The value of v rms speed of CH 4 at − 20 ° C has to be determined. Concept Introduction: Root mean square speed is square root of average value of square of molecular speeds of gas molecules. It includes molecular weight and temperature, both of which affect kinetic energy of gas. It is denoted by v rms . The expression for v rms is as follows: v rms = 3 R T M (1) Here, R is gas constant. T is absolute temperature of gas. M is molecular weight of gas.

Question

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Answer 1

Question

Chapter 3, Problem 3D.9E

(a)

Interpretation Introduction

Interpretation:

The value of vrms speed of CH4 at −20 °C has to be determined.

Concept Introduction:

Root mean square speed is square root of average value of square of molecular speeds of gas molecules. It includes molecular weight and temperature, both of which affect kinetic energy of gas. It is denoted by vrms. The expression for vrms is as follows:

vrms=3RTM (1)

Here,

R is gas constant.

T is absolute temperature of gas.

M is molecular weight of gas.

(a)

Expert Solution

Answer to Problem 3D.9E

Value of vrms of CH4 is 627 m⋅s−1.

Explanation of Solution

Conversion factor to convert −20 °C to Kelvin is as follows:

T(K)=temperature in celsius+273.15=−20 °C+273.15=253.15 K

Substitute 253.15 K for T, 16.04 g/mol for M, and 8.3145 J⋅K−1⋅mol−1 for R in equation (1) to calculate vrms for CH4.

vrms=(3(8.3145 J⋅K−1⋅mol−1)(253.15 K)(16.04 g/mol))(103 g1 kg)=627 m⋅s−1

Hence vrms speed of CH4 is 627 m⋅s−1.

(b)

Interpretation Introduction

Interpretation:

The value of vrms speed of C2H6 at −20 °C has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 3D.9E

Value of vrms for C2H6 is 458 m⋅s−1.

Explanation of Solution

Conversion factor to convert −20 °C to Kelvin is as follows:

T(K)=temperature in celsius+273.15=−20 °C+273.15=253.15 K

Substitute 253.15 K for T, 30.07 g/mol for M, and 8.3145 J⋅K−1⋅mol−1 for R in equation (1) to calculate vrms for C2H6.

vrms=(3(8.3145 J⋅K−1⋅mol−1)(253.15 K)(30.07 g/mol))(103 g1 kg)=458 m⋅s−1

Hence vrms speed of C2H6 is 458 m⋅s−1.

(c)

Interpretation Introduction

Interpretation:

The value of vrms speed of C3H8 at −20 °C has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 3D.9E

Value of vrms for C3H8 is 378 m⋅s−1.

Explanation of Solution

Conversion factor to convert −20 °C to Kelvin is as follows:

T(K)=temperature in celsius+273.15=−20 °C+273.15=253.15 K

Substitute 253.15 K for T, 44.1 g/mol for M, and 8.3145 J⋅K−1⋅mol−1 for R in equation (1) to calculate vrms for C3H8.

vrms=(3(8.3145 J⋅K−1⋅mol−1)(253.15 K)(44.1 g/mol))(103 g1 kg)=378 m⋅s−1

Hence vrms speed of C3H8 is 378 m⋅s−1.

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Answer 2

Question

Chapter 3, Problem 3D.9E

(a)

Interpretation Introduction

Interpretation:

The value of vrms speed of CH4 at −20 °C has to be determined.

Concept Introduction:

Root mean square speed is square root of average value of square of molecular speeds of gas molecules. It includes molecular weight and temperature, both of which affect kinetic energy of gas. It is denoted by vrms. The expression for vrms is as follows:

vrms=3RTM (1)

Here,

R is gas constant.

T is absolute temperature of gas.

M is molecular weight of gas.

(a)

Expert Solution

Answer to Problem 3D.9E

Value of vrms of CH4 is 627 m⋅s−1.

Explanation of Solution

Conversion factor to convert −20 °C to Kelvin is as follows:

T(K)=temperature in celsius+273.15=−20 °C+273.15=253.15 K

Substitute 253.15 K for T, 16.04 g/mol for M, and 8.3145 J⋅K−1⋅mol−1 for R in equation (1) to calculate vrms for CH4.

vrms=(3(8.3145 J⋅K−1⋅mol−1)(253.15 K)(16.04 g/mol))(103 g1 kg)=627 m⋅s−1

Hence vrms speed of CH4 is 627 m⋅s−1.

