Explanation The ground state energy of electron present in hydrogen atom is − 13.6 eV . Therefore, the minimum energy required to ionize the ground state of the hydrogen atom is 13.6 eV . The conversion of eV to J is done as, 1 eV = 1.6 × 10 − 19 J Therefore, the conversion of 13.6 eV to J is done as, 13.6 eV = 13.6 × 1.6 × 10 − 19 J = 2 .176 × 10 − 18 J Formula to calculate the minimum frequency of photon is, υ = E h Here, E is the energy. h is the Planck’s constant. υ is the frequency. Substitute 6.626 × 10 − 34 J s for h and 2

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Chapter 31, Problem 72GP

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The minimum frequency of a photon required to ionize the ground state of the hydrogen atom.

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Chapter 31, Problem 71GP

Chapter 31, Problem 73GP

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Chapter 31 Solutions

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