OWLv2 for Bettelheim/Brown/Campbell/Farrell/Torres' Introduction to General, Organic and Biochemistry, 11th Edition, [Instant Access], 1 term (6 months)
OWLv2 for Bettelheim/Brown/Campbell/Farrell/Torres' Introduction to General, Organic and Biochemistry, 11th Edition, [Instant Access], 1 term (6 months)
11th Edition
ISBN: 9781305106734
Author: Frederick A. Bettelheim; William H. Brown; Mary K. Campbell; Shawn O. Farrell; Omar Torres
Publisher: Cengage Learning US
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Chapter 3, Problem 3.84P
Interpretation Introduction

(a)

Interpretation:

The shape of the following ion should be predicted:

NO2

Concept Introduction:

The shape of molecule is determined by electron density around central atom as it is suggested by VSEPR theory.

According to VSEPR theory we can determine the shape of a molecule by following the given steps.

  1. First identify the number of bonded atoms to the central atom and count the number of lone pair of electrons on central atom. Add these.
  2. The sum obtained above gives us idea about the electronic geometry in a molecule. For example, if it is two then the electron geometry will be linear, if it is three the geometry will be trigonal planar, four the geometry will be tetrahedral, five the geometry will be trigonal bipyramidal, six the geometry will be octahedral.
  3. Now for molecular geometry we have to consider the number of lone pair of electrons.
  4. The molecular geometry depends upon the repulsion order between electron pairs which is
Bond-bond < lone pair −bond pair < lone pair-lone pair.

Interpretation Introduction

(b)

Interpretation:

The shape of the following ion should be predicted:

NH4+

Concept Introduction:

The shape of molecule is determined by electron density around central atom as it is suggested by VSEPR theory.

According to VSEPR theory we can determine the shape of a molecule by following the given steps.

  1. First identify the number of bonded atoms to the central atom and count the number of lone pair of electrons on central atom. Add these.
  2. The sum obtained above gives us idea about the electronic geometry in a molecule. For example, if it is two then the electron geometry will be linear, if it is three the geometry will be trigonal planar, four the geometry will be tetrahedral, five the geometry will be trigonal bipyramidal, six the geometry will be octahedral.
  3. Now for molecular geometry we must consider the number of lone pair of electrons.
  4. The molecular geometry depends upon the repulsion order between electron pairs which is
Bond-bond < lone pair −bond pair < lone pair-lone pair.

Interpretation Introduction

(b)

Interpretation:

The shape of the following ion should be predicted:

CO32

Concept Introduction:

The shape of molecule is determined by electron density around central atom as it is suggested by VSEPR theory.

According to VSEPR theory we can determine the shape of a molecule by following the given steps.

  1. First identify the number of bonded atoms to the central atom and count the number of lone pair of electrons on central atom. Add these.
  2. The sum obtained above gives us idea about the electronic geometry in a molecule. For example, if it is two then the electron geometry will be linear, if it is three the geometry will be trigonal planar, four the geometry will be tetrahedral, five the geometry will be trigonal bipyramidal, six the geometry will be octahedral.
  3. Now for molecular geometry we must consider the number of lone pair of electrons.
  4. The molecular geometry depends upon the repulsion order between electron pairs which is
Bond-bond < lone pair −bond pair < lone pair-lone pair.

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Chapter 3 Solutions

OWLv2 for Bettelheim/Brown/Campbell/Farrell/Torres' Introduction to General, Organic and Biochemistry, 11th Edition, [Instant Access], 1 term (6 months)

