Organic Chemistry
Organic Chemistry
5th Edition
ISBN: 9780078021558
Author: Janice Gorzynski Smith Dr.
Publisher: McGraw-Hill Education
Question
Book Icon
Chapter 30, Problem 30.37P
Interpretation Introduction

(a)

Interpretation: An explanation for the differences observed in the Tg, and Tm values for the given pair of polymers is to be stated.

Concept introduction: The glass transition temperature and the melt transition temperature are often used to characterize the behavior of a polymer on heating. They are denoted by Tg, and Tm respectively. Tg is the temperature at which hardness of an amorphous polymer decreases to become soft (not melted). Tm is the temperature at which crystalline regions of polymer decreases to become amorphous.

Expert Solution
Check Mark

Answer to Problem 30.37P

The given Tg, and Tm values of polyester A is lesser than that of PET. It indicates the presence of more ordered crystalline regions and more disordered amorphous regions in PET than in polyester A.

Explanation of Solution

The given pair of polymers is,

Organic Chemistry, Chapter 30, Problem 30.37P , additional homework tip  1

Figure 1

The above polymer chains have both crystalline regions and amorphous regions. The ordered crystalline regions are called crystallites. Crystallites are the sections where polymer chain is bind together by intermolecular interactions. On the contrary amorphous regions are sections where polymer chains are randomly arranged. These sections are held together by weak intermolecular interactions.

A polymer containing high crystallites area possesses high Tm value and a polymer chain containing high amorphous area possesses high Tg value.

The given Tg, and Tm values of polyester A is lesser than that of PET. Thus, it indicates the presence of more ordered crystalline regions and more disordered amorphous regions in PET than in polyester A.

Conclusion

The given Tg, and Tm values of polyester A is lesser than that of PET. It indicates the presence of more ordered crystalline regions and more disordered amorphous regions in PET than in polyester A.

Interpretation Introduction

(b)

Interpretation: An explanation for the differences observed in the Tg, and Tm values for the given pair of polymers is to be stated.

Concept introduction: The glass transition temperature and the melt transition temperature are often used to characterize the behavior of a polymer on heating. They are denoted by Tg, and Tm respectively. Tg is the temperature at which hardness of an amorphous polymer decreases to become soft (not melted). Tm is the temperature at which crystalline regions of polymer decreases to become amorphous.

Expert Solution
Check Mark

Answer to Problem 30.37P

The given Tg, and Tm values of polyester A is lesser than that of nylon 6,6. It indicates the presence of more ordered crystalline regions and more disordered amorphous regions in nylon 6,6 than in polyester A.

Explanation of Solution

The given pair of polymers is,

Organic Chemistry, Chapter 30, Problem 30.37P , additional homework tip  2

Figure 2

The above polymer chains have both crystalline regions and amorphous regions. The ordered crystalline regions are called crystallites. Crystallites are the sections where polymer chain is bind together by intermolecular interactions. On the contrary amorphous regions are sections where polymer chains are randomly arranged. These sections are held together by weak intermolecular interactions.

A polymer containing high crystallites area possesses high Tm value and a polymer chain containing high amorphous area possesses high Tg value.

The given Tg, and Tm values of polyester A is lesser than that of nylon 6,6. Thus, it indicates the presence of more ordered crystalline regions and more disordered amorphous regions in nylon 6,6 than in polyester A.

Conclusion

The given Tg, and Tm values of polyester A is lesser than that of nylon 6,6. It indicates the presence of more ordered crystalline regions and more disordered amorphous regions in nylon 6,6 than in polyester A.

Interpretation Introduction

(c)

Interpretation: The comparison between the Tm values for Kevlar and the Tm value for nylon 6,6 is to be stated.

Concept introduction: The glass transition temperature and the melt transition temperature are often used to characterize the behavior of a polymer on heating. They are denoted by Tg, and Tm respectively. Tg is the temperature at which hardness of polymer decrease to become soft (not melted). Tm is the temperature at which crystalline regions of polymer decreases to become amorphous.

Expert Solution
Check Mark

Answer to Problem 30.37P

The Tm value for Kevlar is higher than nylon 6,6.

Explanation of Solution

Kevlar is a polyamide, synthesized by 1,4-diaminobenzene and terephthalic acid. It is light in weight but possesses high strength. It is due to the presence of aromatic rings as polymer backbone. This polymer backbone is much more symmetrical, and ordered than nylon 6,6. It indicates the presence of more crystalline region in Kevlar than nylon 6,6.

Organic Chemistry, Chapter 30, Problem 30.37P , additional homework tip  3

Figure 3

Since more ordered polymers have more Tm values, it is expected that the Tm value for Kevlar is higher than that of nylon 6,6.

