CHEMICAL PRINCIPLES (LL) W/ACCESS
7th Edition
ISBN: 9781319421175
Author: ATKINS
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Question
Chapter 3, Problem 3.24E
Interpretation Introduction
Interpretation:
Formation of inverse micelles has to be explained.
Concept Introduction:
Micelles are formed from aggregation molecules that have both polar and nonpolar part. In micelles, polar and ionic part forms outer part of micelle and nonpolar part gets inside outer part and form core of micelle.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Solve this
く
Predicting the pr
Predict the major products of the following organic reaction:
Δ
Some important notes:
• Draw the major product, or products, of the reaction in the drawing area below.
• If there aren't any products, because no reaction will take place, check the box below the drawing area instead.
• Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are
enantiomers.
?
Click and drag to start drawing a structure.
propose synthesis
Chapter 3 Solutions
CHEMICAL PRINCIPLES (LL) W/ACCESS
Ch. 3 - Prob. 3A.1ASTCh. 3 - Prob. 3A.1BSTCh. 3 - Prob. 3A.2ASTCh. 3 - Prob. 3A.2BSTCh. 3 - Prob. 3A.3ASTCh. 3 - Prob. 3A.3BSTCh. 3 - Prob. 3A.1ECh. 3 - Prob. 3A.2ECh. 3 - Prob. 3A.3ECh. 3 - Prob. 3A.4E
Ch. 3 - Prob. 3A.5ECh. 3 - Prob. 3A.6ECh. 3 - Prob. 3A.7ECh. 3 - Prob. 3A.8ECh. 3 - Prob. 3A.9ECh. 3 - Prob. 3A.10ECh. 3 - Prob. 3B.1ASTCh. 3 - Prob. 3B.1BSTCh. 3 - Prob. 3B.2ASTCh. 3 - Prob. 3B.2BSTCh. 3 - Prob. 3B.3ASTCh. 3 - Prob. 3B.3BSTCh. 3 - Prob. 3B.4ASTCh. 3 - Prob. 3B.4BSTCh. 3 - Prob. 3B.5ASTCh. 3 - Prob. 3B.5BSTCh. 3 - Prob. 3B.6ASTCh. 3 - Prob. 3B.6BSTCh. 3 - Prob. 3B.7ASTCh. 3 - Prob. 3B.7BSTCh. 3 - Prob. 3B.8ASTCh. 3 - Prob. 3B.8BSTCh. 3 - Prob. 3B.1ECh. 3 - Prob. 3B.2ECh. 3 - Prob. 3B.5ECh. 3 - Prob. 3B.6ECh. 3 - Prob. 3B.9ECh. 3 - Prob. 3B.10ECh. 3 - Prob. 3B.11ECh. 3 - Prob. 3B.12ECh. 3 - Prob. 3B.13ECh. 3 - Prob. 3B.14ECh. 3 - Prob. 3B.15ECh. 3 - Prob. 3B.16ECh. 3 - Prob. 3B.17ECh. 3 - Prob. 3B.18ECh. 3 - Prob. 3B.19ECh. 3 - Prob. 3B.20ECh. 3 - Prob. 3B.21ECh. 3 - Prob. 3B.22ECh. 3 - Prob. 3B.23ECh. 3 - Prob. 3B.24ECh. 3 - Prob. 3B.25ECh. 3 - Prob. 3B.26ECh. 3 - Prob. 3B.27ECh. 3 - Prob. 3B.28ECh. 3 - Prob. 3B.29ECh. 3 - Prob. 3B.30ECh. 3 - Prob. 3B.31ECh. 3 - Prob. 3B.32ECh. 3 - Prob. 3B.33ECh. 3 - Prob. 3B.34ECh. 3 - Prob. 3B.35ECh. 3 - Prob. 3B.36ECh. 3 - Prob. 3B.37ECh. 3 - Prob. 3B.38ECh. 3 - Prob. 3B.39ECh. 3 - Prob. 3B.40ECh. 3 - Prob. 3B.41ECh. 3 - Prob. 3B.42ECh. 3 - Prob. 3C.1ASTCh. 3 - Prob. 3C.1BSTCh. 3 - Prob. 3C.2ASTCh. 3 - Prob. 3C.2BSTCh. 3 - Prob. 3C.3ASTCh. 3 - Prob. 3C.3BSTCh. 