(b)

Interpretation Introduction

Interpretation:

The value of vrms speed of C2H6 at −20 °C has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 3D.9E

Value of vrms for C2H6 is 458 m⋅s−1.

Explanation of Solution

Conversion factor to convert −20 °C to Kelvin is as follows:

T(K)=temperature in celsius+273.15=−20 °C+273.15=253.15 K

Substitute 253.15 K for T, 30.07 g/mol for M, and 8.3145 J⋅K−1⋅mol−1 for R in equation (1) to calculate vrms for C2H6.

vrms=(3(8.3145 J⋅K−1⋅mol−1)(253.15 K)(30.07 g/mol))(103 g1 kg)=458 m⋅s−1

Hence vrms speed of C2H6 is 458 m⋅s−1.

(c)

Interpretation Introduction

Interpretation:

The value of vrms speed of C3H8 at −20 °C has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 3D.9E

Value of vrms for C3H8 is 378 m⋅s−1.

Explanation of Solution

Conversion factor to convert −20 °C to Kelvin is as follows:

T(K)=temperature in celsius+273.15=−20 °C+273.15=253.15 K

Substitute 253.15 K for T, 44.1 g/mol for M, and 8.3145 J⋅K−1⋅mol−1 for R in equation (1) to calculate vrms for C3H8.

vrms=(3(8.3145 J⋅K−1⋅mol−1)(253.15 K)(44.1 g/mol))(103 g1 kg)=378 m⋅s−1

Hence vrms speed of C3H8 is 378 m⋅s−1.

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Answer 3

Question

Chapter 3, Problem 3D.9E

(a)

Interpretation Introduction

Interpretation:

The value of vrms speed of CH4 at −20 °C has to be determined.

Concept Introduction:

Root mean square speed is square root of average value of square of molecular speeds of gas molecules. It includes molecular weight and temperature, both of which affect kinetic energy of gas. It is denoted by vrms. The expression for vrms is as follows:

vrms=3RTM (1)

Here,

R is gas constant.

T is absolute temperature of gas.

M is molecular weight of gas.

(a)

Expert Solution

Answer to Problem 3D.9E

Value of vrms of CH4 is 627 m⋅s−1.

Explanation of Solution

Conversion factor to convert −20 °C to Kelvin is as follows:

T(K)=temperature in celsius+273.15=−20 °C+273.15=253.15 K

Substitute 253.15 K for T, 16.04 g/mol for M, and 8.3145 J⋅K−1⋅mol−1 for R in equation (1) to calculate vrms for CH4.

vrms=(3(8.3145 J⋅K−1⋅mol−1)(253.15 K)(16.04 g/mol))(103 g1 kg)=627 m⋅s−1

Hence vrms speed of CH4 is 627 m⋅s−1.

(b)

Interpretation Introduction

Interpretation:

The value of vrms speed of C2H6 at −20 °C has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 3D.9E

Value of vrms for C2H6 is 458 m⋅s−1.

Explanation of Solution

Conversion factor to convert −20 °C to Kelvin is as follows:

T(K)=temperature in celsius+273.15=−20 °C+273.15=253.15 K

Substitute 253.15 K for T, 30.07 g/mol for M, and 8.3145 J⋅K−1⋅mol−1 for R in equation (1) to calculate vrms for C2H6.

vrms=(3(8.3145 J⋅K−1⋅mol−1)(253.15 K)(30.07 g/mol))(103 g1 kg)=458 m⋅s−1

Hence vrms speed of C2H6 is 458 m⋅s−1.

(c)

Interpretation Introduction

Interpretation:

The value of vrms speed of C3H8 at −20 °C has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 3D.9E

Value of vrms for C3H8 is 378 m⋅s−1.

Explanation of Solution

Conversion factor to convert −20 °C to Kelvin is as follows:

T(K)=temperature in celsius+273.15=−20 °C+273.15=253.15 K

Substitute 253.15 K for T, 44.1 g/mol for M, and 8.3145 J⋅K−1⋅mol−1 for R in equation (1) to calculate vrms for C3H8.

vrms=(3(8.3145 J⋅K−1⋅mol−1)(253.15 K)(44.1 g/mol))(103 g1 kg)=378 m⋅s−1

Hence vrms speed of C3H8 is 378 m⋅s−1.

