Physics, Books a la Carte Plus Mastering Physics with Pearson eText -- Access Card Package (5th Edition)
5th Edition
ISBN: 9780134032610
Author: James S. Walker
Publisher: PEARSON
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Chapter 30, Problem 21PCE
To determine
The work function of silver.
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Light with a frequency of 3.17 × 1015 Hz strikes a metal surface and ejects electrons that have a maximum kinetic energy of 5.7 eV. What is the work function of the metal?
In developing night-vision equipment, you need to measure the work function for a metal surface, so you perform a photoelectric-effect experiment. You measure the stopping potential V0 as a function of the wavelength l of the light that is incident on the surface. You get the results in the table.
In your analysis, you use c = 2.998 x 108m/s and e = 1.602 x 10-19 C, which are values obtained in other experiments. (a) Select a way to plot your results so that the data points fall close to a straight line. Using that plot, find the slope and y-intercept of the best-fit straight line to the data. (b) Use the results of part (a) to calculate Planck’s constant h (as a test of your data) and the work function (in eV) of the surface. (c) What is the longest wavelength of light that will produce photoelectrons from this surface? (d) What wavelength of light is required to produce photoelectrons with kinetic energy 10.0 eV?
Hi please help:
Light of frequency 9.95×10^14Hz ejects electrons from the surface of silver.
If the maximum kinetic energy of the ejected electrons is 1.80×10−20 J , what is the work function of silver?
Chapter 30 Solutions
Physics, Books a la Carte Plus Mastering Physics with Pearson eText -- Access Card Package (5th Edition)
Ch. 30.1 - Prob. 1EYUCh. 30.2 - Prob. 2EYUCh. 30.3 - Prob. 3EYUCh. 30.4 - Prob. 4EYUCh. 30.5 - Prob. 5EYUCh. 30.6 - Prob. 6EYUCh. 30.7 - Prob. 7EYUCh. 30 - Prob. 1CQCh. 30 - Prob. 2CQCh. 30 - Prob. 3CQ
Ch. 30 - Prob. 4CQCh. 30 - Prob. 5CQCh. 30 - Prob. 6CQCh. 30 - Prob. 7CQCh. 30 - Prob. 8CQCh. 30 - Prob. 9CQCh. 30 - Prob. 10CQCh. 30 - Prob. 1PCECh. 30 - Prob. 2PCECh. 30 - Prob. 3PCECh. 30 - The Sun has a surface temperature of about 5800 K....Ch. 30 - Prob. 5PCECh. 30 - Prob. 6PCECh. 30 - (a) By what factor does the peak frequency change...Ch. 30 - Prob. 8PCECh. 30 - Prob. 9PCECh. 30 - Prob. 10PCECh. 30 - Prob. 11PCECh. 30 - Prob. 12PCECh. 30 - Prob. 13PCECh. 30 - Prob. 14PCECh. 30 - Prob. 15PCECh. 30 - Prob. 16PCECh. 30 - Prob. 17PCECh. 30 - Prob. 18PCECh. 30 - Prob. 19PCECh. 30 - Prob. 20PCECh. 30 - Prob. 21PCECh. 30 - Prob. 22PCECh. 30 - Prob. 23PCECh. 30 - Prob. 24PCECh. 30 - Prob. 25PCECh. 30 - Prob. 26PCECh. 30 - Prob. 27PCECh. 30 - Prob. 28PCECh. 30 - Prob. 29PCECh. 30 - Prob. 30PCECh. 30 - Prob. 31PCECh. 30 - Prob. 32PCECh. 30 - Prob. 33PCECh. 30 - Prob. 34PCECh. 30 - Prob. 35PCECh. 30 - BIO Owl Vision Owls have large, sensitive eyes for...Ch. 30 - Prob. 37PCECh. 30 - Prob. 38PCECh. 30 - Prob. 39PCECh. 30 - Prob. 40PCECh. 30 - Prob. 41PCECh. 30 - Prob. 42PCECh. 30 - Prob. 43PCECh. 30 - Prob. 44PCECh. 30 - Prob. 45PCECh. 30 - Prob. 46PCECh. 30 - Prob. 47PCECh. 30 - Prob. 48PCECh. 30 - Prob. 49PCECh. 30 - Prob. 50PCECh. 30 - Prob. 51PCECh. 30 - Prob. 52PCECh. 30 - Prob. 53PCECh. 30 - Prob. 54PCECh. 30 - Prob. 55PCECh. 30 - Prob. 56PCECh. 30 - Prob. 57PCECh. 30 - Prob. 58PCECh. 30 - Prob. 59PCECh. 30 - Prob. 60PCECh. 30 - Prob. 61PCECh. 30 - Prob. 62PCECh. 30 - Prob. 63PCECh. 30 - Prob. 64PCECh. 30 - Prob. 65PCECh. 30 - Prob. 66PCECh. 30 - Prob. 67PCECh. 30 - Prob. 68PCECh. 30 - Prob. 69PCECh. 30 - Prob. 70PCECh. 30 - Prob. 71PCECh. 30 - Prob. 72PCECh. 30 - Prob. 73PCECh. 30 - Prob. 74PCECh. 30 - Prob. 75PCECh. 30 - Prob. 76PCECh. 30 - Prob. 77PCECh. 30 - Prob. 78PCECh. 30 - Prob. 79PCECh. 