The amount(mol) of calcium oxide ( CaO ) formed from 4.20 g of Ca is to be calculated. Concept introduction: In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other. A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction. The formula to calculate moles is as follows: Amount ( mol ) = mass molecular mass (1)

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Answer 1

Question

Chapter 3, Problem 3.83P

(a)

Interpretation Introduction

Interpretation:

The amount(mol) of calcium oxide (CaO) formed from 4.20 g of Ca is to be calculated.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

The formula to calculate moles is as follows:

Amount(mol)=massmolecular mass (1)

(b)

Interpretation Introduction

Interpretation:

The amount(mol) of calcium oxide (CaO) formed from 2.8 g of O2 is to be calculated.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

The formula to calculate moles is as follows:

Amount(mol)=massmolecular mass (1)

(c)

Interpretation Introduction

Interpretation:

The limiting reactant is to be predicted.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

(d)

Interpretation Introduction

Interpretation:

The mass of calcium oxide (CaO) produced is to be calculated.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

The formula to calculate moles is as follows:

Amount(mol)=massmolecular mass (1)

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Answer 2

Question

Chapter 3, Problem 3.83P

(a)

Interpretation Introduction

Interpretation:

The amount(mol) of calcium oxide (CaO) formed from 4.20 g of Ca is to be calculated.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

The formula to calculate moles is as follows:

Amount(mol)=massmolecular mass (1)

(b)

Interpretation Introduction

Interpretation:

The amount(mol) of calcium oxide (CaO) formed from 2.8 g of O2 is to be calculated.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

The formula to calculate moles is as follows:

Amount(mol)=massmolecular mass (1)

(c)

Interpretation Introduction

Interpretation:

The limiting reactant is to be predicted.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

(d)

Interpretation Introduction

Interpretation:

The mass of calcium oxide (CaO) produced is to be calculated.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

The formula to calculate moles is as follows:

Amount(mol)=massmolecular mass (1)

Expert Solution & Answer

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Answer 3

Question

Chapter 3, Problem 3.83P

(a)

Interpretation Introduction

Interpretation:

The amount(mol) of calcium oxide (CaO) formed from 4.20 g of Ca is to be calculated.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

The formula to calculate moles is as follows:

Amount(mol)=massmolecular mass (1)

(b)

Interpretation Introduction

Interpretation:

The amount(mol) of calcium oxide (CaO) formed from 2.8 g of O2 is to be calculated.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

The formula to calculate moles is as follows:

Amount(mol)=massmolecular mass (1)

(c)

Interpretation Introduction

Interpretation:

The limiting reactant is to be predicted.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

(d)

Interpretation Introduction

Interpretation:

The mass of calcium oxide (CaO) produced is to be calculated.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

The formula to calculate moles is as follows:

Amount(mol)=massmolecular mass (1)

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 3, Problem 3.83P

(a)

Interpretation Introduction

Interpretation:

The amount(mol) of calcium oxide (CaO) formed from 4.20 g of Ca is to be calculated.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

The formula to calculate moles is as follows:

Amount(mol)=massmolecular mass (1)

(b)

Interpretation Introduction

Interpretation:

The amount(mol) of calcium oxide (CaO) formed from 2.8 g of O2 is to be calculated.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

The formula to calculate moles is as follows:

Amount(mol)=massmolecular mass (1)

(c)

Interpretation Introduction

Interpretation:

The limiting reactant is to be predicted.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

(d)

Interpretation Introduction

Interpretation:

The mass of calcium oxide (CaO) produced is to be calculated.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

The formula to calculate moles is as follows:

Amount(mol)=massmolecular mass (1)

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 3, Problem 3.83P

(a)

Interpretation Introduction

Interpretation:

The amount(mol) of calcium oxide (CaO) formed from 4.20 g of Ca is to be calculated.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

The formula to calculate moles is as follows:

Amount(mol)=massmolecular mass (1)

(b)

Interpretation Introduction

Interpretation:

The amount(mol) of calcium oxide (CaO) formed from 2.8 g of O2 is to be calculated.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

The formula to calculate moles is as follows:

Amount(mol)=massmolecular mass (1)

(c)

Interpretation Introduction

Interpretation:

The limiting reactant is to be predicted.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

(d)

Interpretation Introduction

Interpretation:

The mass of calcium oxide (CaO) produced is to be calculated.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

The formula to calculate moles is as follows:

Amount(mol)=massmolecular mass (1)

Answer 6

Chapter 3, Problem 3.83P

(a)

Interpretation Introduction

Interpretation:

The amount(mol) of calcium oxide (CaO) formed from 4.20 g of Ca is to be calculated.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

The formula to calculate moles is as follows:

Amount(mol)=massmolecular mass (1)

Answer 7

Chapter 3, Problem 3.83P

(a)

Interpretation Introduction

Interpretation:

The amount(mol) of calcium oxide (CaO) formed from 4.20 g of Ca is to be calculated.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

The formula to calculate moles is as follows:

Amount(mol)=massmolecular mass (1)

Answer 8

(b)

Interpretation Introduction

Interpretation:

The amount(mol) of calcium oxide (CaO) formed from 2.8 g of O2 is to be calculated.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

The formula to calculate moles is as follows:

Amount(mol)=massmolecular mass (1)

Answer 9

(b)

Interpretation Introduction

Interpretation:

The amount(mol) of calcium oxide (CaO) formed from 2.8 g of O2 is to be calculated.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

The formula to calculate moles is as follows:

Amount(mol)=massmolecular mass (1)

Answer 10

(c)

Interpretation Introduction

Interpretation:

The limiting reactant is to be predicted.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

Answer 11

(c)

Interpretation Introduction

Interpretation:

The limiting reactant is to be predicted.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

Answer 12

(d)

Interpretation Introduction

Interpretation:

The mass of calcium oxide (CaO) produced is to be calculated.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

The formula to calculate moles is as follows:

Amount(mol)=massmolecular mass (1)

Answer 13

(d)

Interpretation Introduction

Interpretation:

The mass of calcium oxide (CaO) produced is to be calculated.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction.

The formula to calculate moles is as follows:

Amount(mol)=massmolecular mass (1)

Answer 14

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Answer 15

Expert Solution & Answer

Answer 16

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Answer 17

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