sp 3 hybridized carbon atoms, most acidic proton, sp 3 hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out. Concept introduction: Hybridization: hybridization is mixing of valence atomic orbitals to get equivalent (equally energetic) hybridized orbitals. Sp 3 hybridized orbital has four orbitals. Sp 3 hybridized carbon atom in a compound has 4 sigma bonds. Identify: the sp 3 hybridized carbon atoms in the cyclopentadiene.

Question

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Answer 1

Question

Chapter 3, Problem 67IP

(a)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Hybridization: hybridization is mixing of valence atomic orbitals to get equivalent (equally energetic) hybridized orbitals. Sp³ hybridized orbital has four orbitals. Sp³ hybridized carbon atom in a compound has 4 sigma bonds.

Identify: the sp³ hybridized carbon atoms in the cyclopentadiene.

(b)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Most acidic proton of a compound depends upon the stability of conjugate base formed after the deprotonation.

Identify: most acidic proton presented in cyclopentadiene.

(c)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Resonance structures: Resonance structures are electrically equivalent Lewis structures. Formal charges on these structures are same, these structures represented through a double headed arrow between the structures. Resonance structures are resulted during the delocalization of pi-bonding electrons and lone pair of electrons in the molecule.

To draw: resonance structures of cyclopentadienyl anion.

(d)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Hybridization: hybridization is mixing of valence atomic orbitals to get equivalent (equally energetic) hybridized orbitals. Geometry can be predicted according to the hybridization of the molecule.

To find: the number sp³- hybridized carbon atoms present in cyclopentadienyl anion.

(e)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Geometry is predicted according to the hybridization of the molecule. Hybridization: hybridization is mixing of valence atomic orbitals to get equivalent (equally energetic) hybridized orbitals.

To find: geometry of cyclopentadienyl anion.

(f)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

In bond-line structure, bonds between other than hydrogen atoms and lone pairs presented are shown. Number of hydrogen atoms attached to a carbon atom depends upon the number of other than hydrogen atoms bonded and lone pairs presented to that carbon atom. Covalence of carbon is four. So hydrogen atoms are presented accordingly if the counting of carbon atom’s bonds with other than hydrogen atom and lone pair of electrons are less than four.

To find: number of hydrogen atoms presented in the cyclopentadienyl anion.

(g)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Lone pairs of the molecules are electron pairs which do not participate in the sigma bonding of the molecule. It can participate in the delocalization of molecule.

To find: the lone pairs present in the cyclopentadienyl anion.

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If a reaction occurs, what would be the major products? Please include a detailed explanation as well as a drawing showing how the reaction occurs and what the final product is.

Answer 2

Question

Chapter 3, Problem 67IP

(a)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Hybridization: hybridization is mixing of valence atomic orbitals to get equivalent (equally energetic) hybridized orbitals. Sp³ hybridized orbital has four orbitals. Sp³ hybridized carbon atom in a compound has 4 sigma bonds.

Identify: the sp³ hybridized carbon atoms in the cyclopentadiene.

(b)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Most acidic proton of a compound depends upon the stability of conjugate base formed after the deprotonation.

Identify: most acidic proton presented in cyclopentadiene.

(c)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Resonance structures: Resonance structures are electrically equivalent Lewis structures. Formal charges on these structures are same, these structures represented through a double headed arrow between the structures. Resonance structures are resulted during the delocalization of pi-bonding electrons and lone pair of electrons in the molecule.

To draw: resonance structures of cyclopentadienyl anion.

(d)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Hybridization: hybridization is mixing of valence atomic orbitals to get equivalent (equally energetic) hybridized orbitals. Geometry can be predicted according to the hybridization of the molecule.

To find: the number sp³- hybridized carbon atoms present in cyclopentadienyl anion.

(e)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Geometry is predicted according to the hybridization of the molecule. Hybridization: hybridization is mixing of valence atomic orbitals to get equivalent (equally energetic) hybridized orbitals.

To find: geometry of cyclopentadienyl anion.