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Answer 4

Question

Chapter 3, Problem 3D.9E

(a)

Interpretation Introduction

Interpretation:

The value of vrms speed of CH4 at −20 °C has to be determined.

Concept Introduction:

Root mean square speed is square root of average value of square of molecular speeds of gas molecules. It includes molecular weight and temperature, both of which affect kinetic energy of gas. It is denoted by vrms. The expression for vrms is as follows:

vrms=3RTM (1)

Here,

R is gas constant.

T is absolute temperature of gas.

M is molecular weight of gas.

(a)

Expert Solution

Answer to Problem 3D.9E

Value of vrms of CH4 is 627 m⋅s−1.

Explanation of Solution

Conversion factor to convert −20 °C to Kelvin is as follows:

T(K)=temperature in celsius+273.15=−20 °C+273.15=253.15 K

Substitute 253.15 K for T, 16.04 g/mol for M, and 8.3145 J⋅K−1⋅mol−1 for R in equation (1) to calculate vrms for CH4.

vrms=(3(8.3145 J⋅K−1⋅mol−1)(253.15 K)(16.04 g/mol))(103 g1 kg)=627 m⋅s−1

Hence vrms speed of CH4 is 627 m⋅s−1.

(b)

Interpretation Introduction

Interpretation:

The value of vrms speed of C2H6 at −20 °C has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 3D.9E

Value of vrms for C2H6 is 458 m⋅s−1.

Explanation of Solution

Conversion factor to convert −20 °C to Kelvin is as follows:

T(K)=temperature in celsius+273.15=−20 °C+273.15=253.15 K

Substitute 253.15 K for T, 30.07 g/mol for M, and 8.3145 J⋅K−1⋅mol−1 for R in equation (1) to calculate vrms for C2H6.

vrms=(3(8.3145 J⋅K−1⋅mol−1)(253.15 K)(30.07 g/mol))(103 g1 kg)=458 m⋅s−1

Hence vrms speed of C2H6 is 458 m⋅s−1.

(c)

Interpretation Introduction

Interpretation:

The value of vrms speed of C3H8 at −20 °C has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 3D.9E

Value of vrms for C3H8 is 378 m⋅s−1.

Explanation of Solution

Conversion factor to convert −20 °C to Kelvin is as follows:

T(K)=temperature in celsius+273.15=−20 °C+273.15=253.15 K

Substitute 253.15 K for T, 44.1 g/mol for M, and 8.3145 J⋅K−1⋅mol−1 for R in equation (1) to calculate vrms for C3H8.

vrms=(3(8.3145 J⋅K−1⋅mol−1)(253.15 K)(44.1 g/mol))(103 g1 kg)=378 m⋅s−1

Hence vrms speed of C3H8 is 378 m⋅s−1.

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Answer 5

Chapter 3, Problem 3D.9E

(a)

Interpretation Introduction

Interpretation:

The value of vrms speed of CH4 at −20 °C has to be determined.

Concept Introduction:

Root mean square speed is square root of average value of square of molecular speeds of gas molecules. It includes molecular weight and temperature, both of which affect kinetic energy of gas. It is denoted by vrms. The expression for vrms is as follows:

vrms=3RTM (1)

Here,

R is gas constant.

T is absolute temperature of gas.

M is molecular weight of gas.

(a)

Expert Solution

Answer to Problem 3D.9E

Value of vrms of CH4 is 627 m⋅s−1.

Explanation of Solution

Conversion factor to convert −20 °C to Kelvin is as follows:

T(K)=temperature in celsius+273.15=−20 °C+273.15=253.15 K

Substitute 253.15 K for T, 16.04 g/mol for M, and 8.3145 J⋅K−1⋅mol−1 for R in equation (1) to calculate vrms for CH4.

vrms=(3(8.3145 J⋅K−1⋅mol−1)(253.15 K)(16.04 g/mol))(103 g1 kg)=627 m⋅s−1

Hence vrms speed of CH4 is 627 m⋅s−1.

(b)

Interpretation Introduction

Interpretation:

The value of vrms speed of C2H6 at −20 °C has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 3D.9E

Value of vrms for C2H6 is 458 m⋅s−1.

