Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)
4th Edition
ISBN: 9780134110684
Author: Randall D. Knight (Professor Emeritus)
Publisher: PEARSON
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Textbook Question
Chapter 30, Problem 2CQ
You want to insert a loop of copper wire between the two permanent magnets in FIGURE Q30.2. Is there an attractive magnetic force that tends to pull the loop in, like a magnet pulls on a paper clip? Or do you need to push the loop in against a repulsive force? Explain.
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Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)
Ch. 30 - Prob. 1CQCh. 30 - You want to insert a loop of copper wire between...Ch. 30 - A vertical, rectangular loop of copper wire is...Ch. 30 - Does the loop of wire in FIGURE Q30.4 have a...Ch. 30 - s5. The two loops of wire in FIGURE Q30.5 are...Ch. 30 - FIGURE Q30.6 shows a bar magnet being pushed...Ch. 30 - A bar magnet is pushed toward a loop of wire as...Ch. 30 - FIGURE Q30.8 shows a bar magnet. a coil of wire,...Ch. 30 - Prob. 9CQCh. 30 - An inductor with a 2.0 A current stores energy. At...
Ch. 30 - Prob. 11CQCh. 30 - Prob. 12CQCh. 30 - Rank in order, from largest to smallest, the three...Ch. 30 - For the circuit of FIGURE Q30.14: a. What is the...Ch. 30 - The earth’s magnetic field strength is 5.0105T ....Ch. 30 - A potential difference of 0.050 V is developed...Ch. 30 - A 10 -cm-long wire is pulled along a U-shaped...Ch. 30 - What is the magnetic flux through the loop shown...Ch. 30 - FIGURE EX30.5 shows a 10cm10cm square bent at a 90...Ch. 30 - Prob. 6EAPCh. 30 - Prob. 7EAPCh. 30 - FIGURE EX30.8 shows a 2.0 -cm-diameter solenoid...Ch. 30 - Prob. 9EAPCh. 30 - 10. A solenoid is wound as shown in FIGURE...Ch. 30 - 11. The metal equilateral triangle in FIGURE...Ch. 30 - The current in the solenoid of FIGURE EX3O.12 is...Ch. 30 - The loop in FIGURE EX30.13 is being pushed into...Ch. 30 - FIGURE EX30.14 shows a 10-cm-diameter loop in...Ch. 30 - Prob. 15EAPCh. 30 - 16. A -turn coil of wire cm in diameter is in a...Ch. 30 - A 5.0 -cm-diameter coil has 20 turns and a...Ch. 30 - FIGURE EX30.18 shows the current as a function of...Ch. 30 - The magnetic field in FIGURE EX30.19 is decreasing...Ch. 30 - The magnetic field inside a -cm-diameter solenoid...Ch. 30 - Scientists studying an anomalous magnetic field...Ch. 30 - Prob. 22EAPCh. 30 - Prob. 23EAPCh. 30 - Prob. 24EAPCh. 30 - Prob. 25EAPCh. 30 - Prob. 26EAPCh. 30 - How much energy is stored in a -cm-diameter,...Ch. 30 - MRI (magnetic resonance imaging) is a medical...Ch. 30 - Prob. 29EAPCh. 30 - Prob. 30EAPCh. 30 - Prob. 31EAPCh. 30 - Prob. 32EAPCh. 30 - Prob. 33EAPCh. 30 - Prob. 34EAPCh. 30 - At t=0 s, the current in the circuit in FIGURE...Ch. 30 - The switch in FIGURE EX3O.36 has been open for a...Ch. 30 - Prob. 37EAPCh. 30 - Prob. 38EAPCh. 30 - Prob. 39EAPCh. 30 - Prob. 40EAPCh. 30 - A 10cm10cm square loop lies in the xy-plane. The...Ch. 30 - A spherical balloon with a volume of L is in a mT...Ch. 30 - Prob. 43EAPCh. 30 - Prob. 44EAPCh. 30 - Prob. 45EAPCh. 30 - FIGURE P30.46 shows a 4.0-cm-diameter loop with...Ch. 30 - Prob. 47EAPCh. 30 - Prob. 48EAPCh. 30 - Prob. 49EAPCh. 30 - Prob. 50EAPCh. 30 - Prob. 51EAPCh. 30 - Prob. 52EAPCh. 30 - Prob. 53EAPCh. 30 - Prob. 54EAPCh. 30 - Prob. 55EAPCh. 30 - Your camping buddy has an idea for a light to go...Ch. 30 - 57. The -wide, zero-resistance slide wire shown...Ch. 30 - ]58. You’ve decided to make the magnetic...Ch. 30 - FIGURE P30.59 shows a U-shaped conducting rail...Ch. 30 - Prob. 60EAPCh. 30 - Prob. 61EAPCh. 30 - Prob. 62EAPCh. 30 - Equation 30.26 is an expression for the induced...Ch. 30 - Prob. 64EAPCh. 30 - One possible concern with MRI (see Exercise 28) is...Ch. 30 - FIGURE P30.66 shows the current through a 10mH...Ch. 30 - Prob. 67EAPCh. 30 - Prob. 68EAPCh. 30 - Prob. 69EAPCh. 30 - Prob. 70EAPCh. 30 - An LC circuit is built with a inductor and an...Ch. 30 - Prob. 72EAPCh. 30 - For your final exam in electronics, you’re asked...Ch. 30 - The inductor in FIGURE P30.74 is a -cm-long, -cm-...Ch. 30 - The capacitor in FIGURE P30.75 is initially...Ch. 30 - The switch in FIGURE P30.76 has been open for a...Ch. 30 - 77. The switch in FIGURE P30.77 has been open for...Ch. 30 - Prob. 78EAPCh. 30 - Prob. 79EAPCh. 30 - Prob. 80EAPCh. 30 - In recent years it has been possible to buy a 1.0F...Ch. 30 - Prob. 82EAPCh. 30 - Prob. 83EAPCh. 30 - Prob. 84EAPCh. 30 - A 2.0 -cm-diameter solenoid is wrapped with 1000...Ch. 30 - High-frequency signals are often transmitted along...