3 - Prob. 3C.1ECh. 3 - Prob. 3C.2ECh. 3 - Prob. 3C.3ECh. 3 - Prob. 3C.4ECh. 3 - Prob. 3C.5ECh. 3 - Prob. 3C.6ECh. 3 - Prob. 3C.7ECh. 3 - Prob. 3C.8ECh. 3 - Prob. 3C.9ECh. 3 - Prob. 3C.10ECh. 3 - Prob. 3C.11ECh. 3 - Prob. 3C.12ECh. 3 - Prob. 3C.13ECh. 3 - Prob. 3C.14ECh. 3 - Prob. 3C.15ECh. 3 - Prob. 3C.16ECh. 3 - Prob. 3D.1ASTCh. 3 - Prob. 3D.1BSTCh. 3 - Prob. 3D.2ASTCh. 3 - Prob. 3D.2BSTCh. 3 - Prob. 3D.1ECh. 3 - Prob. 3D.2ECh. 3 - Prob. 3D.3ECh. 3 - Prob. 3D.4ECh. 3 - Prob. 3D.5ECh. 3 - Prob. 3D.6ECh. 3 - Prob. 3D.7ECh. 3 - Prob. 3D.8ECh. 3 - Prob. 3D.9ECh. 3 - Prob. 3D.10ECh. 3 - Prob. 3D.11ECh. 3 - Prob. 3D.12ECh. 3 - Prob. 3D.13ECh. 3 - Prob. 3D.14ECh. 3 - Prob. 3D.15ECh. 3 - Prob. 3D.16ECh. 3 - Prob. 3D.17ECh. 3 - Prob. 3D.18ECh. 3 - Prob. 3E.1ASTCh. 3 - Prob. 3E.1BSTCh. 3 - Prob. 3E.1ECh. 3 - Prob. 3E.2ECh. 3 - Prob. 3E.3ECh. 3 - Prob. 3E.4ECh. 3 - Prob. 3E.5ECh. 3 - Prob. 3E.6ECh. 3 - Prob. 3E.7ECh. 3 - Prob. 3E.8ECh. 3 - Prob. 3E.9ECh. 3 - Prob. 3E.10ECh. 3 - Prob. 3E.13ECh. 3 - Prob. 3E.14ECh. 3 - Prob. 3F.1ASTCh. 3 - Prob. 3F.1BSTCh. 3 - Prob. 3F.2ASTCh. 3 - Prob. 3F.2BSTCh. 3 - Prob. 3F.3ASTCh. 3 - Prob. 3F.3BSTCh. 3 - Prob. 3F.1ECh. 3 - Prob. 3F.2ECh. 3 - Prob. 3F.3ECh. 3 - Prob. 3F.4ECh. 3 - Prob. 3F.5ECh. 3 - Prob. 3F.6ECh. 3 - Prob. 3F.7ECh. 3 - Prob. 3F.8ECh. 3 - Prob. 3F.9ECh. 3 - Prob. 3F.10ECh. 3 - Prob. 3F.11ECh. 3 - Prob. 3F.12ECh. 3 - Prob. 3F.13ECh. 3 - Prob. 3F.14ECh. 3 - Prob. 3F.15ECh. 3 - Prob. 3F.16ECh. 3 - Prob. 3F.17ECh. 3 - Prob. 3F.18ECh. 3 - Prob. 3F.19ECh. 3 - Prob. 3F.20ECh. 3 - Prob. 3F.21ECh. 3 - Prob. 3F.22ECh. 3 - Prob. 3G.1ECh. 3 - Prob. 3G.2ECh. 3 - Prob. 3G.3ECh. 3 - Prob. 3G.4ECh. 3 - Prob. 3G.5ECh. 3 - Prob. 3G.6ECh. 3 - Prob. 3G.7ECh. 3 - Prob. 3G.8ECh. 3 - Prob. 3G.9ECh. 3 - Prob. 3G.10ECh. 3 - Prob. 3G.11ECh. 3 - Prob. 3G.12ECh. 3 - Prob. 3G.13ECh. 3 - Prob. 3G.14ECh. 3 - Prob. 3G.15ECh. 3 - Prob. 3G.16ECh. 3 - Prob. 3G.17ECh. 3 - Prob. 3G.18ECh. 3 - Prob. 3H.1ASTCh. 3 - Prob. 3H.1BSTCh. 3 - Prob. 3H.2ASTCh. 3 - Prob. 3H.2BSTCh. 3 - Prob. 3H.3ASTCh. 3 - Prob. 3H.3BSTCh. 3 - Prob. 3H.4ASTCh. 3 - Prob. 3H.4BSTCh. 3 - Prob. 3H.5ASTCh. 3 - Prob. 3H.5BSTCh. 3 - Prob. 3H.1ECh. 3 - Prob. 3H.2ECh. 3 - Prob. 3H.3ECh. 3 - Prob. 3H.4ECh. 3 - Prob. 3H.5ECh. 3 - Prob. 3H.6ECh. 3 - Prob. 3H.7ECh. 3 - Prob. 3H.8ECh. 3 - Prob. 3H.9ECh. 3 - Prob. 3H.10ECh. 3 - Prob. 3H.11ECh. 3 - Prob. 3H.12ECh. 3 - Prob. 3H.13ECh. 3 - Prob. 3H.14ECh. 3 - Prob. 3H.15ECh. 3 - Prob. 3H.16ECh. 3 - Prob. 3H.17ECh. 3 - Prob. 3H.19ECh. 3 - Prob. 3H.20ECh. 3 - Prob. 3H.23ECh. 3 - Prob. 3H.24ECh. 3 - Prob. 3H.25ECh. 3 - Prob. 3H.26ECh. 3 - Prob. 3H.27ECh. 3 - Prob. 3H.28ECh. 3 - Prob. 3H.29ECh. 3 - Prob. 3H.30ECh. 3 - Prob. 3H.31ECh. 3 - Prob. 3H.32ECh. 3 - Prob. 3H.33ECh. 3 - Prob. 3H.34ECh. 3 - Prob. 3H.35ECh. 3 - Prob. 3H.36ECh. 3 - Prob. 3I.1ASTCh. 