CHEMICAL PRINCIPLES (LL) W/ACCESS
7th Edition
ISBN: 9781319421175
Author: ATKINS
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 3, Problem 3D.2E
Interpretation Introduction
Interpretation:
The reason for change in frequency of collisions of molecules of gas with walls of container as volume decreases at constant temperature has to be explained.
Concept Introduction:
Kinetic model of gas explains effusion behavior of gases and accounts for
(1) Gas has bunch of molecules in endless random motion.
(2) The gas molecules are considered as extremely small points.
(3) Molecules continuously move in single directions until they collide.
(4) Molecules don’t interact with one another until they collide.
(5) All collisions are considered as elastic.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Find the pH of a 0.120 M solution of HNO2.
Find the pH ignoring activity effects (i.e., the normal way).
Find the pH in a solution of 0.050 M NaCl, including activity
Please help me answer these three questions. Required info should be in data table.
Draw the major organic substitution product or products for (2R,3S)-2-bromo-3-methylpentane reacting with the given
nucleophile. Clearly drawn the stereochemistry, including a wedged bond, a dashed bond and two in-plane bonds at each
stereogenic center. Omit any byproducts.
Bri
CH3CH2O-
(conc.)
Draw the major organic product or products.
Chapter 3 Solutions
CHEMICAL PRINCIPLES (LL) W/ACCESS
Ch. 3 - Prob. 3A.1ASTCh. 3 - Prob. 3A.1BSTCh. 3 - Prob. 3A.2ASTCh. 3 - Prob. 3A.2BSTCh. 3 - Prob. 3A.3ASTCh. 3 - Prob. 3A.3BSTCh. 3 - Prob. 3A.1ECh. 3 - Prob. 3A.2ECh. 3 - Prob. 3A.3ECh. 3 - Prob. 3A.4E
Ch. 3 - Prob. 3A.5ECh. 3 - Prob. 3A.6ECh. 3 - Prob. 3A.7ECh. 3 - Prob. 3A.8ECh. 3 - Prob. 3A.9ECh. 3 - Prob. 3A.10ECh. 3 - Prob. 3B.1ASTCh. 3 - Prob. 3B.1BSTCh. 3 - Prob. 3B.2ASTCh. 3 - Prob. 3B.2BSTCh. 3 - Prob. 3B.3ASTCh. 3 - Prob. 3B.3BSTCh. 3 - Prob. 3B.4ASTCh. 3 - Prob. 3B.4BSTCh. 3 - Prob. 3B.5ASTCh. 3 - Prob. 3B.5BSTCh. 3 - Prob. 3B.6ASTCh. 3 - Prob. 3B.6BSTCh. 3 - Prob. 3B.7ASTCh. 3 - Prob. 3B.7BSTCh. 3 - Prob. 3B.8ASTCh. 3 - Prob. 3B.8BSTCh. 3 - Prob. 3B.1ECh. 3 - Prob. 3B.2ECh. 3 - Prob. 3B.5ECh. 3 - Prob. 3B.6ECh. 3 - Prob. 3B.9ECh. 3 - Prob. 3B.10ECh. 3 - Prob. 3B.11ECh. 3 - Prob. 3B.12ECh. 3 - Prob. 3B.13ECh. 3 - Prob. 3B.14ECh. 3 - Prob. 3B.15ECh. 3 - Prob. 3B.16ECh. 3 - Prob. 3B.17ECh. 3 - Prob. 3B.18ECh. 3 - Prob. 3B.19ECh. 3 - Prob. 3B.20ECh. 3 - Prob. 3B.21ECh. 3 - Prob. 3B.22ECh. 3 - Prob. 3B.23ECh. 3 - Prob. 3B.24ECh. 3 - Prob. 3B.25ECh. 3 - Prob. 3B.26ECh. 3 - Prob. 3B.27ECh. 3 - Prob. 3B.28ECh. 3 - Prob. 3B.29ECh. 3 - Prob. 3B.30ECh. 3 - Prob. 3B.31ECh. 3 - Prob. 3B.32ECh. 3 - Prob. 3B.33ECh. 3 - Prob. 3B.34ECh. 3 - Prob. 3B.35ECh. 3 - Prob. 3B.36ECh. 3 - Prob. 3B.37ECh. 3 - Prob. 3B.38ECh. 3 - Prob. 3B.39ECh. 3 - Prob. 3B.40ECh. 3 - Prob. 3B.41ECh. 3 - Prob. 3B.42ECh. 3 - Prob. 3C.1ASTCh. 