ORGANIC CHEMISTRY,SOLNS...-ETEXT+BOX
4th Edition
ISBN: 9781119760702
Author: Klein
Publisher: WILEY
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Chapter 3.10, Problem 13LTS
Interpretation Introduction
Interpretation: The Lewis acid and Lewis base must be identified in the reaction between
Concept Introduction: The acidity and basicity are defined in terms of electrons by Lewis. A chemical entity that accepts the pair of electrons is said to be Lewis acid whereas the chemical entity that donates pair of electrons is said to be Lewis base.
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Question 4
Determine the rate order and rate constant for sucrose hydrolysis.
Time (hours)
[C6H12O6]
0
0.501
0.500
0.451
1.00
0.404
1.50
0.363
3.00
0.267
First-order, k = 0.210 hour 1
First-order, k = 0.0912 hour 1
O Second-order, k =
0.590 M1 hour 1
O Zero-order, k = 0.0770 M/hour
O Zero-order, k = 0.4896 M/hour
O Second-order, k = 1.93 M-1-hour 1
10 pts
Determine the rate order and rate constant for sucrose hydrolysis.
Time (hours)
[C6H12O6]
0
0.501
0.500
0.451
1.00
0.404
1.50
0.363
3.00
0.267
Chapter 3 Solutions
ORGANIC CHEMISTRY,SOLNS...-ETEXT+BOX
Ch. 3.2 - Prob. 1LTSCh. 3.2 - Prob. 1PTSCh. 3.3 - Prob. 2LTSCh. 3.3 - Prob. 4PTSCh. 3.3 - Prob. 5ATSCh. 3.3 - Prob. 6ATSCh. 3.3 - Prob. 3LTSCh. 3.3 - Prob. 7PTSCh. 3.4 - Prob. 5LTSCh. 3.4 - Prob. 13PTS
Ch. 3.4 - Prob. 6LTSCh. 3.4 - Prob. 15PTSCh. 3.4 - Prob. 16ATSCh. 3.4 - Prob. 17ATSCh. 3.4 - Prob. 7LTSCh. 3.4 - Prob. 18PTSCh. 3.4 - Prob. 19PTSCh. 3.4 - Prob. 8LTSCh. 3.4 - Prob. 23PTSCh. 3.4 - Prob. 24PTSCh. 3.4 - Prob. 25ATSCh. 3.4 - Prob. 26ATSCh. 3.10 - Prob. 13LTSCh. 3 - Prob. 37PPCh. 3 - Prob. 38PPCh. 3 - Prob. 39PPCh. 3 - Prob. 40PPCh. 3 - Prob. 41PPCh. 3 - Prob. 42PPCh. 3 - Prob. 44PPCh. 3 - Prob. 45PPCh. 3 - Prob. 46PPCh. 3 - Prob. 47PPCh. 3 - Prob. 48PPCh. 3 - Prob. 49PPCh. 3 - Prob. 50PPCh. 3 - Prob. 51PPCh. 3 - Prob. 52PPCh. 3 - Prob. 64IPCh. 3 - Prob. 66IPCh. 3 - Prob. 67IPCh. 3 - Prob. 71IPCh. 3 - Prob. 72IPCh. 3 - Prob. 73IPCh. 3 - Prob. 74IPCh. 3 - Prob. 75IPCh. 3 - Prob. 76IP
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