3 - Prob. 3I.1BSTCh. 3 - Prob. 3I.2ASTCh. 3 - Prob. 3I.2BSTCh. 3 - Prob. 3I.3ASTCh. 3 - Prob. 3I.3BSTCh. 3 - Prob. 3I.4ASTCh. 3 - Prob. 3I.4BSTCh. 3 - Prob. 3I.1ECh. 3 - Prob. 3I.2ECh. 3 - Prob. 3I.3ECh. 3 - Prob. 3I.4ECh. 3 - Prob. 3I.5ECh. 3 - Prob. 3I.6ECh. 3 - Prob. 3I.7ECh. 3 - Prob. 3I.8ECh. 3 - Prob. 3I.11ECh. 3 - Prob. 3I.12ECh. 3 - Prob. 3I.13ECh. 3 - Prob. 3I.14ECh. 3 - Prob. 3I.15ECh. 3 - Prob. 3I.16ECh. 3 - Prob. 3J.1ASTCh. 3 - Prob. 3J.1BSTCh. 3 - Prob. 3J.2ASTCh. 3 - Prob. 3J.2BSTCh. 3 - Prob. 3J.3ASTCh. 3 - Prob. 3J.3BSTCh. 3 - Prob. 3J.1ECh. 3 - Prob. 3J.2ECh. 3 - Prob. 3J.3ECh. 3 - Prob. 3J.4ECh. 3 - Prob. 3J.5ECh. 3 - Prob. 3J.6ECh. 3 - Prob. 3J.7ECh. 3 - Prob. 3J.8ECh. 3 - Prob. 3J.9ECh. 3 - Prob. 3J.10ECh. 3 - Prob. 3J.11ECh. 3 - Prob. 3J.12ECh. 3 - Prob. 3J.13ECh. 3 - Prob. 3J.14ECh. 3 - Prob. 3J.15ECh. 3 - Prob. 3J.16ECh. 3 - Prob. 3.1ECh. 3 - Prob. 3.2ECh. 3 - Prob. 3.3ECh. 3 - Prob. 3.4ECh. 3 - Prob. 3.5ECh. 3 - Prob. 3.6ECh. 3 - Prob. 3.7ECh. 3 - Prob. 3.8ECh. 3 - Prob. 3.9ECh. 3 - Prob. 3.10ECh. 3 - Prob. 3.11ECh. 3 - Prob. 3.12ECh. 3 - Prob. 3.13ECh. 3 - Prob. 3.15ECh. 3 - Prob. 3.18ECh. 3 - Prob. 3.19ECh. 3 - Prob. 3.23ECh. 3 - Prob. 3.24ECh. 3 - Prob. 3.25ECh. 3 - Prob. 3.26ECh. 3 - Prob. 3.27ECh. 3 - Prob. 3.29ECh. 3 - Prob. 3.31ECh. 3 - Prob. 3.32ECh. 3 - Prob. 3.35ECh. 3 - Prob. 3.36ECh. 3 - Prob. 3.37ECh. 3 - Prob. 3.38ECh. 3 - Prob. 3.40ECh. 3 - Prob. 3.41ECh. 3 - Prob. 3.42ECh. 3 - Prob. 3.45ECh. 3 - Prob. 3.47ECh. 3 - Prob. 3.49ECh. 3 - Prob. 3.50ECh. 3 - Prob. 3.51ECh. 3 - Prob. 3.53ECh. 3 - Prob. 3.54ECh. 3 - Prob. 3.55ECh. 3 - Prob. 3.56ECh. 3 - Prob. 3.57ECh. 3 - Prob. 3.58ECh. 3 - Prob. 3.59ECh. 3 - Prob. 3.60ECh. 3 - Prob. 3.61ECh. 3 - Prob. 3.62ECh. 3 - Prob. 3.63ECh. 3 - Prob. 3.64ECh. 3 - Prob. 3.65ECh. 3 - Prob. 3.66ECh. 3 - Prob. 3.67ECh. 3 - Prob. 3.68E
Knowledge Booster
Similar questions
- Explanation O Conjugated Pi Systems Deducing the reactants of a Diels-Alder reaction Can the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? Δ If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. • If your answer is no, check the box under the drawing area instead. Click and drag to start drawing a structure. Xarrow_forwardDiels Alder Cycloaddition: Focus on regiochemistry (problems E-F) –> match + of thedienophile and - of the diene while also considering stereochemistry (endo).arrow_forwardHELP! URGENT! PLEASE RESOND ASAP!arrow_forward
