Maximum Revenue The total revenue R earned (in thousands of dollars) from manufacturing handheld video games is given by R ( p ) = – 25 p 2 + 1200 p , where p is the price per unit (in dollars). (a) Find the revenues when the prices per unit are $ 20 , $ 25 and $30 . (b) Find the unit price that yields a maximum revenue. What is the maximum revenue? Explain.
Maximum Revenue The total revenue R earned (in thousands of dollars) from manufacturing handheld video games is given by R ( p ) = – 25 p 2 + 1200 p , where p is the price per unit (in dollars). (a) Find the revenues when the prices per unit are $ 20 , $ 25 and $30 . (b) Find the unit price that yields a maximum revenue. What is the maximum revenue? Explain.
Solution Summary: The author calculates the revenues R when the prices per unit are 20,
Maximum Revenue The total revenue
R
earned (in thousands of dollars) from manufacturing handheld video games is given by
R
(
p
)
=
–
25
p
2
+
1200
p
,
where
p
is the price per unit (in dollars).
(a) Find the revenues when the prices per unit are
$
20
,
$
25
and
$30
.
(b) Find the unit price that yields a maximum revenue. What is the maximum revenue? Explain.
how do you calculate the t-value from the table. I'm confused
The weekly total cost function for producing a laser printer is C(x) = 2400 +79x, where x is the number of printers
produced per week.
(a) Form the weekly average cost function for this product.
(b) Find the average cost for the production of 100 printers.
2400 + 79x
X
(b) The average cost for the production of 100 printers is $
per printer.
(Do not include the $ symbol in your answer. Type an integer or a decimal.)
(a) C(x) =
A rectangular window is topped with a semicircle. The height of the rectangular part is 1 more than 3 times its width, w meters. Which function represents the total area, A, of the window in terms of the width?
Chapter 3 Solutions
Bundle: College Algebra, Loose-leaf Version, 10th + WebAssign Printed Access Card for Larson's College Algebra, 10th Edition, Single-Term
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.