Chapter 3, Problem 3.95P

Interpretation Introduction

Interpretation:

The mass(g) of chloromethane $\left({\text{CH}}_3\text{Cl}\right)$ formed by reaction of $20.5\text{ g}$ methane and $45.0\text{ g}$ chlorine with yield percentof $75.0\%$ is to be calculated.

Concept introduction:

The formula to calculate moles is as follows:

$\text{Amount}\left(\text{mol}\right)=\frac{\text{mass}}{\text{molecular mass}}$ (1)

Stoichiometry gives the quantitative relationship between the reactants and products of the chemical reaction. It helps in the calculation of the percentage yield of the product of any chemical reaction.

Theoretical yield is defined as the expected amount of product obtained during a reaction. Actual yield is the amount of substance obtained experimentally during the reaction. Percent yield indicates how much of the product is obtained from a reaction. The expression to calculate the percent yield is as follows:

The formula to calculate % yield is as follows:

$\%\text{ yield}=\left(\frac{\text{actual yield}}{\text{theoretical yield}}\right)\left(100\text{ \%}\right)$ (2)