The maximum kinetic energy of electron ejected from aluminum surface.

Question

Want to see the full answer?

Answer 1

Question

Chapter 30, Problem 33PCE

(a)

To determine

The maximum kinetic energy of electron ejected from aluminum surface.

(b)

To determine

The range of frequency to provide no electrons.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

When developing a night vision night vision equipment, you need to measure the work function for the surface of a metal, so you perform a photoelectric photoelectric effect experiment. You measure the cutoff potential V0 as a function of of the wavelength À of light striking the surface. The results appear in the following table. In your analysis, you use c = 2.998 X 10^8 m/s and e = 1.602 X 10^-19 C, which are values obtained in other experiments. (a) Select a way to represent your results graphicallyso that the data points are close to a straight line. Using this graph, find the slope and the intercept y of the straight line that best fits the data. (b) Use the results from (a) to calculate the Planck constant h (as a test of your data) and the work function ( in and V) of the surface. ( c) What is the longest wavelength of light that will produce photoelectrons from this surface? (d) What wavelength of wavelength of light is required to produce photoelectrons with a kinetic energy…

The most energetic electromagnetic waves in the universe are gamma-rays from gamma ray bursts (GRBs) from collapsing massive stars, observed by satellites with expected energies of 100 TeV (1 TeV = 1012eV). (a) (10) What is the frequency of these energetic gamma ray photons? 1 eV = 1.60 x 10-19 J. (b) What is the wavelength? 2. An astronaut on the International Space Station (ISS) is experimenting with a solid-state green laser communications system from on-orbit at 435 km altitude to the earth’s surface with a wavelength of 532nm and beam divergence (width) of 10-6 radians or 5.73 x 10-15° << 1°. The indices of refraction in free space and the atmosphere are n0 o 1.00000 ..., and na = 1.000293. Although density in the atmosphere varies continuously from the thinness of the upper atmosphere (near r ® 0) to higher density at the surface, refraction can be modeled as a ‘surface’ mid-atmosphere just like classic Snell’s Law calculations. (a) When the ISS is directly…

In developing night-vision equipment, you need to measure the work function for a metal surface, so you perform a photoelectric-effect experiment. You measure the stopping potential V0 as a function of the wavelength l of the light that is incident on the surface. You get the results in the table. In your analysis, you use c = 2.998 x 108m/s and e = 1.602 x 10-19 C, which are values obtained in other experiments. (a) Select a way to plot your results so that the data points fall close to a straight line. Using that plot, find the slope and y-intercept of the best-fit straight line to the data. (b) Use the results of part (a) to calculate Planck’s constant h (as a test of your data) and the work function (in eV) of the surface. (c) What is the longest wavelength of light that will produce photoelectrons from this surface? (d) What wavelength of light is required to produce photoelectrons with kinetic energy 10.0 eV?