(a) Explanation Given info: The time is 1 .45 ns . The illuminated area is 32.5 μ m in diameter. the energy contained in the pulse is 2 .95 mJ . The conversion of μ m to m is done as, 1 μ m = 10 − 6 m Therefore, the conversion of 32.5 μ m to m is done as, 32.5 μ m = 32.5 × 10 − 6 m The conversion of ns to s is done as, 1 ns = 10 − 9 s Therefore, the conversion of 1 .45 ns to s is done as, 1 .45 ns = 1.45 × 10 − 9 s The conversion of mJ to J is done as, 1 mJ = 10 − 3 J Therefore, the conversion of 2 .95 mJ to J is done as, 2 .95 mJ = 2.95 × 10 − 3 J Write the expression for the area of the spot. A = π r 2 = π ( d 2 ) 2 Here, d is the diameter. A is the area. Substitute 32.5 × 10 − 6 m for d in the above expression to get A A = π ( d 2 ) 2 = 3 (b) To determine The energy received by the molecule in one pulse from the laser.

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Rutherford's scattering experiment

Rutherford’s scattering experiment is also known as the gold foil experiment. This experiment disproved the plum pudding model of J.J. Thomson. In a gold foil experiment, high-energy alpha particles are made to strike a thin gold foil. The scattered alph…

Question

Chapter 31, Problem 74GP

(a)

To determine

The power per square meter (the irradiance) associated with the beam.

(b)

To determine

The energy received by the molecule in one pulse from the laser.

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Chapter 31, Problem 73GP

Chapter 31, Problem 75GP

Chapter 31 Solutions

EBK PHYSICS

Ch. 31.1 - Prob. 1EYU Ch. 31.2 - Prob. 2EYU Ch. 31.3 - Prob. 3EYU Ch. 31.4 - Prob. 4EYU Ch. 31.5 - Prob. 5EYU Ch. 31.6 - Prob. 6EYU Ch. 31.7 - Prob. 7EYU Ch. 31 - Prob. 1CQ Ch. 31 - Prob. 2CQ Ch. 31 - Prob. 3CQ

Ch. 31 - Prob. 4CQ Ch. 31 - Prob. 5CQ Ch. 31 - Prob. 6CQ Ch. 31 - Prob. 7CQ Ch. 31 - Prob. 8CQ Ch. 31 - Prob. 9CQ Ch. 31 - Prob. 1PCE Ch. 31 - Prob. 2PCE Ch. 31 - Prob. 3PCE Ch. 31 - Prob. 4PCE Ch. 31 - Prob. 5PCE Ch. 31 - Prob. 6PCE Ch. 31 - Prob. 7PCE Ch. 31 - Prob. 8PCE Ch. 31 - Prob. 9PCE Ch. 31 - Prob. 10PCE Ch. 31 - Prob. 11PCE Ch. 31 - Prob. 12PCE Ch. 31 - Prob. 13PCE Ch. 31 - Prob. 14PCE Ch. 31 - Prob. 15PCE Ch. 31 - Prob. 16PCE Ch. 31 - Prob. 17PCE Ch. 31 - Prob. 18PCE Ch. 31 - Prob. 19PCE Ch. 31 - Prob. 20PCE Ch. 31 - Prob. 21PCE Ch. 31 - Prob. 22PCE Ch. 31 - Prob. 23PCE Ch. 31 - Prob. 24PCE Ch. 31 - Prob. 25PCE Ch. 31 - Prob. 26PCE Ch. 31 - Prob. 27PCE Ch. 31 - Prob. 28PCE Ch. 31 - Prob. 29PCE Ch. 31 - Prob. 30PCE Ch. 31 - Prob. 31PCE Ch. 31 - Prob. 32PCE Ch. 31 - Prob. 33PCE Ch. 31 - Prob. 34PCE Ch. 31 - Prob. 35PCE Ch. 31 - Prob. 36PCE Ch. 31 - Prob. 37PCE Ch. 31 - Prob. 38PCE Ch. 31 - Prob. 39PCE Ch. 31 - Prob. 40PCE Ch. 31 - Prob. 41PCE Ch. 31 - Prob. 42PCE Ch. 31 - Prob. 43PCE Ch. 31 - Prob. 44PCE Ch. 31 - Prob. 45PCE Ch. 31 - Prob. 46PCE Ch. 31 - Prob. 47PCE Ch. 31 - Prob. 48PCE Ch. 31 - Prob. 49PCE Ch. 31 - Prob. 50PCE Ch. 31 - Prob. 51PCE Ch. 31 - Prob. 52PCE Ch. 31 - Give the electronic configuration for the ground...Ch. 31 - Prob. 54PCE Ch. 31 - Prob. 55PCE Ch. 31 - Prob. 56PCE Ch. 31 - The configuration of the outer electrons in Ni is...Ch. 31 - Prob. 58PCE Ch. 31 - Prob. 59PCE Ch. 31 - Prob. 60PCE Ch. 31 - Prob. 61PCE Ch. 31 - Prob. 62PCE Ch. 31 - Prob. 63PCE Ch. 31 - Prob. 64PCE Ch. 31 - Prob. 65PCE Ch. 31 - Prob. 66PCE Ch. 31 - Prob. 67PCE Ch. 31 - Prob. 68GP Ch. 31 - Prob. 69GP Ch. 31 - Prob. 70GP Ch. 31 - Prob. 71GP Ch. 31 - Prob. 72GP Ch. 31 - Prob. 73GP Ch. 31 - Prob. 74GP Ch. 31 - Prob. 75GP Ch. 31 - Prob. 76GP Ch. 31 - Prob. 77GP Ch. 31 - Prob. 78GP Ch. 31 - Prob. 79GP Ch. 31 - Prob. 80GP Ch. 31 - Prob. 81GP Ch. 31 - Prob. 82GP Ch. 31 - Prob. 83GP Ch. 31 - Prob. 84PP Ch. 31 - Prob. 85PP Ch. 31 - Prob. 86PP Ch. 31 - Prob. 87PP Ch. 31 - Prob. 88PP Ch. 31 - Prob. 89PP

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