Conclusion

The Tm value for Kevlar is higher than nylon 6,6.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
julietteyep@gmail.com X YSCU Grades for Juliette L Turner: Orc X 199 A ALEKS - Juliette Turner - Modul X A ALEKS - Juliette Turner - Modul x G butane newman projection - Gox + www-awa.aleks.com/alekscgi/x/Isl.exe/10_u-IgNslkr7j8P3jH-IBxzaplnN4HsoQggFsejpgqKoyrQrB2dKVAN-BcZvcye0LYa6eXZ8d4vVr8Nc1GZqko5mtw-d1MkNcNzzwZsLf2Tu9_V817y?10Bw7QYjlb il Scribbr citation APA SCU email Student Portal | Main Ryker-Learning WCU-PHARM D MySCU YSCU Canvas- SCU Module 4: Homework (Ch 9-10) Question 28 of 30 (1 point) | Question Attempt: 1 of Unlimited H₂SO heat OH The mechanism of this reaction involves two carbocation intermediates, A and B. Part 1 of 2 KHSO 4 rearrangement A heat B H₂O 2 OH Draw the structure of A. Check Search #t m Save For Later Juliet Submit Assignm 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Access
The electrons flow from the electron-rich atoms of the nucleophile to the electrons poor atoms of the alkyl halide. Identify the electron rich in the nucleophile. Enter the element symbol only, do not include any changes.
Hello, I am doing a court case analysis in my Analytical Chemistry course. The case is about a dog napping and my role is prosecution of the defendant. I am tasked in the Area of Expertise in Neutron Activation and Isotopic Analysis.   Attached is the following  case study reading of my area of expertise! The landscaping stone was not particularly distinctive in its decoration but matched both the color and pattern of the Fluential’s landscaping stone as well as the stone in the back of the recovered vehicle. Further analysis of the stone was done using a technique called instrumental neutron activation analysis. (Proceed to Neutron Activation data)     Photo Notes: Landscaping stone recovered in vehicle. Stone at Fluential’s home is similar inappearance.   Finally, the white paint on the brick was analyzed using stable isotope analysis. The brick recovered at the scene had smeared white paint on it. A couple of pieces of brick in the back of the car had white paint on them. They…

Chapter 30 Solutions

Organic Chemistry

Ch. 30 - Prob. 30.11PCh. 30 - Problem 30.12 What polymer is formed by anionic...Ch. 30 - Prob. 30.13PCh. 30 - Prob. 30.14PCh. 30 - Problem 30.15 What polyamide is formed from each...Ch. 30 - Prob. 30.16PCh. 30 - Prob. 30.17PCh. 30 - Prob. 30.18PCh. 30 - Prob. 30.19PCh. 30 - Prob. 30.20PCh. 30 - Prob. 30.21PCh. 30 - Prob. 30.22PCh. 30 - Prob. 30.23PCh. 30 - Prob. 30.24PCh. 30 - Prob. 30.25PCh. 30 - 30.26 Draw the structure of the polymer formed by...Ch. 30 - Prob. 30.27PCh. 30 - Prob. 30.28PCh. 30 - Prob. 30.29PCh. 30 - 30.30 Draw each polymer in Problem 30.29 using the...Ch. 30 - Prob. 30.31PCh. 30 - Prob. 30.32PCh. 30 - Prob. 30.33PCh. 30 - Prob. 30.34PCh. 30 - Prob. 30.35PCh. 30 - Prob. 30.36PCh. 30 - Prob. 30.37PCh. 30 - Prob. 30.38PCh. 30 - 30.39 Draw a stepwise mechanism for the...Ch. 30 - 30.40 Cationic polymerization of 3-phenylpropene ...Ch. 30 - Prob. 30.41PCh. 30 - Prob. 30.42PCh. 30 - 30.43 Although styrene undergoes both cationic and...Ch. 30 - 30.44 Rank the following compounds in order of...Ch. 30 - Prob. 30.45PCh. 30 - Prob. 30.46PCh. 30 - 30.47 Draw a stepwise mechanism for the following...Ch. 30 - 30.48 Draw a stepwise mechanism for the reaction...Ch. 30 - 30.49 Draw the products of each reaction. a. e....Ch. 30 - Prob. 30.50PCh. 30 - Prob. 30.51PCh. 30 - 30.52 (a) Explain why poly (vinyl alcohol) cannot...Ch. 30 - 30.53 Devise a synthesis of terephthalic acid and...Ch. 30 - Prob. 30.54PCh. 30 - Prob. 30.55PCh. 30 - 30.56 Compound A is a novel poly (ester amide)...Ch. 30 - 30.57 Researchers at Rutgers University have...Ch. 30 - 30.58 Melmac, a thermosetting polymer formed from...Ch. 30 - 30.59 Although chain branching in radical...Ch. 30 - Prob. 30.60P
Knowledge Booster
Background pattern image
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Organic Chemistry
Chemistry
ISBN:9781305080485
Author:John E. McMurry
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning
Text book image
Macroscale and Microscale Organic Experiments
Chemistry
ISBN:9781305577190
Author:Kenneth L. Williamson, Katherine M. Masters
Publisher:Brooks Cole