A Step-Down Transformer. A transformer connected to a 120 V (rms) ac line is to supply 12.0 V (rms) to a portable electronic device. The load resistance in the secondary is 5.00 Ω. (a) What should the ratio of primary to secondary turns of the transformer be? (b) What rms current must the secondary supply? (c) What average power is delivered to the load? (d) What resistance connected directly across the 120-V line would draw the same power as the transformer? Show that this is equal to 5.00 Ω times the square of the ratio of primary to secondary turns.
A Step-Down Transformer. A transformer connected to a 120 V (rms) ac line is to supply 12.0 V (rms) to a portable electronic device. The load resistance in the secondary is 5.00 Ω. (a) What should the ratio of primary to secondary turns of the transformer be? (b) What rms current must the secondary supply? (c) What average power is delivered to the load? (d) What resistance connected directly across the 120-V line would draw the same power as the transformer? Show that this is equal to 5.00 Ω times the square of the ratio of primary to secondary turns.
A Step-Down Transformer. A transformer connected to a 120 V (rms) ac line is to supply 12.0 V (rms) to a portable electronic device. The load resistance in the secondary is 5.00 Ω. (a) What should the ratio of primary to secondary turns of the transformer be? (b) What rms current must the secondary supply? (c) What average power is delivered to the load? (d) What resistance connected directly across the 120-V line would draw the same power as the transformer? Show that this is equal to 5.00 Ω times the square of the ratio of primary to secondary turns.
No chatgpt pls will upvote Already got wrong chatgpt answer
3.63 • Leaping the River II. A physics professor did daredevil
stunts in his spare time. His last stunt was an attempt to jump across
a river on a motorcycle (Fig. P3.63). The takeoff ramp was inclined at
53.0°, the river was 40.0 m wide, and the far bank was 15.0 m lower
than the top of the ramp. The river itself was 100 m below the ramp.
Ignore air resistance. (a) What should his speed have been at the top of
the ramp to have just made it to the edge of the far bank? (b) If his speed
was only half the value found in part (a), where did he land?
Figure P3.63
53.0°
100 m
40.0 m→
15.0 m
Please solve and answer the question correctly please. Thank you!!
Chapter 31 Solutions
University Physics with Modern Physics, Volume 1 (Chs. 1-20) (14th Edition)
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