- Question 4 Determine the rate order and rate constant for sucrose hydrolysis. Time (hours) [C6H12O6] 0 0.501 0.500 0.451 1.00 0.404 1.50 0.363 3.00 0.267 First-order, k = 0.210 hour 1 First-order, k = 0.0912 hour 1 O Second-order, k = 0.590 M1 hour 1 O Zero-order, k = 0.0770 M/hour O Zero-order, k = 0.4896 M/hour O Second-order, k = 1.93 M-1-hour 1 10 ptsarrow_forwardDetermine the rate order and rate constant for sucrose hydrolysis. Time (hours) [C6H12O6] 0 0.501 0.500 0.451 1.00 0.404 1.50 0.363 3.00 0.267arrow_forwardDraw the products of the reaction shown below. Use wedge and dash bonds to indicate stereochemistry. Ignore inorganic byproducts. OSO4 (cat) (CH3)3COOH Select to Draw ઘarrow_forward
- Calculate the reaction rate for selenious acid, H2SeO3, if 0.1150 M I-1 decreases to 0.0770 M in 12.0 minutes. H2SeO3(aq) + 6I-1(aq) + 4H+1(aq) ⟶ Se(s) + 2I3-1(aq) + 3H2O(l)arrow_forwardProblem 5-31 Which of the following objects are chiral? (a) A basketball (d) A golf club (b) A fork (c) A wine glass (e) A spiral staircase (f) A snowflake Problem 5-32 Which of the following compounds are chiral? Draw them, and label the chirality centers. (a) 2,4-Dimethylheptane (b) 5-Ethyl-3,3-dimethylheptane (c) cis-1,4-Dichlorocyclohexane Problem 5-33 Draw chiral molecules that meet the following descriptions: (a) A chloroalkane, C5H11Cl (c) An alkene, C6H12 (b) An alcohol, C6H140 (d) An alkane, C8H18 Problem 5-36 Erythronolide B is the biological precursor of erythromycin, a broad-spectrum antibiotic. How H3C CH3 many chirality centers does erythronolide B have? OH Identify them. H3C -CH3 OH Erythronolide B H3C. H3C. OH OH CH3arrow_forwardPLEASE HELP! URGENT! PLEASE RESPOND!arrow_forward
- 2. Propose a mechanism for this reaction. ہلی سے ملی N H (excess)arrow_forwardSteps and explanationn please.arrow_forwardProblem 5-48 Assign R or S configurations to the chirality centers in ascorbic acid (vitamin C). OH H OH HO CH2OH Ascorbic acid O H Problem 5-49 Assign R or S stereochemistry to the chirality centers in the following Newman projections: H Cl H CH3 H3C. OH H3C (a) H H H3C (b) CH3 H Problem 5-52 Draw the meso form of each of the following molecules, and indicate the plane of symmetry in each: OH OH (a) CH3CHCH2CH2CHCH3 CH3 H3C. -OH (c) H3C CH3 (b) Problem 5-66 Assign R or S configurations to the chiral centers in cephalexin, trade-named Keflex, the most widely prescribed antibiotic in the United States. H2N H IHH S Cephalexin N. CH3 CO₂Harrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning
Introductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
Introductory Chemistry: An Active Learning Approa...
Chemistry
ISBN:9781305079250
Author:Mark S. Cracolice, Ed Peters
Publisher:Cengage Learning