The Solar System
10th Edition
ISBN: 9781337672252
Author: The Solar System
Publisher: Cengage
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Chapter 3, Problem 1P
Pretend the Moon’s orbit around Earth is a perfect circle. How long does it take in units of days for the Moon to move 90 degrees relative to the stars? Is this number dependent on the synodic period or the sidereal period?
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What would be the duration of the year if the
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The earth revolves around the sun in exactly 365 1/4 days which is equivalent to 1 year. To make up for the loss of 1/4 day, the calendar was adjusted so that we have a leap year for every 4 years. If the earth were to speed in its motion slightly so that a year would be completed in exactly 365 days and 6 hours, how often would we need to have a leap year?
To find the acceleration from equation (a=v^2/r), the velocity of an object traveling in a circle is the distance traveled (i.e. the circumference, which is 2?r) divided by the travel time (i.e. the period T). The Moon’s sidereal period is 27.32 days. Convert this period into seconds. Complete Table 1 for the Moon to find its orbital period in seconds, its average velocity in meters per second and its acceleration in meters per second^2 where Orbital radius (m) = 3.84 x 10^8.
Chapter 3 Solutions
The Solar System
Ch. 3 - Why are most of the constellations that were...Ch. 3 - Prob. 2RQCh. 3 - Prob. 3RQCh. 3 - Prob. 4RQCh. 3 - Prob. 5RQCh. 3 - Prob. 6RQCh. 3 - Prob. 7RQCh. 3 - Prob. 8RQCh. 3 - Prob. 9RQCh. 3 - Prob. 10RQ
Ch. 3 - Prob. 11RQCh. 3 - If Earth had no atmosphere, what color would the...Ch. 3 - If the Moon orbited Earth from North Pole to South...Ch. 3 - Why do solar eclipses happen only at new moon? Why...Ch. 3 - Prob. 15RQCh. 3 - Prob. 16RQCh. 3 - Prob. 17RQCh. 3 - Why cant the Moon be eclipsed when it is halfway...Ch. 3 - Prob. 19RQCh. 3 - Prob. 20RQCh. 3 - Prob. 21RQCh. 3 - Prob. 22RQCh. 3 - Pretend the Moon’s orbit around Earth is a perfect...Ch. 3 - Prob. 2PCh. 3 - Identify the phases of the Moon if at sunset in...Ch. 3 - What fraction of the Moons surface area is the far...Ch. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10PCh. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - If a solar eclipse occurs on October 3: (a) Why...Ch. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 1SPCh. 3 - Prob. 2SPCh. 3 - Prob. 1LLCh. 3 - Prob. 2LLCh. 3 - Prob. 3LLCh. 3 - Prob. 4LLCh. 3 - Prob. 5LLCh. 3 - Prob. 6LLCh. 3 - Prob. 7LLCh. 3 - Prob. 8LLCh. 3 - Prob. 9LLCh. 3 - Prob. 10LLCh. 3 - Prob. 11LL
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- In a part of Earth’s orbit where Earth is moving faster than usual around the Sun, would the length of the sidereal day change? If so, how? Explain.arrow_forwardIf G = 6.674 ⨉ 10 −11m3/kg/s 2and M Earth= 5.972 ⨉ 10 24kg and the sidereal period of the Earth is 27.32 days, then, from Kepler’s third law in #4, what is the expected orbital distance of the Moon?arrow_forwardIt takes 23 hours 56 minutes and 4 seconds for the earth to make one revolution (mean sidereal day). What is the angular speed of the earth? Submit Answer Tries 0/12 Assume the earth is spherical. Relative to someone on the rotation axis, what is the linear speed of an object on the surface if the radius vector from the center of the earth to the object makes an angle of 61.0° with the axis of rotation. The radius of the earth is 6.37×103 km. Submit Answer Tries 0/12 What is the acceleration of the object on the surface of the earth in the previous problem? Submit Answer Tries 0/12arrow_forward
- I measured the angular separation of Jupiter's moons in arcminutes/arcseconds and converted this angle to radians. The conversion factor for degrees to radians was 57.3 degrees per radian. Which unit of measurement is larger? 1 degree or 1 radian?arrow_forwardIt takes the Earth approximately 365 normal days to orbit the sun. Using this information and assuming 24 hours in a normal day, approximately how many nanoseconds does it take for the Earth to orbit the sun?arrow_forwardOne full year is 365.26 days. Using this number and the distance between the sun and the earth, calculate the Earth’s velocity. Question 8 options: 21.4 km/s 23.7 km/s 26.2 km/s 29.8 km/s 31.9 km/sarrow_forward
- The earth takes 365.256 days to go around the sun and 23 hours 56 min and 4.0905 s to revolve about its axis. These give the earth an orbital speed of 29.8 km/s and a rotational speed of 465 m/s at the equator, a 64:1 ratio. If the moon orbits the earth in a period of 29 d 12 h 44 min 2.9 s, has a sidereal period of 27.321582 days, a radius of 1737 km, and a mean distance from the earth of 384,000 km, what is the similar velocity ratio for the moon?arrow_forwardThe Earth covers about 1° per day in its orbit about the Sun, and the solar day is slightly longer than the sidereal day. If Earth spun in a retrograde direction like Venus but it still had the same sidereal period (23 hr 56 min), how long would the solar day be? The solar day would be 72 hr and min.arrow_forwardMars' period (its "year") was noted by Kepler to be about 687 days (Earth days), which is (687d / 365 d) = 1.88 yr. Determine the distance of Mars from the Sun using the Earth as reference. (The distance of Earth from the Sun is 1.50 x 10 m) !3! Thu TMS IMS TE TES TES TE 2 28 x 10 m TES yr After reading and understanding the concept Gravity, please do the following problems: 1. What keeps a satellite up in its orbit around the Earth?arrow_forward
- Calculate the angle of (a) 10 (degree) (b) 1′ (minute of arc or arcmin) and (c) 1″(second of arc or arc second) in radians. Use 3600=2π rad, 10 =60′ and1′ = 60 ″arrow_forwardIf city is located in 2.8° north latitude and 46.0° east longitude. From there, you want to fly to a city in 7° north latitude and 52° east longitude. How much is the arc length of the big circle at 11000 m when the earth's radius is 6370 km? The arc length is 14223 km. Give your answer rounded to one kilmetre. Your last answer was interpreted as follows: 14223 XAnswer is incorrect. Keep centre of Earth as origin and define vectors to cities. Try again.arrow_forwardRight Ascension and Declination is a coordinate system for objects in the sky, and is analogous to longitude and latitude coordinates, respectively, for objects on Earth. Right ascension (RA) coordinates are given in hours (h), minutes (m), and seconds (s). Declination (DEC) coordinates are given in degrees (°), arcminutes ('), and arcseconds ("). Sirius is the brightest star in the night sky. Its RA and DEC coordinates are 6h 45 m 7.96 s and -16° 44' 78.6". Using unit conversion, find the RA coordinate only in hours and round the coordinate to 5 significant figures.arrow_forward
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