Ch. 3.7 - Prob. 3.11PCh. 3.8 - Prob. 3.12PCh. 3.9 - Prob. 3.13PCh. 3.9 - Prob. 3.14PCh. 3.10 - Problem 3-15 Predict all bond angles for these...Ch. 3.11 - Problem 3-16 Which of these molecules are polar?...Ch. 3 - 3-17 Answer true or false. (a) The octet rule...Ch. 3 - 3-18 How many electrons must each atom gain or...Ch. 3 - 3-19 Show how each chemical change obeys the octet...Ch. 3 - 3-20 Show how each chemical change obeys the octet...Ch. 3 - 3-21 Write the formula for the most stable ion...Ch. 3 - 3-22 Why is Li- not a stable ion?Ch. 3 - 3-23 Predict which ions are stable: (a) (b) (c)...Ch. 3 - 3-24 Predict which ions are stable: (a) Br2- (b)...Ch. 3 - 3-25 Why are carbon and silicon reluctant to form...Ch. 3 - 3-26 Table 3-2 shows the following ions of copper:...Ch. 3 - 3-27 Answer true or false. (a) For Group lA and...Ch. 3 - 3-28 Name each polyatomic ion. (a) HCO3- (b) NO2-...Ch. 3 - 3-29 Answer true or false. (a) According to the...Ch. 3 - Prob. 3.30PCh. 3 - 3-31 Why does electronegativity generally increase...Ch. 3 - 3-32 Judging from their relative positions in the...Ch. 3 - Prob. 3.33PCh. 3 - 3-34 Which of these bonds is the most polar? The...Ch. 3 - 3-35 Classify each bond as nonpolar covalent,...Ch. 3 - 3-36 Classify each bond as nonpolar covalent,...Ch. 3 - 3-37 Answer true or false. (a) An ionic bond is...Ch. 3 - 3-38 Complete the chart by writing formulas for...Ch. 3 - 3-39 Write a formula for the ionic compound formed...Ch. 3 - Prob. 3.40PCh. 3 - 3-41 Describe the structure of sodium chloride in...Ch. 3 - 3-42 What is the charge on each ion in these...Ch. 3 - 3-43 Write the formula for the compound formed...Ch. 3 - 3-44 Write the formula for the ionic compound...Ch. 3 - 3-45 Which formulas are not correct? For each that...Ch. 3 - 3-46 Which formulas are not correct? For each that...Ch. 3 - 3-47 Answer true or false. (a) The name of a...Ch. 3 - 3-48 Potassium chloride and potassium bicarbonate...Ch. 3 - Prob. 3.49PCh. 3 - 3-50 Name the polyatomic ion(s) in each compound....Ch. 3 - 3-51 Write the formulas for the ions present in...Ch. 3 - Prob. 3.52PCh. 3 - 3-53 Write formulas for the following ionic...Ch. 3 - 3-54 Write formulas for the following ionic...Ch. 3 - Prob. 3.55PCh. 3 - 3-56 How many covalent bonds are normally formed...Ch. 3 - 3-57 What is: (a) A single bond? (b) A double...Ch. 3 - 3-58 In Section 2-3B, we saw that there are seven...Ch. 3 - Prob. 3.59PCh. 3 - Prob. 3.60PCh. 3 - Prob. 3.61PCh. 3 - Prob. 3.62PCh. 3 - 3-63 What is the difference between (a) a bromine...Ch. 3 - 3-64 Acetylene (C2H2), hydrogen cyanide (HCN), and...Ch. 3 - Prob. 3.65PCh. 3 - 3-66 Why can’t second-row elements have more than...Ch. 3 - 3-67 Why does nitrogen have three bonds and one...Ch. 3 - 3-68 Draw a Lewis structure of a covalent compound...Ch. 3 - Prob. 3.69PCh. 3 - 3-70 Draw a Lewis structure of a covalent compound...Ch. 3 - Prob. 3.71PCh. 3 - Prob. 3.72PCh. 3 - Prob. 3.73PCh. 3 - 3-74 Answer true or false. (a) A binary covalent...Ch. 3 - Prob. 3.75PCh. 3 - Prob. 3.76PCh. 3 - 3-77 Ozone, O3, is an unstable blue gas with a...Ch. 3 - 3-78 Nitrous oxide, N20, laughing gas, is a...Ch. 3 - 3-79 Answer true or false. (a) The letters VSEPR...Ch. 3 - Prob. 3.80PCh. 3 - Prob. 3.81PCh. 3 - 3-82 Hydrogen and nitrogen combine in different...Ch. 3 - Prob. 3.83PCh. 3 - Prob. 3.84PCh. 3 - Prob. 3.85PCh. 3 - Prob. 3.86PCh. 3 - 3-87 Consider the molecule boron trffluoride, BF3....Ch. 3 - Prob. 3.88PCh. 3 - 3-89 Is it possible for a molecule to have no...Ch. 3 - Prob. 3.90PCh. 3 - Prob. 3.91PCh. 3 - Prob. 3.92PCh. 3 - Prob. 3.93PCh. 3 - Prob. 3.94PCh. 3 - Prob. 3.95PCh. 3 - Prob. 3.96PCh. 3 - Prob. 3.97PCh. 3 - Prob. 3.98PCh. 3 - 3-99 Knowing what you do about covalent bonding in...Ch. 3 - Prob. 3.100PCh. 3 - Prob. 3.101PCh. 3 - Prob. 3.102PCh. 3 - Prob. 3.103PCh. 3 - Prob. 3.104PCh. 3 - 3-105 Consider the structure of Vitamin E shown...Ch. 3 - 3-106 Consider the structure of Penicillin G shown...Ch. 3 - 3-107 Ephedrine, a molecule at one time found in...Ch. 3 - Prob. 3.108PCh. 3 - 3-109 Until several years ago, the two...Ch. 3 - 3-110 Name and write the formula for the fluorine...Ch. 3 - Prob. 3.111PCh. 3 - Prob. 3.112PCh. 3 - Prob. 3.113PCh. 3 - Prob. 3.114PCh. 3 - Prob. 3.115PCh. 3 - Prob. 3.116PCh. 3 - Prob. 3.117PCh. 3 - Prob. 3.118PCh. 3 - 3-119 Perchloroethylene, which is a liquid at room...Ch. 3 - 3-120 Vinyl chloride is the starting material for...Ch. 3 - 3-121 Tetrafluoroethylene is the starting material...Ch. 3 - 3-122 Some of the following structural formulas...Ch. 3 - 3-123 Sodium borohydride, NaBH4, has found wide...Ch. 3 - Prob. 3.124PCh. 3 - Prob. 3.125PCh. 3 - Prob. 3.126PCh. 3 - 3-127 Amoxicillin is an antibiotic used to treat...Ch. 3 - Prob. 3.128P
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