(a) Interpretation: The number of atoms per FCC unit cell needs to be calculated. Concept Introduction: Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74. Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R .

Question

0.5 mm 450 mm -350 mm Bronze Aluminum A 1500 mm² A 1800 mm² E 105 GPa E 73 GPa K = 21.6 X 10 G < = 23.2 × 10-G PROBLEM 2.59 Determine (a) the compressive force in the bars shown after a temperature rise of 82°C, (b) the corresponding change in length of the bronze bar.

Answer 1

Question

Chapter 3, Problem 3.83P

Interpretation Introduction

(a)

Interpretation:

The number of atoms per FCC unit cell needs to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Interpretation Introduction

(b)

Interpretation:

The coordinates of smaller atoms with radius r per unit cell is to be determined.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Interpretation Introduction

(c)

Interpretation:

The atomic packing fraction for FCC structure is to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

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0.5 mm 450 mm -350 mm Bronze Aluminum A 1500 mm² A 1800 mm² E 105 GPa E 73 GPa K = 21.6 X 10 G < = 23.2 × 10-G PROBLEM 2.59 Determine (a) the compressive force in the bars shown after a temperature rise of 82°C, (b) the corresponding change in length of the bronze bar.

Three speech signals are TDM multiplexed with a high-quality music signal. If each speech signal is sampled at 16 kHz and PCM quantized by 8 bits/sample, while the music signal is sampled at 64 kHz with the same PCM quantizer. 1. Draw the block diagram of this TDM. 2. Calculate the output bit rate of this TDM.

The truss shown below sits on a roller at A and a pin at E. Determine the magnitudes of the forces in truss members GH, GB, BC and GC. State whether they are in tension or compression or are zero force members.

Answer 2

Question

Chapter 3, Problem 3.83P

Interpretation Introduction

(a)

Interpretation:

The number of atoms per FCC unit cell needs to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Interpretation Introduction

(b)

Interpretation:

The coordinates of smaller atoms with radius r per unit cell is to be determined.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Interpretation Introduction

(c)

Interpretation:

The atomic packing fraction for FCC structure is to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

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Answer 3

Question

Chapter 3, Problem 3.83P

Interpretation Introduction

(a)

Interpretation:

The number of atoms per FCC unit cell needs to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Interpretation Introduction

(b)

Interpretation:

The coordinates of smaller atoms with radius r per unit cell is to be determined.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Interpretation Introduction

(c)

Interpretation:

The atomic packing fraction for FCC structure is to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

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Answer 4

Question

Chapter 3, Problem 3.83P

Interpretation Introduction

(a)

Interpretation:

The number of atoms per FCC unit cell needs to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Interpretation Introduction

(b)

Interpretation:

The coordinates of smaller atoms with radius r per unit cell is to be determined.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Interpretation Introduction

(c)

Interpretation:

The atomic packing fraction for FCC structure is to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

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Answer 5

Chapter 3, Problem 3.83P

Interpretation Introduction

(a)

Interpretation:

The number of atoms per FCC unit cell needs to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Interpretation Introduction

(b)

Interpretation:

The coordinates of smaller atoms with radius r per unit cell is to be determined.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Interpretation Introduction

(c)

Interpretation:

The atomic packing fraction for FCC structure is to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Answer 6

Chapter 3, Problem 3.83P

Interpretation Introduction

(a)

Interpretation:

The number of atoms per FCC unit cell needs to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Answer 7

Chapter 3, Problem 3.83P

Interpretation Introduction

(a)

Interpretation:

The number of atoms per FCC unit cell needs to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The coordinates of smaller atoms with radius r per unit cell is to be determined.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The coordinates of smaller atoms with radius r per unit cell is to be determined.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Answer 10

Interpretation Introduction

(c)

Interpretation:

The atomic packing fraction for FCC structure is to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Answer 11

Interpretation Introduction

(c)

Interpretation:

The atomic packing fraction for FCC structure is to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Answer 12

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Answer 23

Ch. 3 - Prob. 3.1P Ch. 3 - Prob. 3.2P Ch. 3 - Prob. 3.3P Ch. 3 - Prob. 3.4P Ch. 3 - Prob. 3.5P Ch. 3 - Prob. 3.6P Ch. 3 - Prob. 3.7P Ch. 3 - Prob. 3.8P Ch. 3 - Prob. 3.9P Ch. 3 - Prob. 3.10P

Solution Summary: The author calculates the number of atoms per FCC unit cell. Atoms with R radius consume 74% of total volume and the remaining 26% is empty.

Chapter 3 Solutions