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EBK PHYSICS
5th Edition
ISBN: 9780134051796
Author: Walker
Publisher: YUZU
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Question
Chapter 30, Problem 50PCE
(a)
To determine
Whether the change in wavelength of the X-ray photon increase, decrease or remain the same with the increase in scattering angle after it scatters from a free electron.
(b)
To determine
The best explanation for change in wavelength of the X-ray photon to increase after it scatters from a free electron.
Expert Solution & Answer
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Students have asked these similar questions
3.) The graph shows how current I varies with potential difference V across a component X.
904
80-
70-
60-
50-
I/MA
40-
30-
20-
10-
0+
0
0.5
1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0
VIV
Component X and a cell of negligible internal resistance are placed in a circuit.
A variable resistor R is connected in series with component X. The ammeter reads 20mA.
4.0V
4.0V
Component X and the cell are now placed in a potential divider circuit.
(a) Outline why component X is considered non-ohmic. [1]
(b(i)) Determine the resistance of the variable resistor. [3]
(b(ii)) Calculate the power dissipated in the circuit. [1]
(c(i)) State the range of current that the ammeter can measure as the slider S of the potential divider
is moved from Q to P. [1]
(c(ii)) Describe, by reference to your answer for (c)(i), the advantage of the potential divider
arrangement over the arrangement in (b).
1.) Two long parallel current-carrying wires P and Q are separated by 0.10 m. The current in wire P is 5.0 A.
The magnetic force on a length of 0.50 m of wire P due to the current in wire Q is 2.0 × 10-s N.
(a) State and explain the magnitude of the force on a length of 0.50 m of wire Q due to the current in P. [2]
(b) Calculate the current in wire Q. [2]
(c) Another current-carrying wire R is placed parallel to wires P and Q and halfway between them as shown.
wire P
wire R
wire Q
0.05 m
0.05 m
The net magnetic force on wire Q is now zero.
(c.i) State the direction of the current in R, relative to the current in P.[1]
(c.ii) Deduce the current in R. [2]
2.) A 50.0 resistor is connected to a cell of emf 3.00 V. The voltmeter and the ammeter in the circuit are ideal.
V
A
50.00
(a) The current in the ammeter is 59.0 mA. Calculate the internal resistance of the cell.
The circuit is changed by connecting another resistor R in parallel to the 50.0 resistor.
V
A
50.00
R
(b) Explain the effect of this change on R is made of a resistive wire of uniform cross-sectional area 3.1 × 10-8 m²,
resistivity 4.9 × 10-70m and length L. The resistance of R is given by the equation
R = KL
where k is a constant.
(b.i) the reading of the ammeter. [2]
(b.ii) the reading of the voltmeter. [2]
(c) Calculate k. State an appropriate unit for your answer. [3]
[2]
Chapter 30 Solutions
EBK PHYSICS
Ch. 30.1 - Prob. 1EYUCh. 30.2 - Prob. 2EYUCh. 30.3 - Prob. 3EYUCh. 30.4 - Prob. 4EYUCh. 30.5 - Prob. 5EYUCh. 30.6 - Prob. 6EYUCh. 30.7 - Prob. 7EYUCh. 30 - Prob. 1CQCh. 30 - Prob. 2CQCh. 30 - Prob. 3CQ
Ch. 30 - Prob. 4CQCh. 30 - Prob. 5CQCh. 30 - Prob. 6CQCh. 30 - Prob. 7CQCh. 30 - Prob. 8CQCh. 30 - Prob. 9CQCh. 30 - Prob. 10CQCh. 30 - Prob. 1PCECh. 30 - Prob. 2PCECh. 30 - Prob. 3PCECh. 30 - The Sun has a surface temperature of about 5800 K....Ch. 30 - Prob. 5PCECh. 30 - Prob. 6PCECh. 30 - (a) By what factor does the peak frequency change...Ch. 30 - Prob. 8PCECh. 30 - Prob. 9PCECh. 30 - Prob. 10PCECh. 30 - Prob. 11PCECh. 30 - Prob. 12PCECh. 30 - Prob. 13PCECh. 30 - Prob. 14PCECh. 30 - Prob. 15PCECh. 30 - Prob. 16PCECh. 30 - Prob. 17PCECh. 30 - Prob. 18PCECh. 30 - Prob. 19PCECh. 30 - Prob. 20PCECh. 30 - Prob. 21PCECh. 30 - Prob. 22PCECh. 30 - Prob. 23PCECh. 30 - Prob. 24PCECh. 30 - Prob. 25PCECh. 30 - Prob. 26PCECh. 30 - Prob. 27PCECh. 30 - Prob. 28PCECh. 30 - Prob. 29PCECh. 30 - Prob. 30PCECh. 30 - Prob. 31PCECh. 30 - Prob. 32PCECh. 30 - Prob. 33PCECh. 30 - Prob. 34PCECh. 30 - Prob. 35PCECh. 30 - BIO Owl Vision Owls have large, sensitive eyes for...Ch. 30 - Prob. 37PCECh. 30 - Prob. 38PCECh. 30 - Prob. 39PCECh. 30 - Prob. 40PCECh. 30 - Prob. 41PCECh. 30 - Prob. 42PCECh. 30 - Prob. 43PCECh. 30 - Prob. 44PCECh. 30 - Prob. 45PCECh. 30 - Prob. 46PCECh. 30 - Prob. 47PCECh. 30 - Prob. 48PCECh. 30 - Prob. 49PCECh. 30 - Prob. 50PCECh. 30 - Prob. 51PCECh. 30 - Prob. 52PCECh. 30 - Prob. 53PCECh. 30 - Prob. 54PCECh. 30 - Prob. 55PCECh. 30 - Prob. 56PCECh. 30 - Prob. 57PCECh. 30 - Prob. 58PCECh. 30 - Prob. 59PCECh. 30 - Prob. 60PCECh. 30 - Prob. 61PCECh. 30 - Prob. 62PCECh. 30 - Prob. 63PCECh. 30 - Prob. 64PCECh. 30 - Prob. 65PCECh. 30 - Prob. 66PCECh. 30 - Prob. 67PCECh. 30 - Prob. 68PCECh. 30 - Prob. 69PCECh. 30 - Prob. 70PCECh. 30 - Prob. 71PCECh. 30 - Prob. 72PCECh. 30 - Prob. 73PCECh. 30 - Prob. 74PCECh. 30 - Prob. 75PCECh. 30 - Prob. 76PCECh. 30 - Prob. 77PCECh. 30 - Prob. 78PCECh. 30 - Prob. 79PCECh. 30 - Prob. 80GPCh. 30 - Prob. 81GPCh. 30 - Prob. 82GPCh. 30 - Prob. 83GPCh. 30 - Prob. 84GPCh. 30 - Prob. 85GPCh. 30 - Prob. 86GPCh. 30 - Prob. 87GPCh. 30 - Prob. 88GPCh. 30 - Prob. 89GPCh. 30 - Prob. 90GPCh. 30 - Prob. 91GPCh. 30 - Prob. 92GPCh. 30 - Prob. 93GPCh. 30 - Prob. 94GPCh. 30 - Prob. 95GPCh. 30 - Prob. 96GPCh. 30 - Prob. 97PPCh. 30 - Prob. 98PPCh. 30 - Prob. 99PPCh. 30 - Prob. 100PPCh. 30 - Prob. 101PPCh. 30 - Prob. 102PP
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