3 - Prob. 3C.1BSTCh. 3 - Prob. 3C.2ASTCh. 3 - Prob. 3C.2BSTCh. 3 - Prob. 3C.3ASTCh. 3 - Prob. 3C.3BSTCh. 3 - Prob. 3C.1ECh. 3 - Prob. 3C.2ECh. 3 - Prob. 3C.3ECh. 3 - Prob. 3C.4ECh. 3 - Prob. 3C.5ECh. 3 - Prob. 3C.6ECh. 3 - Prob. 3C.7ECh. 3 - Prob. 3C.8ECh. 3 - Prob. 3C.9ECh. 3 - Prob. 3C.10ECh. 3 - Prob. 3C.11ECh. 3 - Prob. 3C.12ECh. 3 - Prob. 3C.13ECh. 3 - Prob. 3C.14ECh. 3 - Prob. 3C.15ECh. 3 - Prob. 3C.16ECh. 3 - Prob. 3D.1ASTCh. 3 - Prob. 3D.1BSTCh. 3 - Prob. 3D.2ASTCh. 3 - Prob. 3D.2BSTCh. 3 - Prob. 3D.1ECh. 3 - Prob. 3D.2ECh. 3 - Prob. 3D.3ECh. 3 - Prob. 3D.4ECh. 3 - Prob. 3D.5ECh. 3 - Prob. 3D.6ECh. 3 - Prob. 3D.7ECh. 3 - Prob. 3D.8ECh. 3 - Prob. 3D.9ECh. 3 - Prob. 3D.10ECh. 3 - Prob. 3D.11ECh. 3 - Prob. 3D.12ECh. 3 - Prob. 3D.13ECh. 3 - Prob. 3D.14ECh. 3 - Prob. 3D.15ECh. 3 - Prob. 3D.16ECh. 3 - Prob. 3D.17ECh. 3 - Prob. 3D.18ECh. 3 - Prob. 3E.1ASTCh. 3 - Prob. 3E.1BSTCh. 3 - Prob. 3E.1ECh. 3 - Prob. 3E.2ECh. 3 - Prob. 3E.3ECh. 3 - Prob. 3E.4ECh. 3 - Prob. 3E.5ECh. 3 - Prob. 3E.6ECh. 3 - Prob. 3E.7ECh. 3 - Prob. 3E.8ECh. 3 - Prob. 3E.9ECh. 3 - Prob. 3E.10ECh. 3 - Prob. 3E.13ECh. 3 - Prob. 3E.14ECh. 3 - Prob. 3F.1ASTCh. 3 - Prob. 3F.1BSTCh. 3 - Prob. 3F.2ASTCh. 3 - Prob. 3F.2BSTCh. 3 - Prob. 3F.3ASTCh. 3 - Prob. 3F.3BSTCh. 3 - Prob. 3F.1ECh. 3 - Prob. 3F.2ECh. 3 - Prob. 3F.3ECh. 3 - Prob. 3F.4ECh. 3 - Prob. 3F.5ECh. 3 - Prob. 3F.6ECh. 3 - Prob. 3F.7ECh. 3 - Prob. 3F.8ECh. 3 - Prob. 3F.9ECh. 3 - Prob. 3F.10ECh. 3 - Prob. 3F.11ECh. 3 - Prob. 3F.12ECh. 3 - Prob. 3F.13ECh. 3 - Prob. 3F.14ECh. 3 - Prob. 3F.15ECh. 3 - Prob. 3F.16ECh. 3 - Prob. 3F.17ECh. 3 - Prob. 3F.18ECh. 3 - Prob. 3F.19ECh. 3 - Prob. 3F.20ECh. 3 - Prob. 3F.21ECh. 3 - Prob. 3F.22ECh. 3 - Prob. 3G.1ECh. 3 - Prob. 3G.2ECh. 3 - Prob. 3G.3ECh. 3 - Prob. 3G.4ECh. 3 - Prob. 3G.5ECh. 3 - Prob. 3G.6ECh. 3 - Prob. 3G.7ECh. 3 - Prob. 3G.8ECh. 3 - Prob. 3G.9ECh. 3 - Prob. 3G.10ECh. 3 - Prob. 3G.11ECh. 3 - Prob. 3G.12ECh. 3 - Prob. 3G.13ECh. 3 - Prob. 3G.14ECh. 3 - Prob. 3G.15ECh. 3 - Prob. 3G.16ECh. 3 - Prob. 3G.17ECh. 3 - Prob. 3G.18ECh. 3 - Prob. 3H.1ASTCh. 3 - Prob. 3H.1BSTCh. 3 - Prob. 3H.2ASTCh. 3 - Prob. 3H.2BSTCh. 3 - Prob. 3H.3ASTCh. 3 - Prob. 3H.3BSTCh. 3 - Prob. 3H.4ASTCh. 3 - Prob. 3H.4BSTCh. 3 - Prob. 3H.5ASTCh. 3 - Prob. 3H.5BSTCh. 