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- Two long, straight wires carry the same current as shown in Figure P30.22. One wire is parallel to the z axis and the other wire is parallel to the x axis as shown. Find an expression for the magnetic field at the origin.arrow_forwardA toroid with an inner radius of 20 cm and an outer radius of 22 cm is tightly wound with one layer of wire that has a diameter of 0.25 mm. (a) How many turns are there on the toroid? (b) If the current through the toroid windings is 2.0 A, what is the strength of the magnetic field at the center of the toroid?arrow_forwardA wire carrying a current I is bent into the shape of an exponential spiral, r = e, from = 0 to = 2 as suggested in Figure P29.47. To complete a loop, the ends of the spiral are connected by a straight wire along the x axis. (a) The angle between a radial line and its tangent line at any point on a curve r = f() is related to the function by tan=rdr/d Use this fact to show that = /4. (b) Find the magnetic field at the origin. Figure P29.47arrow_forward
- A uniform magnetic field of magnitude is directed parallel to the z-axis. A proton enters the field with a velocity v=(4j+3k)106m/s and travels in a helical path with a radius of 5.0 cm. (a) What is the value of B? (b) What is the time required for one trip around the helix? (c) Where is the proton 5.0107s after entering the field?arrow_forwardA circular coil 15.0 cm in radius and composed of 145 tightly wound turns carries a current of 2.50 A in the counterclockwise direction, where the plane of the coil makes an angle of 15.0 with the y axis (Fig. P30.73). The coil is free to rotate about the z axis and is placed in a region with a uniform magnetic field given by B=1.35jT. a. What is the magnitude of the magnetic torque on the coil? b. In what direction will the coil rotate? FIGURE P30.73arrow_forwardWhy is the following situation impossible? Figure P28.46 shows an experimental technique for altering the direction of travel for a charged particle. A particle of charge q = 1.00 C and mass m = 2.00 1015 kg enters the bottom of the region of uniform magnetic field at speed = 2.00 105 m/s, with a velocity vector perpendicular to the field lines. The magnetic force on the particle causes its direction of travel to change so that it leaves the region of the magnetic field at the top traveling at an angle from its original direction. The magnetic field has magnitude B = 0.400 T and is directed out of the page. The length h of the magnetic field region is 0.110 m. An experimenter performs the technique and measures the angle at which the particles exit the top of the field. She finds that the angles of deviation are exactly as predicted. Figure P28.46arrow_forward
- (a) A physicist performing a sensitive measurement wants to limit the magnetic force on a moving charge in her equipment to less than 1.001012N. What is the greatest the charge can be if it moves at a maximum speed of 30.0 m/s in Earth's field? (b) Discuss whether it would be difficult to limit the charge to less than the value found in (a) by comparing it with typical static electricity' and noting that static is often absent,arrow_forwardDetermine the magnetic field (in terms of I, a, and d) at the origin due to the current loop in Figure P29.9. The loop extends to infinity above the figure. Figure P29.9arrow_forward(a) A physicist performing a sensitive measurement wants to limit the magnetic force on a moving charge in her equipment to less than 1.001012N. What is the greatest the charge can be if it moves at a maximum speed of 30.0 m/s in the Earth’s field? (b) Discuss whether it would be difficult to limit the charge to less than the value found in (a) by competing it with typical static electricity and noting that static is often absent.arrow_forward
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Magnets and Magnetic Fields; Author: Professor Dave explains;https://www.youtube.com/watch?v=IgtIdttfGVw;License: Standard YouTube License, CC-BY