MASTERPHYS:KNIGHT'S PHYSICS ACCESS+WKB
4th Edition
ISBN: 9780135245033
Author: Knight
Publisher: PEARSON
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Chapter 30, Problem 1EAP
The earth’s magnetic field strength is
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An astronaut is connected to her spacecraft by a 25.0-m-long tether cord as she and the spacecraft orbit the Earth in a circular path at a speed of 7.80 x 103 m/s. At one instant, the emf between the ends of a wire embedded in the cord is measured to be 1.17 V. Assume the long dimension of the cord is perpendicular to the Earth’s magnetic field at that instant. Assume also the tether’s center of mass moves with a velocity perpendicular to the Earth’s magnetic field. (a) What is the magnitude of the Earth’s field at this location? (b) Does the emf change as the system moves from one location to another? Explain. (c) Provide two conditions under which the emf would be zero even though the magnetic field is not zero.
An automobile with a radio antenna 1.0 m long generates an emf, V1, since it is traveling at 100.0 km/h in a location where the Earth’s horizontal magnetic field is 5.5×10−5T. At some time, the radio antenna halves in length and the car begins traveling at a quarter of the original speed. What is the ratio of the new emf
0.75 V1
0.125 V1
1 V1
0.5 V1
b. It has been suggested that birds might use the EMF induced between their
wing tips by the earth's magnetic field as a means of helping them navigate
during migration. What EMF would be induced for a Canada goose with a
wingspread of 1.5 m flying 10 m/s in a region where the vertical component
of the earth's field is 30 µT?
Chapter 30 Solutions
MASTERPHYS:KNIGHT'S PHYSICS ACCESS+WKB
Ch. 30 - Prob. 1CQCh. 30 - You want to insert a loop of copper wire between...Ch. 30 - A vertical, rectangular loop of copper wire is...Ch. 30 - Does the loop of wire in FIGURE Q30.4 have a...Ch. 30 - s5. The two loops of wire in FIGURE Q30.5 are...Ch. 30 - FIGURE Q30.6 shows a bar magnet being pushed...Ch. 30 - A bar magnet is pushed toward a loop of wire as...Ch. 30 - FIGURE Q30.8 shows a bar magnet. a coil of wire,...Ch. 30 - Prob. 9CQCh. 30 - An inductor with a 2.0 A current stores energy. At...
Ch. 30 - Prob. 11CQCh. 30 - Prob. 12CQCh. 30 - Rank in order, from largest to smallest, the three...Ch. 30 - For the circuit of FIGURE Q30.14: a. What is the...Ch. 30 - The earth’s magnetic field strength is 5.0105T ....Ch. 30 - A potential difference of 0.050 V is developed...Ch. 30 - A 10 -cm-long wire is pulled along a U-shaped...Ch. 30 - What is the magnetic flux through the loop shown...Ch. 30 - FIGURE EX30.5 shows a 10cm10cm square bent at a 90...Ch. 30 - Prob. 6EAPCh. 30 - Prob. 7EAPCh. 30 - FIGURE EX30.8 shows a 2.0 -cm-diameter solenoid...Ch. 30 - Prob. 9EAPCh. 30 - 10. A solenoid is wound as shown in FIGURE...Ch. 30 - 11. The metal equilateral triangle in FIGURE...Ch. 30 - The current in the solenoid of FIGURE EX3O.12 is...Ch. 30 - The loop in FIGURE EX30.13 is being pushed into...Ch. 30 - FIGURE EX30.14 shows a 10-cm-diameter loop in...Ch. 30 - Prob. 15EAPCh. 30 - 16. A -turn coil of wire cm in diameter is in a...Ch. 30 - A 5.0 -cm-diameter coil has 20 turns and a...Ch. 30 - FIGURE EX30.18 shows the current as a function of...Ch. 30 - The magnetic field in FIGURE EX30.19 is decreasing...Ch. 30 - The magnetic field inside a -cm-diameter solenoid...Ch. 30 - Scientists studying an anomalous magnetic field...Ch. 30 - Prob. 22EAPCh. 30 - Prob. 23EAPCh. 30 - Prob. 24EAPCh. 30 - Prob. 25EAPCh. 30 - Prob. 26EAPCh. 30 - How much energy is stored in a -cm-diameter,...Ch. 30 - MRI (magnetic resonance imaging) is a medical...Ch. 30 - Prob. 29EAPCh. 