Interpretation:
Thermal electrocyclic ring closure of (2Z, 4Z, 6Z)-2,4,6-octatriene yielding products via conrotatory and disrotatory cyclizations.
Concept introduction:
Conrotatory and disrotatory is based on the rotation at each end of the molecule. In conrotatory mode, both atomic orbitals of the end groups turn in the same direction ,such as both atomic orbitals rotating clockwise or counter-clockwise. In disrotatory mode, the atomic orbitals of the end groups turn in opposite directions ,one atomic orbital turns clockwise and the other counter-clockwise. The cis/trans geometry of the final product is directly decided by the difference between conrotation and disrotation.
Whether a particular reaction is conrotatory or disrotatory can be accomplished by examining the molecular orbitals of each molecule and through a set of rules. Only two pieces of information are required to determine conrotation or disrotation using the set of rules: how many electrons are in the pi-system and whether the reaction is induced by heat or by light. This set of rules can also be derived from an analysis of the molecular orbitals for predicting the stereochemistry of electrocyclic reactions.
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Chapter 30 Solutions
Organic Chemistry
- When treated with NaOH, the bromide below gives an alkene by the E2 mechanism, by elimination of the H atom indicated by the arrow: (a) Draw the Newman projection from which elimination takes place. (b) Draw the mechanism. (c) Draw the product with the proper stereochemistry. (d) Assign the proper stereochemical descriptor to the product. (e) Give the rate equationarrow_forwardTreatment of propadiene (an allene) with hydrogen bromide produces 2-bromopropene as the major product. This suggests that the more stable carbocation intermediate is produced by the addition of a proton to Br HBr. H2C=C=CH, H3C CH2 a terminal carbon rather than to the central carbon. Propadiene 2-Bromopropene (a) Draw both carbocation intermediates that can be produced by the addition of a proton to the allene. (b) Explain the relative stabilities of those intermediates. Hint: Draw the orbital picture of the intermediates and consider whether the CH, groups in propadiene are in the same plane.arrow_forwardElimination, stereochemical aspects. Draw the major product that is obtained when (2R,3R)-2-Bromo-3-phenylbutane is treated with sodium ethoxide and explain the stereochemical outcome of the reaction using Newman projections.arrow_forward
- I know that there is a SN1 and E1 reaction that would give different products but I have only seen it with cyclohexane, will it differ with pentane?arrow_forward5. What product would you expect to obtain from the Sy2 reaction of (S)-2-bromo- hexane with sodium acetate, CH3CO2Na? Show the stereochemistry of both product and reactant.arrow_forwardPredict the dehydrohalogenation product(s) that result when the following alkyl halides are heated in alcoholic KOH. When more than one product can be formed, rank them in terms of their predicted stability (1 is most stable isomer, 2 the next most stable isomer, etc...) a) b) HD HD H CH3 ''CI H CH3 Br 'Br KOH EtOH KOH EtOH KOH EtOHarrow_forward
- Draw curved arrows and identify the thermal and photochemical products of the electrocyclic reaction of (2Z,4Z,6E)-octa-2,4,6-triene. Step 2: An electrocyclic reaction will undergo a concerted electron shift to form a cyclic ring. A new sigma bond will be formed between carbons 2 and 7. The product will be neutral. (2ZAZ,6E)-octa-2,4,6-triene Draw the curved arrows to show the mechanism. Select Draw Rings More Erasearrow_forward(2R,3S)-2-Bromo-3-phenylbutane undergoes an E2 elimination when treated with sodium methoxide. Draw all possible Newman projections for the bond relevant for the elimination reaction, and use those Newman projections to explain the stereochemical outcome of the reaction. Draw the final product and provide its IUPAC name.arrow_forwardWhen 3,3-dimethyl-1-butene is treated with HBr alone, the major product is 2-bromo-2,3-dimethylbutane. When the same alkene is treated with HBr and peroxide, the sole product is 1-bromo-3,3-dimethylbutane. Explain these results by referring to the mechanisms.arrow_forward
- When 3-bromo-1-methylcyclohexene undergoes solvolysis in hot ethanol, two productsare formed. Propose a mechanism that accounts for both of these productsarrow_forwardThere are two stereoisomers of 1-tert-butyl-4-chloro-cyclohexane. One of these isomers reacts with sodium ethoxide in an E2 reaction that is 500 times faster than the reaction of the other isomer. Identify the isomer that reacts faster and explain the difference in rate for these two isomers.arrow_forward5) Predict the product and provide a mechanism and stereochemistry of the following reaction. 0 H₂SO4 + CH3OH- 1arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning