To determine The sketch of p-V diagram. The heat transfer. Explanation The following figure shows the p-V diagram. Figure-(1) Write the expression for gas constant. R = R ¯ M (I) Here, universal gas constant is R ¯ , gas constant is R and molecular weight of Oxygen is M . Write the expression volume. V = p 1 m R T 1 (II) Here, initial pressure is p 1 , volume is V , mass is m and initial temperature is T 1 . Write the expression for the pressure of air. p a i r = p a t m + m p g A (III) Here, pressure of air is p a i r , atmospheric pressure is p a t m , mass of piston is m p , piston area is A and acceleration due to gravity is g . Write the expression for final temperature of the air. T 2 = p 2 V m R (IV) Here, final temperature of the air is T 2 . Write the expression for change in internal energy. Δ U = m ( u 2 − u 1 ) (V) Here, change in internal energy is Δ U , initial specific internal energy is u 1 and the final specific internal energy is u 2 . Write the expression for heat transfer using First law of Thermodynamics for zero work done. Q = Δ U (VI) Here heat transfer during the process is Q . Conclusion: Substitute 8.314 kJ / kmol ⋅ K for R ¯ and 28.97 kg / kmol for M in Equation (I). R = 8.314 kJ / kmol ⋅ K 28.97 kg / kmol = 0.286986 kJ / kg ⋅ K Substitute 3 bar for p 1 , 0.286986 kJ / kg ⋅ K for R , 0.005 kg for m and 600 K for T 1 in Equation (II). V = ( 0.005 kg ) ( 0.286986 kJ / kg ⋅ K ) ( 600 K ) ( 3 bar ) = ( 0.860958 kJ ) ( 1000 Nm 1 kJ ) ( 3 bar ) ( 10 5 N / m 2 1 bar ) = 2.86 × 10 − 3 m 3 Substitute 10 5 Pa for p a t m , 50 kg for m p , 9.8 m / s 2 for g and 9.75 × 10 − 3 m 2 for A in Equation (III)

Appendices to accompany Fundamentals of Engineering Thermodynamics, 8e

8th Edition

ISBN: 9781118957219

Author: Michael J. Moran, Howard N. Shapiro

Publisher: WILEY

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Chapter 3.14, Problem 132P

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The sketch of p-V diagram.

The heat transfer.

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Chapter 3.14, Problem 131P

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Appendices to accompany Fundamentals of Engineering Thermodynamics, 8e

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