30 - Prob. 30EAPCh. 30 - Prob. 31EAPCh. 30 - Prob. 32EAPCh. 30 - Prob. 33EAPCh. 30 - Prob. 34EAPCh. 30 - At t=0 s, the current in the circuit in FIGURE...Ch. 30 - The switch in FIGURE EX3O.36 has been open for a...Ch. 30 - Prob. 37EAPCh. 30 - Prob. 38EAPCh. 30 - Prob. 39EAPCh. 30 - Prob. 40EAPCh. 30 - A 10cm10cm square loop lies in the xy-plane. The...Ch. 30 - A spherical balloon with a volume of L is in a mT...Ch. 30 - Prob. 43EAPCh. 30 - Prob. 44EAPCh. 30 - Prob. 45EAPCh. 30 - FIGURE P30.46 shows a 4.0-cm-diameter loop with...Ch. 30 - Prob. 47EAPCh. 30 - Prob. 48EAPCh. 30 - Prob. 49EAPCh. 30 - Prob. 50EAPCh. 30 - Prob. 51EAPCh. 30 - Prob. 52EAPCh. 30 - Prob. 53EAPCh. 30 - Prob. 54EAPCh. 30 - Prob. 55EAPCh. 30 - Your camping buddy has an idea for a light to go...Ch. 30 - 57. The -wide, zero-resistance slide wire shown...Ch. 30 - ]58. You’ve decided to make the magnetic...Ch. 30 - FIGURE P30.59 shows a U-shaped conducting rail...Ch. 30 - Prob. 60EAPCh. 30 - Prob. 61EAPCh. 30 - Prob. 62EAPCh. 30 - Equation 30.26 is an expression for the induced...Ch. 30 - Prob. 64EAPCh. 30 - One possible concern with MRI (see Exercise 28) is...Ch. 30 - FIGURE P30.66 shows the current through a 10mH...Ch. 30 - Prob. 67EAPCh. 30 - Prob. 68EAPCh. 30 - Prob. 69EAPCh. 30 - Prob. 70EAPCh. 30 - An LC circuit is built with a inductor and an...Ch. 30 - Prob. 72EAPCh. 30 - For your final exam in electronics, you’re asked...Ch. 30 - The inductor in FIGURE P30.74 is a -cm-long, -cm-...Ch. 30 - The capacitor in FIGURE P30.75 is initially...Ch. 30 - The switch in FIGURE P30.76 has been open for a...Ch. 30 - 77. The switch in FIGURE P30.77 has been open for...Ch. 30 - Prob. 78EAPCh. 30 - Prob. 79EAPCh. 30 - Prob. 80EAPCh. 30 - In recent years it has been possible to buy a 1.0F...Ch. 30 - Prob. 82EAPCh. 30 - Prob. 83EAPCh. 30 - Prob. 84EAPCh. 30 - A 2.0 -cm-diameter solenoid is wrapped with 1000...Ch. 30 - High-frequency signals are often transmitted along...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- A circular loop of wire with a radius of 4.0 cm is in a uniform magnetic field of magnitude 0.060 T. The plane of the loop is perpendicular to the direction of the magnetic field. In a time interval of 0.50 s, the magnetic field changes to the opposite direction with a magnitude of 0.040 T. What is the magnitude of the average emf induced in the loop? (a) 0.20 V (b) 0.025 V (c) 5.0 mV (d) 1.0 mV (e) 0.20 mVarrow_forwardUsing an electromagnetic flowmeter (Fig. P19.69), a heart surgeon monitors the flow rate of blood through an artery. Electrodes A and B make contact with the outer surface of the blood vessel, which has interior diameter 3.00 mm. (a) For a magnetic field magnitude of 0.040 0 T, a potential difference of 160 V appears between the electrodes. Calculate the speed of the blood. (b) Verify that electrode A is positive, as shown. Does the sign of the emf depend on whether the mobile ions in the blood are predominantly positively or negatively charged? Explain. Figure P19.69arrow_forwardA metal bar of length 25 cm is placed perpendicular to a uniform magnetic field of strength 3 T. (a) Determine the induced emf between the ends of the rod when it is not moving, (b) Determine the emf when the rod is moving perpendicular to its Length and magnetic field with a speed of 50 cm/s.arrow_forward
