College Physics
10th Edition
ISBN: 9781285737027
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Chapter 30, Problem 39AP
To determine
The energy released in the fusion reaction.
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A fusion reaction that has been considered as a source of energy is the absorption of a proton by a boron-11 nucleus to produce three alpha particles: 1/1H + 11/5B → 3(4/2He)This reaction is an attractive possibility because boron is easily obtained from the Earth’s crust. A disadvantage is that the protons and boron nuclei must have large kinetic energies for the reaction to take place. This requirement contrasts with the initiation of uranium fission by slow neutrons. (a) How much energy is released in each reaction? (b) Why must the reactant particles have high kinetic energies?
Select the missing product of this nuclear reaction:
235
U + n
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1
90
→ ? + 2 n +
Rb
37
O A. 144
Cs
55
о в. 146
Cs
55
C. 143.
53
O D. 143
Хе
54
Help.
Chapter 30 Solutions
College Physics
Ch. 30.6 - Prob. 30.1QQCh. 30.6 - Prob. 30.2QQCh. 30 - Prob. 1CQCh. 30 - Prob. 2CQCh. 30 - Prob. 3CQCh. 30 - Prob. 4CQCh. 30 - Prob. 5CQCh. 30 - Prob. 6CQCh. 30 - Prob. 7CQCh. 30 - Prob. 8CQ
Ch. 30 - Prob. 9CQCh. 30 - Prob. 10CQCh. 30 - Prob. 11CQCh. 30 - Prob. 12CQCh. 30 - Prob. 1PCh. 30 - Prob. 2PCh. 30 - Prob. 3PCh. 30 - Prob. 4PCh. 30 - Prob. 5PCh. 30 - Prob. 6PCh. 30 - Prob. 7PCh. 30 - Prob. 8PCh. 30 - Prob. 9PCh. 30 - Prob. 10PCh. 30 - Prob. 11PCh. 30 - Prob. 12PCh. 30 - Prob. 13PCh. 30 - Prob. 14PCh. 30 - Prob. 15PCh. 30 - Find the energy released in the fusion reaction...Ch. 30 - Find the energy released in the fusion reaction...Ch. 30 - Prob. 18PCh. 30 - Prob. 19PCh. 30 - Prob. 20PCh. 30 - Prob. 21PCh. 30 - Prob. 22PCh. 30 - Prob. 23PCh. 30 - Prob. 24PCh. 30 - Prob. 25PCh. 30 - Prob. 26PCh. 30 - Prob. 27PCh. 30 - Prob. 28PCh. 30 - Prob. 29PCh. 30 - Prob. 30PCh. 30 - Prob. 31PCh. 30 - Prob. 32PCh. 30 - Prob. 33PCh. 30 - Prob. 34PCh. 30 - Prob. 35PCh. 30 - Prob. 36PCh. 30 - Prob. 37APCh. 30 - Prob. 38APCh. 30 - Prob. 39APCh. 30 - Prob. 40APCh. 30 - Prob. 41APCh. 30 - Prob. 42APCh. 30 - Prob. 43APCh. 30 - Prob. 44APCh. 30 - Prob. 45APCh. 30 - Prob. 46APCh. 30 - Prob. 47APCh. 30 - Prob. 48APCh. 30 - Prob. 49APCh. 30 - Prob. 50AP
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- (a) Write the complete reaction equation for electron capture by 15. (b) Calculate the energy released.arrow_forwardHow many kilograms of water are needed to obtain the 198.8 mol of deuterium, assuming that deuterium is 0.01500% (by number) of natural hydrogen?arrow_forwardAnother set of reactions that result in the fusing ofhydrogen into helium in the Sun and especially in hotter starsis called the carbon cycle. It is12C + 1H → 13N + γ,13N → 13C + e+ + ve,13C + 1H → 14N + γ,14N + 1H → 15O + γ,15O → 15N + e+ + ve,15N + 1H → 12C + 4He.Write down the overall effect of the carbon cycle (as wasdone for the proton-proton cycle in2e− + 41H → 4 He + 2ve + 6γ ). Note the number of protons ( 1H ) required and assume that the positrons ( e+ ) annihilate electrons to form more γ rays.arrow_forward
- Calculate the threshold energy for the following reactings: (i) n+Th²³2 → Th²³1 + 2n (ii)n+Th232 → Th²33 + yarrow_forward(a) Determine the product of the reaction 7 Li + 4He → ? + n. 3 2 chemPad XX že Help Greek 7 4 (b) What is the Q value of the reaction? (The atomic mass of Li is 7.016004 u, the atomic mass of He is 4.002603 u, the atomic mass of a neutron is 1.008665 u, and the atomic mass of the unknown product is 10.012937 u.) 3 2 MeVarrow_forwardComplete the following nuclear reactions. (a) ?+ 14 / 7 N → 1 / 1 H + 17 / 8 O (b) 7 / 3 Li + 1 / 1 H → 4 / 2 He + ?arrow_forward
- i need the answer quicklyarrow_forwardQuestion 1 Calculate the binding energy for 0.064 mole of He (4.00150 amu) in kJ. Question 2 Calculate the binding energy for 0.022 mole of 10Be (10.01019 amu) in kJ. Question 3 Calculate the binding energy for 0.029 mole of 12C (11.99671 amu) in kJ.arrow_forwardDetermine the energy yield of the following fission reaction. Use the given masses below. SU + in → Zr + Te + 3(n) 139 52 92 mzr-94 93.906 u MTe-139 138.935 u 3.0 x 10°m/s. %3D mu-235 = 235.044, mn= 1.009u and c = %3Darrow_forward
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