 50AAPCh. 3.15 - Prob. 51AAPCh. 3.15 - Prob. 52AAPCh. 3.15 - Prob. 53AAPCh. 3.15 - Prob. 54AAPCh. 3.15 - Prob. 55AAPCh. 3.15 - Determine the Miller-Bravais direction indices of...Ch. 3.15 - Determine the Miller-Bravais direction indices of...Ch. 3.15 - Prob. 58AAPCh. 3.15 - Prob. 59AAPCh. 3.15 - Prob. 60AAPCh. 3.15 - Prob. 61AAPCh. 3.15 - Prob. 62AAPCh. 3.15 - Prob. 63AAPCh. 3.15 - Prob. 64AAPCh. 3.15 - Prob. 65AAPCh. 3.15 - Prob. 66AAPCh. 3.15 - Prob. 67AAPCh. 3.15 - Prob. 68AAPCh. 3.15 - Prob. 69AAPCh. 3.15 - Prob. 70AAPCh. 3.15 - Prob. 71AAPCh. 3.15 - Prob. 72AAPCh. 3.15 - Prob. 73AAPCh. 3.15 - Prob. 74SEPCh. 3.15 - Prob. 75SEPCh. 3.15 - Prob. 76SEPCh. 3.15 - Assuming that the volume of an HCP metal cell...Ch. 3.15 - Prob. 79SEPCh. 3.15 - Prob. 80SEPCh. 3.15 - Prob. 81SEPCh. 3.15 - Prob. 82SEPCh. 3.15 - Prob. 83SEPCh. 3.15 - Prob. 84SEPCh. 3.15 - Prob. 85SEPCh. 3.15 - Prob. 86SEPCh. 3.15 - Prob. 87SEPCh. 3.15 - Prob. 88SEPCh. 3.15 - Prob. 89SEPCh. 3.15 - Prob. 90SEPCh. 3.15 - Prob. 91SEPCh. 3.15 - Prob. 92SEPCh. 3.15 - Prob. 93SEPCh. 3.15 - Prob. 94SEPCh. 3.15 - Prob. 95SEPCh. 3.15 - Prob. 96SEP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Consider a unit cell with lattice dimensions a, b, and c in the x-, y and z directions. Which of the following sets of Miller indices can represent a crystallographic plane with intercepts of b and (c/4) along the y- and z-axes respectively? (more than one answer is possible for this question. marks will only be awarded for the question if all the correct options are selected (i.e. 'all or nothing' marking scheme). a. b. C. d. (214) (421) (114) e. (412)arrow_forwardA metal having a cubic structure has a density of 2.6 g/cm3, an atomicweight of 87.62 g/mol, and a lattice parameter of 6.0849Unexpected text node: One atom is associated with each lattice point.Determine the crystal structure of the metal.arrow_forwardThe metal niobium has a BCC crystal structure. If the angle of diffraction for the (211) set of planes occurs at 75.99° (first-order reflection) when monochromatic x-radiation having a wavelength of 0.1659 nm is used, compute the following: (a) The interplanar spacing for this set of planes i nm (b) The atomic radius for a Nb atom nmarrow_forward
- Need help on thisarrow_forwardConsider two hypothetical metallic crystal structures A and B. A has an fcc and Ba bcc lattice structure. Both have the same unit cell volume. The Atomic Packing Factor for A is 0.740 and that for B is 0.680. What is the ratio of the fcc to bcc atomic radii? (This question has only one correct answer) O a. 0.92 Ob. 0.44 Ос. 0.63 O d. 0.82 е. 1.21arrow_forward2 Miscellaneous I (a) A certain metal has a BCC crystal structure, a density of 5.96 g/cm³, and an atomic weight of 50.9 g/mol. Calculate the atomic radius. (b) Compute the interplanar spacing for the (111) set of planes for this metal. Are these planes close- packed? (c) Determine the expected diffraction angle for this (111) set of planes when monochromatic radiation of wavelength 0.154 nm is used. (d) What is the metal used in this problem?arrow_forward
- qjly21 For FCC iron, calculate the diffraction angle for the (220) set of planes. The lattice parameter for Fe is 0.3571 nm. Assume that monochromatic radiation having a wavelength of 0.1540 nm is used, and the order of reflection is 1.arrow_forwardFor which set of crystallographic planes will a first-order diffraction peak occur at a diffraction angle of 44.53° for FCC nickel (Ni) when monochromatic radiation having a wavelength of 0.1542 nm is used? The atomic radius for Ni is 0.1246 nm. (arrow_forwardQuestion-2. BCC Tantalum has an atomic radius of 0.1430 nm. Answer the following questions: (a) Calculate the lattice parameter a, b, c of the BCC structure. (b) Determine the interplanar spacings of (110), (200), (211), and (220) planes (c) Determine the expected angles for the first-order reflection of (110), (200), (211), and (220) planes when monochromatic x-ray radiation of a wavelength 0.1542 nm is used.arrow_forward
- Consider an fcc lattice with cube side length 1.2 Å. What are the planar densities of the (110) and (100) planes respectively (in units of 1020 atoms/m?): (This question has only one correct answer) O a. (100) = 2.08, (110) = 0.98 O b. (100) = 1.39, (110) = 0.98 O c. (100) = 1.39, (110) = 1.20 O d. (100) = 0.98, (110) = 1.39arrow_forwarda) Draw the [11 0], [-1 1 0], [ 0-1-1] directions for FCC and prove they are crystallographically equivalent. The family of directions is shown with these brackets. So we can say these directions are part of the family of directions. b) Draw the (1 o 0), (-1 0 0), (0 -1 0), and (00-1) planes for FCC and prove they are crystallographically equivalent. The family of directions is shown with {} these brackets. So we can say these planes are part of the {10 0} family of planes. h me Note that I cannot put a bar as the minus sign.arrow_forwardConsider an fcc lattice with cube side length 2.7 Å. What are the planar densities of the (110) and (100) planes respectively (in units of 1020 atoms/m²): (This question has only one correct answer) a. (100) = 0.19, (110) = 0.27 b. (100) = 0.27, (110) = 0.19 c. (100) = 0.41, (110) = 0.19 d. (100) = 0.27, (110) = 0.24arrow_forward
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