(f)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

In bond-line structure, bonds between other than hydrogen atoms and lone pairs presented are shown. Number of hydrogen atoms attached to a carbon atom depends upon the number of other than hydrogen atoms bonded and lone pairs presented to that carbon atom. Covalence of carbon is four. So hydrogen atoms are presented accordingly if the counting of carbon atom’s bonds with other than hydrogen atom and lone pair of electrons are less than four.

To find: number of hydrogen atoms presented in the cyclopentadienyl anion.

(g)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Lone pairs of the molecules are electron pairs which do not participate in the sigma bonding of the molecule. It can participate in the delocalization of molecule.

To find: the lone pairs present in the cyclopentadienyl anion.

Expert Solution & Answer

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Check out a sample textbook solution

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Answer 3

Question

Chapter 3, Problem 67IP

(a)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Hybridization: hybridization is mixing of valence atomic orbitals to get equivalent (equally energetic) hybridized orbitals. Sp³ hybridized orbital has four orbitals. Sp³ hybridized carbon atom in a compound has 4 sigma bonds.

Identify: the sp³ hybridized carbon atoms in the cyclopentadiene.

(b)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Most acidic proton of a compound depends upon the stability of conjugate base formed after the deprotonation.

Identify: most acidic proton presented in cyclopentadiene.

(c)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Resonance structures: Resonance structures are electrically equivalent Lewis structures. Formal charges on these structures are same, these structures represented through a double headed arrow between the structures. Resonance structures are resulted during the delocalization of pi-bonding electrons and lone pair of electrons in the molecule.

To draw: resonance structures of cyclopentadienyl anion.

(d)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Hybridization: hybridization is mixing of valence atomic orbitals to get equivalent (equally energetic) hybridized orbitals. Geometry can be predicted according to the hybridization of the molecule.

To find: the number sp³- hybridized carbon atoms present in cyclopentadienyl anion.

(e)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Geometry is predicted according to the hybridization of the molecule. Hybridization: hybridization is mixing of valence atomic orbitals to get equivalent (equally energetic) hybridized orbitals.

To find: geometry of cyclopentadienyl anion.

(f)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

In bond-line structure, bonds between other than hydrogen atoms and lone pairs presented are shown. Number of hydrogen atoms attached to a carbon atom depends upon the number of other than hydrogen atoms bonded and lone pairs presented to that carbon atom. Covalence of carbon is four. So hydrogen atoms are presented accordingly if the counting of carbon atom’s bonds with other than hydrogen atom and lone pair of electrons are less than four.

To find: number of hydrogen atoms presented in the cyclopentadienyl anion.

(g)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Lone pairs of the molecules are electron pairs which do not participate in the sigma bonding of the molecule. It can participate in the delocalization of molecule.

To find: the lone pairs present in the cyclopentadienyl anion.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 3, Problem 67IP

(a)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Hybridization: hybridization is mixing of valence atomic orbitals to get equivalent (equally energetic) hybridized orbitals. Sp³ hybridized orbital has four orbitals. Sp³ hybridized carbon atom in a compound has 4 sigma bonds.

Identify: the sp³ hybridized carbon atoms in the cyclopentadiene.

(b)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Most acidic proton of a compound depends upon the stability of conjugate base formed after the deprotonation.

Identify: most acidic proton presented in cyclopentadiene.

(c)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Resonance structures: Resonance structures are electrically equivalent Lewis structures. Formal charges on these structures are same, these structures represented through a double headed arrow between the structures. Resonance structures are resulted during the delocalization of pi-bonding electrons and lone pair of electrons in the molecule.

To draw: resonance structures of cyclopentadienyl anion.

(d)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Hybridization: hybridization is mixing of valence atomic orbitals to get equivalent (equally energetic) hybridized orbitals. Geometry can be predicted according to the hybridization of the molecule.

To find: the number sp³- hybridized carbon atoms present in cyclopentadienyl anion.

(e)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Geometry is predicted according to the hybridization of the molecule. Hybridization: hybridization is mixing of valence atomic orbitals to get equivalent (equally energetic) hybridized orbitals.

