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(a)
Interpretation:
The number of atoms of element A per unit cell is to be calculated.
Concept Introduction:
The most basic repeating structure of any solid is said to be the unit cell consuming least volume. The repeating pattern of unit cells results in a network said to be a lattice.
An atom's coordination number in a unit cell is equal to the number of atoms it touches in the cell.
(b)
Interpretation:
The number of atoms of element B per unit cell is to be calculated.
Concept Introduction:
Most basic repeating structure of any solid is said to be the unit cell consuming least volume. The repeating pattern of unit cells results in a network said to be a lattice.
An atom's coordination number in a unit cell is equal to the number of atoms it touches in the cell.
(c)
Interpretation:
Whether the answer in part (b) related with the stoichiometry of AB2 compound or not should be determined.
Concept Introduction:
Rutile crystal structure is in the form of PQ2. Q is an oxygen atom and P is a metal atom. Coordinates of Q are:
(d)
Interpretation:
The unit cell for rutile should be drawn by using different symbol for every atom and a legend should be provided that shows which symbol denotes which type of atom.
Concept Introduction:
Parameters of unit cell:
(e)
Interpretation:
The rutile strcuture should be described as a simple tetragonal lattice with basis.
Concept Introduction:
Parameters of unit cell:
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Chapter 3 Solutions
Essentials Of Materials Science And Engineering
- 4. Two different silicon samples maintained at 300K are characterized by the energy band diagrams. Answer the questions that follow after choosing a specific diagram for analysis. a) Do equilibrium conditions prebail? How do you know? b) Sketch the electrostatic potential (V) inside the semiconductor as a function of x. c) Sketch the electric field (ε) inside the semiconductor as a function of x. EF Ec E₁ Ev E₁ EF Ev X X 0 L/2 L 0 L/2 L 3.arrow_forwardProblem 2 Consider the power drawn by a resistance load in a DC circuit. The power is calculated as P = VI or P = 1²R. It is given that the normalized uncertainty or % percentage uncertainty in measurements of I, R, and V are the same. Find the uncertainty in P using the two different expressions for power. Is the uncertainty using the two methods the same? If not, WHY, explain?arrow_forwardStudy the Capital One Breach article via the following link: https://www.darkreading.com/cloud-security/capital-one-breach-conviction-exposes-scale-of-cloud-entitlement-riskDiscuss (a) the breach, (b) what and who was affected, and (c) provide at least three outcomes, using references from the article, what you learned on cloud network architecture critical to your personal information.arrow_forward
- See BOTH images to answer correctly thxarrow_forwardA piston–cylinder device contains 3 kg of nitrogen initially at 100 kPa and 25°C. Nitrogen is now compressed slowly in a polytropic process during which PV1.3 = constant until the volume is reduced by one-half. Determine the work done and the heat transfer for this process. The gas constant of N2 is R = 0.2968 kPa·m3/kg·K. The cv value of N2 at the anticipated average temperature of 350 K is 0.744 kJ/kg·K (Table A-2b). The work done for this process is kJ. The heat transfer for this process is kJ.arrow_forwardI tried solving this one but I have no idea where I went wrong can you please help me out with this?arrow_forward
- a. An average hole drift velocity of 103 cm/sec results when 2V is applied across a 1 cm long semiconductor bar. What is the hole mobility inside the bar? b. Name the two dominant carrier scattering mechanisms in nondegeneratedly doped semiconductors of device quality. c. For a give semiconductor the carrier mobilities in intrinsic material are (choose one: higher than, lower than, the same as) those in heavily doped material. Briefly explain why the mobilites in intrinsic material are (chosen answer) those in heavily doped material.arrow_forwardDuring a picnic on a hot summer day, all the cold drinks disappear quickly, and the only available drinks are those at the ambient temperature of 85°F. In an effort to cool a 12- fluid-oz drink in a can, a person grabs the can and starts shaking it in the iced water of the chest at 32°F. Using the properties of water for the drink, determine the mass of ice that will melt by the time the canned drink cools to 37°F. The density and specific heat of water at the average temperature of (85+37)/2 = 61ºF are ρ = 62.3 lbm/ft3 and cp = 1.0 Btu/lbmºF (Table A-3E). The heat of fusion of water is 143.5 Btu/lbm. The mass of ice that will melt by the time the canned drink cools to 37°F is lbm.arrow_forwardSteam enters a nozzle at 400°C and 800 kPa with a velocity of 10 m/s and leaves at 375°C and 400 kPa while losing heat at a rate of 26.5 kW. For an inlet area of 800 cm2, determine the velocity and the volume flow rate of the steam at the nozzle exit. Use steam tables. At the left side of the lines, 800 kilo Pascal, 400 degree Centigrade, 10 meters per second are shown. At the right side of the lines, 400 kilo Pascal, 375 degree Centigrade are shown. The velocity of the steam at the nozzle exit is m/s. The volume flow rate of the steam at the nozzle exit is m3/s.arrow_forward
- A saturated liquid–vapor mixture of water, called wet steam, in a steam line at 1450 kPa is throttled to 50 kPa and 100°C. What is the quality in the steam line? Use data from the steam tables. Above the right side of the tube, 50 kilos 100 degree Centigrade indicated. The quality in the steam line is .arrow_forwardI tried this problems a couple of ways but I don't know what I'm doing wrong can you help me please?arrow_forwardRefrigerant-134a enters a compressor at 180 kPa as a saturated vapor with a flow rate of 0.35 m3/min and leaves at 900 kPa. The power supplied to the refrigerant during the compression process is 2.35 kW. What is the temperature of R-134a at the exit of the compressor? The temperature of R-134a at the exit of the compressor is °C.arrow_forward
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