The given ions are to be placed in decreasing order of size. Concept introduction: The ionic size depends on the number of electrons transferred. The atomic size of cations is smaller than anions. Also the size of ions increases by gaining electrons whereas size decreases by accepting electrons. To determine: The decreasing order of size of ions V ,V 2 + ,V 3 + , V 5 + .
The given ions are to be placed in decreasing order of size. Concept introduction: The ionic size depends on the number of electrons transferred. The atomic size of cations is smaller than anions. Also the size of ions increases by gaining electrons whereas size decreases by accepting electrons. To determine: The decreasing order of size of ions V ,V 2 + ,V 3 + , V 5 + .
Solution Summary: The author explains that the ionic size depends on the number of electrons transferred. The atomic size of cations is smaller than anions.
Interpretation: The given ions are to be placed in decreasing order of size.
Concept introduction: The ionic size depends on the number of electrons transferred. The atomic size of cations is smaller than anions. Also the size of ions increases by gaining electrons whereas size decreases by accepting electrons.
To determine: The decreasing order of size of ions V,V2+,V3+,V5+.
(b)
Interpretation Introduction
Interpretation: The given ions are to be placed in decreasing order of size.
Concept introduction: The ionic size depends on the number of electrons transferred. The atomic size of cations is smaller than anions. Also the size of ions increases by gaining electrons whereas size decreases by accepting electrons.
To determine: The decreasing order of size of ions Na+,K+,Rb+andCs+.
(c)
Interpretation Introduction
Interpretation: The given ions are to be placed in decreasing order of size.
Concept introduction: The ionic size depends on the number of electrons transferred. The atomic size of cations is smaller than anions. Also the size of ions increases by gaining electrons whereas size decreases by accepting electrons.
To determine: The decreasing order of size of ions Te2−,I−,Cs+,Ba2+.
(d)
Interpretation Introduction
Interpretation: The given ions are to be placed in decreasing order of size.
Concept introduction: The ionic size depends on the number of electrons transferred. The atomic size of cations is smaller than anions. Also the size of ions increases by gaining electrons whereas size decreases by accepting electrons.
To determine: The decreasing order of size of ions P,P−,P2−,P3−.
(e)
Interpretation Introduction
Interpretation: The given ions are to be placed in decreasing order of size.
Concept introduction: The ionic size depends on the number of electrons transferred. The atomic size of cations is smaller than anions. Also the size of ions increases by gaining electrons whereas size decreases by accepting electrons.
To determine: The decreasing order of size of ions O2−,S−,Se2−,Te2−.
Rank the labeled protons (Ha-Hd) in order of increasing acidity, starting with the least acidic.
НОН НЬ
OHd
Онс
Can the target compound at right be efficiently synthesized in good yield from the unsubstituted benzene at left?
?
starting
material
target
If so, draw a synthesis below. If no synthesis using reagents ALEKS recognizes is possible, check the box under the drawing area.
Be sure you follow the standard ALEKS rules for submitting syntheses.
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Note for advanced students: you may assume that you are using a large excess of benzene as your starting material.
C
:0
T
Add/Remove step
G
The following equations represent the formation of compound MX. What is the AH for the
electron affinity of X (g)?
X₂ (g) → 2X (g)
M (s) → M (g)
M (g)
M (g) + e-
AH = 60 kJ/mol
AH = 22 kJ/mol
X (g) + e-X (g)
M* (g) +X (g) → MX (s)
AH = 118 kJ/mol
AH = ?
AH = -190 kJ/mol
AH = -100 kJ/mol
a)
-80 kJ
b)
-30 kJ
c)
-20 kJ
d)
20 kJ
e)
156 kJ
Chapter 3 Solutions
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