30 - Prob. 80GPCh. 30 - Prob. 81GPCh. 30 - Prob. 82GPCh. 30 - Prob. 83GPCh. 30 - Prob. 84GPCh. 30 - Prob. 85GPCh. 30 - Prob. 86GPCh. 30 - Prob. 87GPCh. 30 - Prob. 88GPCh. 30 - Prob. 89GPCh. 30 - Prob. 90GPCh. 30 - Prob. 91GPCh. 30 - Prob. 92GPCh. 30 - Prob. 93GPCh. 30 - Prob. 94GPCh. 30 - Prob. 95GPCh. 30 - Prob. 96GPCh. 30 - Prob. 97PPCh. 30 - Prob. 98PPCh. 30 - Prob. 99PPCh. 30 - Prob. 100PPCh. 30 - Prob. 101PPCh. 30 - Prob. 102PP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- A 900-W microwave generator in an oven generates energy quanta of frequency 2560 MHz. (a) How many energy quanta does it emit per second? (b) How many energy quanta must be absorbed by a pasta dish placed in the radiation cavity to increase its temperature by 45.0 K? Assume that the dish has a mass of 0.5 kg and that its specific heat is 0.9 kcal/kg • K. (c) Assume that all energy quanta emitted by the generator are absorbed by the pasta dish. How long must we wait until the dish in (b) is ready?arrow_forwardWhen developing a night vision night vision equipment, you need to measure the work function for the surface of a metal, so you perform a photoelectric photoelectric effect experiment. You measure the cutoff potential V0 as a function of of the wavelength À of light striking the surface. The results appear in the following table. In your analysis, you use c = 2.998 X 10^8 m/s and e = 1.602 X 10^-19 C, which are values obtained in other experiments. (a) Select a way to represent your results graphicallyso that the data points are close to a straight line. Using this graph, find the slope and the intercept y of the straight line that best fits the data. (b) Use the results from (a) to calculate the Planck constant h (as a test of your data) and the work function ( in and V) of the surface. ( c) What is the longest wavelength of light that will produce photoelectrons from this surface? (d) What wavelength of wavelength of light is required to produce photoelectrons with a kinetic energy…arrow_forwardLight of frequency 9.6 x 1014 Hz is incident on a metal surface. The stopping potential for this metal at this frequency is 2.2 V. How much work is required for an electron to escape the surface of this metal? O 3.5 × 10-19 J O 1.6 × 10-19 J O 2.2 × 10:1⁹ J O 3.2 × 10-19 J O 2.8 x 10-19 Jarrow_forward
- Can an electron in a hydrogen atom have a speed of 3.60 × 105 m/s? If so, what are its energy and the radius of its orbit? What about a speed of 3.65 × 105 m/s?arrow_forwardA strange metallic rock is found and is being tested. Suppose that light with a frequency of 9.40 ✕ 1014 Hz is incident upon the rock and a stopping potential of 1.50 V is needed to reduce the electron current to zero in a photoelectric experiment.What is the minimum frequency of light for which electrons are still ejected from the surface of this material? Hzarrow_forwardLight of frequency 7.21×1014 Hz is incident on a metal surface. Electrons with a maximum speed of 6.0 × 105 m/s are ejected from the surface. What is the threshold frequency for photoemission of electrons?arrow_forward
- In the photoelectric effect, electrons are ejected from a metal surface when light strikes it. A certain minimum energy, Emin, is required to eject an electron. Any energy absorbed beyond that minimum gives kinetic energy to the ejected electron. It is found that when light at a wavelength of 540 nm falls on a cesium surface, an electron is ejected with a kinetic energy of 2.60 x 10-20 J. When the wavelength is 400 nm, the kinetic energy is 1.54 x 10-19 J. Calculate Emin for cesium in joules Calculate the longest wavelength, in nanometers, that will eject electrons from cesium.arrow_forwardLight of frequency 7.21 x 1014 Hz is incident on a metal surface. Electrons with a maximum speed of 6.0 x 105 m/s are ejected from the surface. What is the threshold frequency for photoemission of electrons?arrow_forwardDuring a certain experiment, the de Broglie wavelength of an electron is 460 nm = 4.6 ✕ 10−7 m, which is the same as the wavelength of blue light. How fast (in m/s) is the electron moving?arrow_forward
- 2. Light of frequency 7.40 × 10¹4 Hz ejects electrons from surface (A) with a maximum kinetic energy that is -19 1.20 x 107 J greater than the maximum kinetic energy of electrons ejected from surface B. Calculate the difference in work function for these two surfaces. J ×60 S ssf60 ssfo SS €60 ssf603 ssf60 ssf F60 ss f60 ssf60 tengarrow_forwardWhat is the velocity of an electron emitted by lithium (work function = 2.90 e.v.) if light with a frequency of 4.77x1015 s-1 is absorbed?arrow_forwardWhen light with a wavelength of 219 nm is incident on a certain metal surface, electrons are ejected with a maximum kinetic energy of 3.32×10−193.32×10−19 J. Determine the wavelength of light that should be used to triple the maximum kinetic energy of the electrons ejected from this surface.arrow_forward
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