- A thin conducting bar (60.0 cm long) aligned in the positive y direction is moving with velocity v=(1.25m/s)i in a region with a spatially uniform 0.400-T magnetic field directed at an angle of 36.0 above the xy plane. a. What is the magnitude of the emf induced along the length of the moving bar? b. Which end of the bar is positively charged?arrow_forwardUnreasonable results Frustrated by the small Hall voltage obtained in blood flow measurements, a medical physicist decides to increase the applied magnetic field strength to get a 0.500-V output for blood moving at 30.0 cm/s in a 1.50-cm-diameter vessel. (a) What magnetic field strength is needed? (b) What is unreasonable about this result? (C) Which premise is responsible?arrow_forwardA time-dependent uniform magnetic field of magnitude B(t) is confined in a cylindrical region of radius R. A conducting rod of length 2D is placed in the region, as shown below. Show that the emf between the ends of the rod is given by dBdtDR2D2 . ( Hint: To find the between the ends, we need to integrate the electric field from one end to the other. To find the electric field, use Faraday’s law as “Ampere’s law for E”.)arrow_forward
- A conducting rod of length moves with velocity v parallel to a long wire carrying a steady current I. The axis of the rod is maintained perpendicular to the wire with the near end a distance r away (Fig. P30.44). Show that the magnitude of the emf induced in the rod is E=0Iv2ln(1+lr) Figure P30.44arrow_forwardA circular loop of wire of resistance R = 0.500 and radius r = 8.00 cm is in a uniform magnetic field directed out of the page as in Figure P31.54. If a clockwise current of I = 2.50 mA is induced in the loop, (a) is the magnetic field increasing or decreasing in time? (b) Find the rate at which the field is changing with time. Figure P31.54arrow_forwardIn Figure P20.65 the rolling axle of length 1.50 m is pushed along horizontal rails at a constant speed v = 3.00 m/s. A resist or R = 0.400 is connected to the rails at points a and b, directly opposite each other. (The wheels make good electrical contact with the rails, so the axle, rails, and R form a closed-loop circuit. The only significant resistance in the circuit is R.) A uniform magnetic field B = 0.800 T is directed vertically downward. (a) Find the induced current I in the resistor. (b) What horizontal force F is required to keep the axle rolling at constant speed? (c) Which end of the resistor, a or b. is at the higher electric potential? (d) Alter the axle rolls past the resistor, does the current in R reverse direction? Explain your answer. Figure P20.65arrow_forward
- Design a current loop that, when rotated in a uniform magnetic field of strength 0.10 T, will produce an emf =0 sin t. where 0=110V and 0=110V .arrow_forwardIs Ampere’s law valid for all closed paths? Why isn’t it normally useful for calculating a magnetic field?arrow_forwardA parallel-plate capacitor with plate separation d is connected to a source of emf that places a time-dependent voltage V(t) across its circular plates of radius r0and area (a) Write an expression for the time rate of change of energy inside the capacitor in terms of V(t) and dV(t)/ dt. (b) Assuming that V(t) is increasing with time, identify the directions of the elecuic field lines inside the capacitor and of the magnetic field lines at the edge of the region between the plates, and then the direction of the Poynting vector S at this location. (c) Obtain expressions for the time dependence of E(t), for B(t) from the displacement current, and for the magnitude of the Poynting vector at the edge of the region between the plates. (d) From S , obtain an expression In terms of ‘(t) and dV(t)/dt for the rate at which electromagnetic field energy the region between the plates. (e) Compare the results of pails (a) and (d) and explain the relationship between them.arrow_forward
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