Explanation of Solution

Conversion factor to convert −20 °C to Kelvin is as follows:

T(K)=temperature in celsius+273.15=−20 °C+273.15=253.15 K

Substitute 253.15 K for T, 30.07 g/mol for M, and 8.3145 J⋅K−1⋅mol−1 for R in equation (1) to calculate vrms for C2H6.

vrms=(3(8.3145 J⋅K−1⋅mol−1)(253.15 K)(30.07 g/mol))(103 g1 kg)=458 m⋅s−1

Hence vrms speed of C2H6 is 458 m⋅s−1.

(c)

Interpretation Introduction

Interpretation:

The value of vrms speed of C3H8 at −20 °C has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 3D.9E

Value of vrms for C3H8 is 378 m⋅s−1.

Explanation of Solution

Conversion factor to convert −20 °C to Kelvin is as follows:

T(K)=temperature in celsius+273.15=−20 °C+273.15=253.15 K

Substitute 253.15 K for T, 44.1 g/mol for M, and 8.3145 J⋅K−1⋅mol−1 for R in equation (1) to calculate vrms for C3H8.

vrms=(3(8.3145 J⋅K−1⋅mol−1)(253.15 K)(44.1 g/mol))(103 g1 kg)=378 m⋅s−1

Hence vrms speed of C3H8 is 378 m⋅s−1.

Answer 6

Chapter 3, Problem 3D.9E

(a)

Interpretation Introduction

Interpretation:

The value of vrms speed of CH4 at −20 °C has to be determined.

Concept Introduction:

Root mean square speed is square root of average value of square of molecular speeds of gas molecules. It includes molecular weight and temperature, both of which affect kinetic energy of gas. It is denoted by vrms. The expression for vrms is as follows:

vrms=3RTM (1)

Here,

R is gas constant.

T is absolute temperature of gas.

M is molecular weight of gas.

(a)

Expert Solution

Answer to Problem 3D.9E

Value of vrms of CH4 is 627 m⋅s−1.

Explanation of Solution

Conversion factor to convert −20 °C to Kelvin is as follows:

T(K)=temperature in celsius+273.15=−20 °C+273.15=253.15 K

Substitute 253.15 K for T, 16.04 g/mol for M, and 8.3145 J⋅K−1⋅mol−1 for R in equation (1) to calculate vrms for CH4.

vrms=(3(8.3145 J⋅K−1⋅mol−1)(253.15 K)(16.04 g/mol))(103 g1 kg)=627 m⋅s−1

Hence vrms speed of CH4 is 627 m⋅s−1.

Answer 7

Chapter 3, Problem 3D.9E

(a)

Interpretation Introduction

Interpretation:

The value of vrms speed of CH4 at −20 °C has to be determined.

Concept Introduction:

Root mean square speed is square root of average value of square of molecular speeds of gas molecules. It includes molecular weight and temperature, both of which affect kinetic energy of gas. It is denoted by vrms. The expression for vrms is as follows:

vrms=3RTM (1)

Here,

R is gas constant.

T is absolute temperature of gas.

M is molecular weight of gas.

Answer 8

(a)

Expert Solution

Answer to Problem 3D.9E

Value of vrms of CH4 is 627 m⋅s−1.

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Conversion factor to convert −20 °C to Kelvin is as follows:

T(K)=temperature in celsius+273.15=−20 °C+273.15=253.15 K

Substitute 253.15 K for T, 16.04 g/mol for M, and 8.3145 J⋅K−1⋅mol−1 for R in equation (1) to calculate vrms for CH4.

vrms=(3(8.3145 J⋅K−1⋅mol−1)(253.15 K)(16.04 g/mol))(103 g1 kg)=627 m⋅s−1

Hence vrms speed of CH4 is 627 m⋅s−1.

Answer 13

(b)

Interpretation Introduction

Interpretation:

The value of vrms speed of C2H6 at −20 °C has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 3D.9E

Value of vrms for C2H6 is 458 m⋅s−1.

Explanation of Solution

Conversion factor to convert −20 °C to Kelvin is as follows:

T(K)=temperature in celsius+273.15=−20 °C+273.15=253.15 K

Substitute 253.15 K for T, 30.07 g/mol for M, and 8.3145 J⋅K−1⋅mol−1 for R in equation (1) to calculate vrms for C2H6.

vrms=(3(8.3145 J⋅K−1⋅mol−1)(253.15 K)(30.07 g/mol))(103 g1 kg)=458 m⋅s−1

Hence vrms speed of C2H6 is 458 m⋅s−1.