3 - Prob. 3H.1ECh. 3 - Prob. 3H.2ECh. 3 - Prob. 3H.3ECh. 3 - Prob. 3H.4ECh. 3 - Prob. 3H.5ECh. 3 - Prob. 3H.6ECh. 3 - Prob. 3H.7ECh. 3 - Prob. 3H.8ECh. 3 - Prob. 3H.9ECh. 3 - Prob. 3H.10ECh. 3 - Prob. 3H.11ECh. 3 - Prob. 3H.12ECh. 3 - Prob. 3H.13ECh. 3 - Prob. 3H.14ECh. 3 - Prob. 3H.15ECh. 3 - Prob. 3H.16ECh. 3 - Prob. 3H.17ECh. 3 - Prob. 3H.19ECh. 3 - Prob. 3H.20ECh. 3 - Prob. 3H.23ECh. 3 - Prob. 3H.24ECh. 3 - Prob. 3H.25ECh. 3 - Prob. 3H.26ECh. 3 - Prob. 3H.27ECh. 3 - Prob. 3H.28ECh. 3 - Prob. 3H.29ECh. 3 - Prob. 3H.30ECh. 3 - Prob. 3H.31ECh. 3 - Prob. 3H.32ECh. 3 - Prob. 3H.33ECh. 3 - Prob. 3H.34ECh. 3 - Prob. 3H.35ECh. 3 - Prob. 3H.36ECh. 3 - Prob. 3I.1ASTCh. 3 - Prob. 3I.1BSTCh. 3 - Prob. 3I.2ASTCh. 3 - Prob. 3I.2BSTCh. 3 - Prob. 3I.3ASTCh. 3 - Prob. 3I.3BSTCh. 3 - Prob. 3I.4ASTCh. 3 - Prob. 3I.4BSTCh. 3 - Prob. 3I.1ECh. 3 - Prob. 3I.2ECh. 3 - Prob. 3I.3ECh. 3 - Prob. 3I.4ECh. 3 - Prob. 3I.5ECh. 3 - Prob. 3I.6ECh. 3 - Prob. 3I.7ECh. 3 - Prob. 3I.8ECh. 3 - Prob. 3I.11ECh. 3 - Prob. 3I.12ECh. 3 - Prob. 3I.13ECh. 3 - Prob. 3I.14ECh. 3 - Prob. 3I.15ECh. 3 - Prob. 3I.16ECh. 3 - Prob. 3J.1ASTCh. 3 - Prob. 3J.1BSTCh. 3 - Prob. 3J.2ASTCh. 3 - Prob. 3J.2BSTCh. 3 - Prob. 3J.3ASTCh. 3 - Prob. 3J.3BSTCh. 3 - Prob. 3J.1ECh. 3 - Prob. 3J.2ECh. 3 - Prob. 3J.3ECh. 3 - Prob. 3J.4ECh. 3 - Prob. 3J.5ECh. 3 - Prob. 3J.6ECh. 3 - Prob. 3J.7ECh. 3 - Prob. 3J.8ECh. 3 - Prob. 3J.9ECh. 3 - Prob. 3J.10ECh. 3 - Prob. 3J.11ECh. 3 - Prob. 3J.12ECh. 3 - Prob. 3J.13ECh. 3 - Prob. 3J.14ECh. 3 - Prob. 3J.15ECh. 3 - Prob. 3J.16ECh. 3 - Prob. 3.1ECh. 3 - Prob. 3.2ECh. 3 - Prob. 3.3ECh. 3 - Prob. 3.4ECh. 3 - Prob. 3.5ECh. 3 - Prob. 3.6ECh. 3 - Prob. 3.7ECh. 3 - Prob. 3.8ECh. 3 - Prob. 3.9ECh. 3 - Prob. 3.10ECh. 3 - Prob. 3.11ECh. 3 - Prob. 3.12ECh. 3 - Prob. 3.13ECh. 3 - Prob. 3.15ECh. 3 - Prob. 3.18ECh. 3 - Prob. 3.19ECh. 3 - Prob. 3.23ECh. 3 - Prob. 3.24ECh. 3 - Prob. 3.25ECh. 3 - Prob. 3.26ECh. 3 - Prob. 3.27ECh. 3 - Prob. 3.29ECh. 3 - Prob. 3.31ECh. 3 - Prob. 3.32ECh. 3 - Prob. 3.35ECh. 3 - Prob. 3.36ECh. 3 - Prob. 3.37ECh. 3 - Prob. 3.38ECh. 3 - Prob. 3.40ECh. 3 - Prob. 3.41ECh. 3 - Prob. 3.42ECh. 3 - Prob. 3.45ECh. 3 - Prob. 3.47ECh. 3 - Prob. 3.49ECh. 3 - Prob. 3.50ECh. 3 - Prob. 3.51ECh. 3 - Prob. 3.53ECh. 3 - Prob. 3.54ECh. 3 - Prob. 3.55ECh. 3 - Prob. 3.56ECh. 3 - Prob. 3.57ECh. 3 - Prob. 3.58ECh. 3 - Prob. 3.59ECh. 3 - Prob. 3.60ECh. 3 - Prob. 3.61ECh. 3 - Prob. 3.62ECh. 3 - Prob. 3.63ECh. 3 - Prob. 3.64ECh. 3 - Prob. 3.65ECh. 3 - Prob. 3.66ECh. 3 - Prob. 3.67ECh. 3 - Prob. 3.68E
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Tartaric acid (C4H6O6) is a diprotic weak acid. A sample of 875 mg tartaric acid are dissolved in 100 mL water and titrated with 0.994 M NaOH. How many mL of NaOH are needed to reach the first equivalence point? How many mL of NaOH are needed to reach the second equivalence point?arrow_forwardIncluding activity, calculate the solubility of Pb(IO3)2 in a matrix of 0.020 M Mg(NO3)2.arrow_forwardIncluding activity coefficients, find [Hg22+] in saturated Hg2Br2 in 0.00100 M KBr.arrow_forward
