The Solar System
10th Edition
ISBN: 9781337672252
Author: The Solar System
Publisher: Cengage
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Chapter 3, Problem 9P
To determine
The angular diameter of earth.
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From Earth, the angular size of the Moon is 0.5 degree. The distance between the Earth and the Moon is 384,400 km. Use the small-angle formula to find the size of the Moon. Compare the number to the distance of the Moon given previously. It is consistent?
d. Diameter of the Sun
I h
A
d.
Standing on the beach at sunset, you extend the tip of your finger at your full arm length from
your face, covering the Sun. Upon moving your finger around, you find that only about half of its
width is needed to completely cover the Sun's diameter. You measure your finger width to be 0.5
inches. You know your arm length to be 28.0 inches. You have be told that the Sun is
approximately 93 million miles away. Use this information to determine the approximate
diameter of the Sun, filling in the table below with the proper quantities measure in meters.
1 = ½ finger
g = eye level
height
d = object
h = Diameter
f= object
height from
level to top of eye level
X = Arm
A =
angle
width
length
distance
from eye
of the Sun
object
The Earth is about 12,000 km in diameter. It is therefore how many orders of magnitude wider than you are tall? (i.e., the Earth’s diameter is how many times larger than your height (give an order-of-magnitude estimate)?) (I am 5'2")
Chapter 3 Solutions
The Solar System
Ch. 3 - Why are most of the constellations that were...Ch. 3 - Prob. 2RQCh. 3 - Prob. 3RQCh. 3 - Prob. 4RQCh. 3 - Prob. 5RQCh. 3 - Prob. 6RQCh. 3 - Prob. 7RQCh. 3 - Prob. 8RQCh. 3 - Prob. 9RQCh. 3 - Prob. 10RQ
Ch. 3 - Prob. 11RQCh. 3 - If Earth had no atmosphere, what color would the...Ch. 3 - If the Moon orbited Earth from North Pole to South...Ch. 3 - Why do solar eclipses happen only at new moon? Why...Ch. 3 - Prob. 15RQCh. 3 - Prob. 16RQCh. 3 - Prob. 17RQCh. 3 - Why cant the Moon be eclipsed when it is halfway...Ch. 3 - Prob. 19RQCh. 3 - Prob. 20RQCh. 3 - Prob. 21RQCh. 3 - Prob. 22RQCh. 3 - Pretend the Moon’s orbit around Earth is a perfect...Ch. 3 - Prob. 2PCh. 3 - Identify the phases of the Moon if at sunset in...Ch. 3 - What fraction of the Moons surface area is the far...Ch. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10PCh. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - If a solar eclipse occurs on October 3: (a) Why...Ch. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 1SPCh. 3 - Prob. 2SPCh. 3 - Prob. 1LLCh. 3 - Prob. 2LLCh. 3 - Prob. 3LLCh. 3 - Prob. 4LLCh. 3 - Prob. 5LLCh. 3 - Prob. 6LLCh. 3 - Prob. 7LLCh. 3 - Prob. 8LLCh. 3 - Prob. 9LLCh. 3 - Prob. 10LLCh. 3 - Prob. 11LL
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- What would be the distance to the nearest star, Alpha Centauri (4.4 light-years away). (Hint: Find the distance to Alpha Centauri in units of AU.) Express your answer to two significant figures and include the appropriate units.arrow_forwardThe mean radius of earth is 6,371.0 kilometers and the mean radius of earths moon is 1,737.5 kilometers. What is the approximate difference in the mean conferences, in kilometers, of earth and earths moon? Round your answer to the nearest tenth of a kilometer.arrow_forwardThinking about the Scale of the Solar System As we discussed, the radius of the Earth is approximately 6370 km. The Sun, on the other hand, is approximately 700,000 km in radius and located, on average, one astronomical unit (1 au=1.5x108 km) from the Earth. Imagine that you stand near Mansueto Library, at the corner of 57th and Ellis. You hold a standard desk globe, which has a diameter of 12 inches, and you want to build a model of the Sun, Earth, and their separation that keeps all sizes and lengths in proportion to one another. a) How big would the Sun be in this scale model? Give your answer in feet and meters. b) The nearest star to the Solar System outside of the Sun is Proxima Centauri, which is approximately 4.2 light years away (a light year is the distance light travels in one year, or approximately 9.5x1012 km). Given the scale model outlined above, how far would a model Proxima Centauri be placed from you? Give your answer in miles and km.arrow_forward
- Suppose you were given a 3 in diameter ball to represent the Earth and a 1 in diameter ball to represent the Moon. (The actual ratio of Earth diameter to Moon diameter is 3.7 to 1.) The actual average Earth–Moon distance is about 384,000 kilometers, and Earth’s diameter is about 12,800 kilometers. How many “Earth diameters” is the distance from Earth to the Moon? Based on your answer to Question 2, what is the correct scaled distance of the Moon, using the 3-inch ball as Earth? The Sun’s actual diameter is about 1,400,000 kilometers. How many “Earth diameters” is this? Given your 3-inch Earth, how large (i.e what diameter) of a ball would you need to represent the Sun? Give your answer in feet. The average Earth–Sun distance is about 149,600,000 km. To represent this distance to scale, how far away would you have to place your 3-inch Earth from your Sun? Give your answer in feet. Could we use this scale to visualize the solar system instead of just the Earth and Moon? Why or Why…arrow_forwardOn August 27, 2003, the planet Mars was at a distance of 0.373 AU from Earth. The diameter of Mars is 6788 km. Calculate the angular diameter of Mars, as seen from Earth on August 27, 2003. Give your answer in arcminutes.arrow_forwardIf the moon is 238,000 miles from earth, convert this distance to meters and leave your answer in scientific notation. ( Recall 5280 ft = 1 mi , 1 m = 3.3 ft) b) In a school zone, the speed limit is 25 miles/hour. Convert this speed to meters/second (m/s). Round your answer to the nearest tenth.arrow_forward
- The angular diameter and distance of the Moon are 31 minutes of arc and 384,400 km. Use the small angle equation to find the linear diameter of the Moonarrow_forwardThe moon is about 3.8 × 10^5 km from Earth. How many centimeters is this? One km = 100,000 cm. Write your answer in scientific notationarrow_forwardEAn astronaut arrives on the planet Oceania and climbs to the top of a cliff overlooking the sea. The astronaut's eye is 100 m above the sea level and he observes that the horizon in all directions appears to be at angle of 5 mrad below the local horizontal. What is the radius of the planet Oceania at sea level? How far away is the horizon from the astronaut? 6000 km and 50 km 3600 km and 20 km 2000 km and 40 km 8000 km and 40 kmarrow_forward
- Use the small-angle formula to calculate the angular diameter of Earth as seen from the Moon. (Note: The linear diameter of Earth is 12,700 km.)arrow_forwardGive four ways to demonstrate that Earth is spherical.arrow_forwardConsider a calendar based entirely on the day and the month (the Moon’s period from full phase to full phase). How many days are there in a month? Can you figure out a scheme analogous to leap year to make this calendar work?arrow_forward
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