Answer 14

(b)

Interpretation Introduction

Interpretation:

The value of vrms speed of C2H6 at −20 °C has to be determined.

Concept Introduction:

Refer to part (a).

Answer 15

(b)

Expert Solution

Answer to Problem 3D.9E

Value of vrms for C2H6 is 458 m⋅s−1.

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Conversion factor to convert −20 °C to Kelvin is as follows:

T(K)=temperature in celsius+273.15=−20 °C+273.15=253.15 K

Substitute 253.15 K for T, 30.07 g/mol for M, and 8.3145 J⋅K−1⋅mol−1 for R in equation (1) to calculate vrms for C2H6.

vrms=(3(8.3145 J⋅K−1⋅mol−1)(253.15 K)(30.07 g/mol))(103 g1 kg)=458 m⋅s−1

Hence vrms speed of C2H6 is 458 m⋅s−1.

Answer 20

(c)

Interpretation Introduction

Interpretation:

The value of vrms speed of C3H8 at −20 °C has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 3D.9E

Value of vrms for C3H8 is 378 m⋅s−1.

Explanation of Solution

Conversion factor to convert −20 °C to Kelvin is as follows:

T(K)=temperature in celsius+273.15=−20 °C+273.15=253.15 K

Substitute 253.15 K for T, 44.1 g/mol for M, and 8.3145 J⋅K−1⋅mol−1 for R in equation (1) to calculate vrms for C3H8.

vrms=(3(8.3145 J⋅K−1⋅mol−1)(253.15 K)(44.1 g/mol))(103 g1 kg)=378 m⋅s−1

Hence vrms speed of C3H8 is 378 m⋅s−1.

Answer 21

(c)

Interpretation Introduction

Interpretation:

The value of vrms speed of C3H8 at −20 °C has to be determined.

Concept Introduction:

Refer to part (a).

Answer 22

(c)

Expert Solution

Answer to Problem 3D.9E

Value of vrms for C3H8 is 378 m⋅s−1.

Answer 23

(c)

Expert Solution

Answer 24

(c)

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

Conversion factor to convert −20 °C to Kelvin is as follows:

T(K)=temperature in celsius+273.15=−20 °C+273.15=253.15 K

Substitute 253.15 K for T, 44.1 g/mol for M, and 8.3145 J⋅K−1⋅mol−1 for R in equation (1) to calculate vrms for C3H8.

vrms=(3(8.3145 J⋅K−1⋅mol−1)(253.15 K)(44.1 g/mol))(103 g1 kg)=378 m⋅s−1

Hence vrms speed of C3H8 is 378 m⋅s−1.

Answer 27

Ch. 3 - Prob. 3A.1AST Ch. 3 - Prob. 3A.1BST Ch. 3 - Prob. 3A.2AST Ch. 3 - Prob. 3A.2BST Ch. 3 - Prob. 3A.3AST Ch. 3 - Prob. 3A.3BST Ch. 3 - Prob. 3A.1E Ch. 3 - Prob. 3A.2E Ch. 3 - Prob. 3A.3E Ch. 3 - Prob. 3A.4E

Concept explainers

Answer to Problem 3D.9E

Explanation of Solution

Interpretation:

The value of vrms speed of C2H6 at −20 °C has to be determined.

Concept Introduction:

Refer to part (a).

Answer to Problem 3D.9E

Explanation of Solution

Interpretation:

The value of vrms speed of C3H8 at −20 °C has to be determined.

Concept Introduction:

Refer to part (a).

Answer to Problem 3D.9E

Explanation of Solution

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Chapter 3 Solutions

Concept explainers

Answer to Problem 3D.9E

Explanation of Solution

Interpretation: The value of vrms speed of C2H6 at −20 °C has to be determined. Concept Introduction: Refer to part (a).

Answer to Problem 3D.9E

Explanation of Solution

Interpretation: The value of vrms speed of C3H8 at −20 °C has to be determined. Concept Introduction: Refer to part (a).

Answer to Problem 3D.9E

Explanation of Solution

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Chapter 3 Solutions

Interpretation:

The value of vrms speed of C2H6 at −20 °C has to be determined.

Concept Introduction:

Refer to part (a).

Interpretation:

The value of vrms speed of C3H8 at −20 °C has to be determined.

Concept Introduction:

Refer to part (a).