To analyse whether the given molecules follows octet rule or not. Concept Introduction: A covalent bond is formed by sharing of same number of electrons between two atoms to complete their octet. Atoms taking part in covalent bond formation may share one, two or three electron pairs thus forming single, double and triple bond respectively. Lewis structure of a molecule can be determined as- 1. Calculate the total number of valence electrons.(T.V.E. = a). Sum up all the electrons of all atoms present in the molecule. If the molecule is an anion, add the same number of electrons as the charge present on the ion. If it is a cation, subtract the same number of electrons as the charge present on the ion. 2. Calculate the total number of electrons required for each atom to have a complete octet or doublet for hydrogen (b). 3. Therefore number of bonds formed = b − a 2 4. Remaining electrons are called as lone pairs. 5. Assign formal charges to atoms.
To analyse whether the given molecules follows octet rule or not. Concept Introduction: A covalent bond is formed by sharing of same number of electrons between two atoms to complete their octet. Atoms taking part in covalent bond formation may share one, two or three electron pairs thus forming single, double and triple bond respectively. Lewis structure of a molecule can be determined as- 1. Calculate the total number of valence electrons.(T.V.E. = a). Sum up all the electrons of all atoms present in the molecule. If the molecule is an anion, add the same number of electrons as the charge present on the ion. If it is a cation, subtract the same number of electrons as the charge present on the ion. 2. Calculate the total number of electrons required for each atom to have a complete octet or doublet for hydrogen (b). 3. Therefore number of bonds formed = b − a 2 4. Remaining electrons are called as lone pairs. 5. Assign formal charges to atoms.
Solution Summary: The author analyzes whether the given molecules follow the octet rule or not.
To analyse whether the given molecules follows octet rule or not.
Concept Introduction:
A covalent bond is formed by sharing of same number of electrons between two atoms to complete their octet. Atoms taking part in covalent bond formation may share one, two or three electron pairs thus forming single, double and triple bond respectively.
Lewis structure of a molecule can be determined as-
1. Calculate the total number of valence electrons.(T.V.E. = a).
Sum up all the electrons of all atoms present in the molecule.
If the molecule is an anion, add the same number of electrons as the charge present on the ion.
If it is a cation, subtract the same number of electrons as the charge present on the ion.
2. Calculate the total number of electrons required for each atom to have a complete octet or doublet for hydrogen (b).
Write structural formulas for the major products by
doing addition reactions
1. You must add H2 as Pt is catalyst it does not take part in reactions
only speed up the process
H₂
CH2=CH-CH3
Pt
2. Add HCI break it into H and Cl
CH3
HCI
3. Add Br2 only CC14 is catalyst
CH3-CH=CH2
B12
CCl4
4. Add water to this and draw major product, H2SO4 is catalyst you have add
water H20 in both the reaction below
H₂SO4
CH3-CH=CH2
CH3
H2SO4/H₂O
CH3-C=CH2
reflux
?
Plan the synthesis of the following compound using the starting
material provided and any other reagents needed as long as
carbon based reagents have 3 carbons or less. Either the
retrosynthesis or the forward synthesis (mechanisms are not
required but will be graded if provided) will be accepted if all
necessary reagents and intermediates are shown (solvents and
temperature requirements are not needed unless specifically
involved in the reaction, i.e. DMSO in the Swern oxidation or
heat in the KMnO4 oxidation).
H
H
Hint These are benzene substitution reactions.
ALCI3 and UV light are catalyst no part in reactions and triangle A means
heating.
A. Add ethyl for Et in benzene ring alkylation reaction EtCl =
CH3CH2CL
1) EtC1 / AlCl3 / A
?
B: Add Br to benzene ring ( substitution)
2) Br₂ / uv light
?
C Add (CH3)2 CHCH2 in benzene ring ( substitution)
(CH3)2CHCH,C1 / AICI,
?
Chapter 3 Solutions
OWLv2 for Bettelheim/Brown/Campbell/Farrell/Torres' Introduction to General, Organic and Biochemistry, 11th Edition, [Instant Access], 1 term (6 months)
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