To find: geometry of cyclopentadienyl anion.

(f)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

In bond-line structure, bonds between other than hydrogen atoms and lone pairs presented are shown. Number of hydrogen atoms attached to a carbon atom depends upon the number of other than hydrogen atoms bonded and lone pairs presented to that carbon atom. Covalence of carbon is four. So hydrogen atoms are presented accordingly if the counting of carbon atom’s bonds with other than hydrogen atom and lone pair of electrons are less than four.

To find: number of hydrogen atoms presented in the cyclopentadienyl anion.

(g)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Lone pairs of the molecules are electron pairs which do not participate in the sigma bonding of the molecule. It can participate in the delocalization of molecule.

To find: the lone pairs present in the cyclopentadienyl anion.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 3, Problem 67IP

(a)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Hybridization: hybridization is mixing of valence atomic orbitals to get equivalent (equally energetic) hybridized orbitals. Sp³ hybridized orbital has four orbitals. Sp³ hybridized carbon atom in a compound has 4 sigma bonds.

Identify: the sp³ hybridized carbon atoms in the cyclopentadiene.

(b)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Most acidic proton of a compound depends upon the stability of conjugate base formed after the deprotonation.

Identify: most acidic proton presented in cyclopentadiene.

(c)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Resonance structures: Resonance structures are electrically equivalent Lewis structures. Formal charges on these structures are same, these structures represented through a double headed arrow between the structures. Resonance structures are resulted during the delocalization of pi-bonding electrons and lone pair of electrons in the molecule.

To draw: resonance structures of cyclopentadienyl anion.

(d)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Hybridization: hybridization is mixing of valence atomic orbitals to get equivalent (equally energetic) hybridized orbitals. Geometry can be predicted according to the hybridization of the molecule.

To find: the number sp³- hybridized carbon atoms present in cyclopentadienyl anion.

(e)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Geometry is predicted according to the hybridization of the molecule. Hybridization: hybridization is mixing of valence atomic orbitals to get equivalent (equally energetic) hybridized orbitals.

To find: geometry of cyclopentadienyl anion.

(f)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

In bond-line structure, bonds between other than hydrogen atoms and lone pairs presented are shown. Number of hydrogen atoms attached to a carbon atom depends upon the number of other than hydrogen atoms bonded and lone pairs presented to that carbon atom. Covalence of carbon is four. So hydrogen atoms are presented accordingly if the counting of carbon atom’s bonds with other than hydrogen atom and lone pair of electrons are less than four.

To find: number of hydrogen atoms presented in the cyclopentadienyl anion.

(g)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Lone pairs of the molecules are electron pairs which do not participate in the sigma bonding of the molecule. It can participate in the delocalization of molecule.

To find: the lone pairs present in the cyclopentadienyl anion.

Answer 6

Chapter 3, Problem 67IP

(a)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Hybridization: hybridization is mixing of valence atomic orbitals to get equivalent (equally energetic) hybridized orbitals. Sp³ hybridized orbital has four orbitals. Sp³ hybridized carbon atom in a compound has 4 sigma bonds.

Identify: the sp³ hybridized carbon atoms in the cyclopentadiene.

Answer 7

Chapter 3, Problem 67IP

(a)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Hybridization: hybridization is mixing of valence atomic orbitals to get equivalent (equally energetic) hybridized orbitals. Sp³ hybridized orbital has four orbitals. Sp³ hybridized carbon atom in a compound has 4 sigma bonds.

Identify: the sp³ hybridized carbon atoms in the cyclopentadiene.

Answer 8

(b)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Most acidic proton of a compound depends upon the stability of conjugate base formed after the deprotonation.

Identify: most acidic proton presented in cyclopentadiene.

Answer 9

(b)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Most acidic proton of a compound depends upon the stability of conjugate base formed after the deprotonation.

Identify: most acidic proton presented in cyclopentadiene.