- Including activity, calculate the pH of a 0.010 M HCl solution with an ionic strength of 0.10 M.arrow_forwardCan I please get the graph 1: Concentration vs. Density?arrow_forwardOrder the following series of compounds from highest to lowest reactivity to electrophilic aromatic substitution, explaining your answer: 2-nitrophenol, p-Toluidine, N-(4-methylphenyl)acetamide, 4-methylbenzonitrile, 4-(trifluoromethyl)benzonitrile.arrow_forward
- Ordene la siguiente serie de compuestos de mayor a menor reactividad a la sustitución aromática electrofílica, explicando su respuesta: ácido bencenosulfónico, fluorobenceno, etilbenceno, clorobenceno, terc-butilbenceno, acetofenona.arrow_forwardCan I please get all final concentrations please!arrow_forwardState the detailed mechanism of the reaction of benzene with isopropanol in sulfuric acid.arrow_forward
- Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction. For the decomposition reaction of N2O5(g): 2 N2O5(g) · 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 -> NO2 + NO3_(K1) NO2 + NO3 →> N2O5 (k-1) → NO2 + NO3 → NO2 + O2 + NO (K2) NO + N2O5 → NO2 + NO2 + NO2 (K3) Give the expression for the acceptable rate. (A). d[N₂O] dt = -1 2k,k₂[N205] k₁+k₂ d[N₂O5] (B). dt =-k₁[N₂O₂] + k₁[NO2][NO3] - k₂[NO2]³ (C). d[N₂O] dt =-k₁[N₂O] + k₁[N205] - K3 [NO] [N205] (D). d[N2O5] =-k₁[NO] - K3[NO] [N₂05] dtarrow_forwardA 0.10 M solution of acetic acid (CH3COOH, Ka = 1.8 x 10^-5) is titrated with a 0.0250 M solution of magnesium hydroxide (Mg(OH)2). If 10.0 mL of the acid solution is titrated with 20.0 mL of the base solution, what is the pH of the resulting solution?arrow_forwardFor the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3) → Give the expression for the acceptable rate. → → (A). d[N205] dt == 2k,k₂[N₂O₂] k₁+k₁₂ (B). d[N2O5] =-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³ dt (C). d[N2O5] =-k₁[N₂O] + k [NO] - k₂[NO] [NO] d[N2O5] (D). = dt = -k₁[N2O5] - k¸[NO][N₂05] dt Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Chemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage Learning
World of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage Learning
Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
Chemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
Chemistry for Engineering Students
Chemistry
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Cengage Learning
World of Chemistry, 3rd edition
Chemistry
ISBN:9781133109655
Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:Brooks / Cole / Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chemistry: An Atoms First Approach
Chemistry
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Cengage Learning