To determine The final temperature. Explanation Write the expression for heat energy transfer into the system. Q = Q ˙ Δ t (I) Here, heat transfer rate is Q ˙ , time interval is Δ t . Write the expression for gas constant. R = R ¯ M (II) Here, universal gas constant is R ¯ , gas constant is R , and molecular weight of Oxygen is M . Write the expression for specific heat at constant volume. C V = R k − 1 (III) Here, specific heat at constant volume is C v and specific heat ratio is k . Write the expression for heat transfer. Q = m C V ( T 2 − T 1 ) (IV) Here initial temperature is T 1 , final temperature is T 2 , mass is m , heat transfer is Q Conclusion: Substitute 400 W for Q ˙ , 1 hour for Δ t in Equation (I). Q = ( 400 W ) ( 1 hour ) = ( 400 W ) ( 1 J / s 1 W ) ( 1 hour ) ( 3600 s 1 hour ) = ( 1440000 J ) ( 1 kJ 1000 J ) = 1440 kJ Substitute 8.314 kJ / kmol ⋅ K for R ¯ and 2.016 kg / kmol for M in Equation (II). R = 8

Appendices to accompany Fundamentals of Engineering Thermodynamics, 8e

8th Edition

ISBN: 9781118957219

Author: Michael J. Moran, Howard N. Shapiro

Publisher: WILEY

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Thermodynamic Relations

Thermodynamics is the division of physics that deals with the transfer of any kind of energy, whether it be heat, temperature, or work, from one object to another.

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Chapter 3.14, Problem 123P

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The final temperature.

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Chapter 3.14, Problem 122P

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Appendices to accompany Fundamentals of Engineering Thermodynamics, 8e

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