Answer 10

(c)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Resonance structures: Resonance structures are electrically equivalent Lewis structures. Formal charges on these structures are same, these structures represented through a double headed arrow between the structures. Resonance structures are resulted during the delocalization of pi-bonding electrons and lone pair of electrons in the molecule.

To draw: resonance structures of cyclopentadienyl anion.

Answer 11

(c)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Resonance structures: Resonance structures are electrically equivalent Lewis structures. Formal charges on these structures are same, these structures represented through a double headed arrow between the structures. Resonance structures are resulted during the delocalization of pi-bonding electrons and lone pair of electrons in the molecule.

To draw: resonance structures of cyclopentadienyl anion.

Answer 12

(d)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Hybridization: hybridization is mixing of valence atomic orbitals to get equivalent (equally energetic) hybridized orbitals. Geometry can be predicted according to the hybridization of the molecule.

To find: the number sp³- hybridized carbon atoms present in cyclopentadienyl anion.

Answer 13

(d)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Hybridization: hybridization is mixing of valence atomic orbitals to get equivalent (equally energetic) hybridized orbitals. Geometry can be predicted according to the hybridization of the molecule.

To find: the number sp³- hybridized carbon atoms present in cyclopentadienyl anion.

Answer 14

(e)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Geometry is predicted according to the hybridization of the molecule. Hybridization: hybridization is mixing of valence atomic orbitals to get equivalent (equally energetic) hybridized orbitals.

To find: geometry of cyclopentadienyl anion.

Answer 15

(e)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Geometry is predicted according to the hybridization of the molecule. Hybridization: hybridization is mixing of valence atomic orbitals to get equivalent (equally energetic) hybridized orbitals.

To find: geometry of cyclopentadienyl anion.

Answer 16

(f)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

In bond-line structure, bonds between other than hydrogen atoms and lone pairs presented are shown. Number of hydrogen atoms attached to a carbon atom depends upon the number of other than hydrogen atoms bonded and lone pairs presented to that carbon atom. Covalence of carbon is four. So hydrogen atoms are presented accordingly if the counting of carbon atom’s bonds with other than hydrogen atom and lone pair of electrons are less than four.

To find: number of hydrogen atoms presented in the cyclopentadienyl anion.

Answer 17

(f)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

In bond-line structure, bonds between other than hydrogen atoms and lone pairs presented are shown. Number of hydrogen atoms attached to a carbon atom depends upon the number of other than hydrogen atoms bonded and lone pairs presented to that carbon atom. Covalence of carbon is four. So hydrogen atoms are presented accordingly if the counting of carbon atom’s bonds with other than hydrogen atom and lone pair of electrons are less than four.

To find: number of hydrogen atoms presented in the cyclopentadienyl anion.

Answer 18

(g)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Lone pairs of the molecules are electron pairs which do not participate in the sigma bonding of the molecule. It can participate in the delocalization of molecule.

To find: the lone pairs present in the cyclopentadienyl anion.

Answer 19

(g)

Interpretation Introduction

Interpretation:

sp³ hybridized carbon atoms, most acidic proton, sp³ hybridized carbon atoms of conjugate base, geometry of conjugate base, number of hydrogen atoms in the conjugate base, number of lone pairs in the conjugate base and the resonance structure of conjugate base of cyclopentadiene are needed to find out.

Concept introduction:

Lone pairs of the molecules are electron pairs which do not participate in the sigma bonding of the molecule. It can participate in the delocalization of molecule.

To find: the lone pairs present in the cyclopentadienyl anion.

Answer 20

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Answer 21

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Answer 22

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Answer 23

Ch. 3.2 - Prob. 1LTS Ch. 3.2 - Prob. 1PTS Ch. 3.3 - Prob. 2LTS Ch. 3.3 - Prob. 4PTS Ch. 3.3 - Prob. 5ATS Ch. 3.3 - Prob. 6ATS Ch. 3.3 - Prob. 3LTS Ch. 3.3 - Prob. 7PTS Ch. 3.4 - Prob. 5LTS Ch. 3.4 - Prob. 13PTS

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Chapter 3 Solutions