(a)
Interpretation:
The formula of copper (I) sulfite needs to be determined.
Concept Introduction:
When the number of electrons increases or decreases from the

Answer to Problem 3.82P
Explanation of Solution
The given name is copper (I) sulfite.
Here, copper is cation and sulfite is anion. The cation and anion with their charges are represented as follows:
The ratio of charge of cation to anion is as follows:
Therefore, the formula of the compound will be:
(b)
Interpretation:
The formula of aluminum nitrate needs to be determined.
Concept Introduction:
When the number of electrons increases or decreases from the atomic number, ions are formed. Cation is a positively charged ion formed by losing electron/s and anion is a negatively charged ion formed by gaining electron/s. While writing name of the ionic compounds, the name of cation is always written first followed by the name of the anion. In order to form an ionic compound, the cation and anion combine in such a way that the total charge is zero.

Answer to Problem 3.82P
Explanation of Solution
The given name is aluminum nitrate.
Here, aluminum is cation and nitrate is anion. The cation and anion with their charges are represented as follows:
The ratio of charge of cation to anion is as follows:
Therefore, the formula of the compound will be:
(c)
Interpretation:
The formula of tin (II) acetate needs to be determined.
Concept Introduction:
When the number of electrons increases or decreases from the atomic number, ions are formed. Cation is a positively charged ion formed by losing electron/s and anion is a negatively charged ion formed by gaining electron/s. While writing name of the ionic compounds, the name of cation is always written first followed by the name of the anion. In order to form an ionic compound, the cation and anion combine in such a way that the total charge is zero.

Answer to Problem 3.82P
Explanation of Solution
The given name is tin (II) acetate
Here, tin is cation and acetate is anion. The cation and anion with their charges are represented as follows:
The ratio of charge of cation to anion is as follows:
Therefore, the formula of the compound will be:
(d)
Interpretation:
The formula of lead (IV) carbonate needs to be determined.
Concept Introduction:
When the number of electrons increases or decreases from the atomic number, ions are formed. Cation is a positively charged ion formed by losing electron/s and anion is a negatively charged ion formed by gaining electron/s. While writing name of the ionic compounds, the name of cation is always written first followed by the name of the anion. In order to form an ionic compound, the cation and anion combine in such a way that the total charge is zero.

Answer to Problem 3.82P
Explanation of Solution
The given name is lead (IV) carbonate.
Here, lead is cation and carbonate is anion. The cation and anion with their charges are represented as follows:
The ratio of charge of cation to anion is as follows:
Therefore, the formula of the compound will be:
(e)
Interpretation:
The formula of zinc hydrogen phosphate needs to be determined.
Concept Introduction:
When the number of electrons increases or decreases from the atomic number, ions are formed. Cation is a positively charged ion formed by losing electron/s and anion is a negatively charged ion formed by gaining electron/s. While writing name of the ionic compounds, the name of cation is always written first followed by the name of the anion. In order to form an ionic compound, the cation and anion combine in such a way that the total charge is zero.

Answer to Problem 3.82P
Explanation of Solution
The given name is zinc hydrogen phosphate.
Here, zinc is cation and hydrogen phosphate is anion. The cation and anion with their charges are represented as follows:
The ratio of charge of cation to anion is as follows:
Therefore, the formula of the compound will be:
(f)
Interpretation:
The formula of manganese dihydrogen phosphate needs to be determined.
Concept Introduction:
When the number of electrons increases or decreases from the atomic number, ions are formed. Cation is a positively charged ion formed by losing electron/s and anion is a negatively charged ion formed by gaining electron/s. While writing name of the ionic compounds, the name of cation is always written first followed by the name of the anion. In order to form an ionic compound, the cation and anion combine in such a way that the total charge is zero.

Answer to Problem 3.82P
Explanation of Solution
The given name is manganese dihydrogen phosphate.
Here, manganese is cation and dihydrogen phosphate is anion. The cation and anion with their charges are represented as follows:
The ratio of charge of cation to anion is as follows:
Therefore, the formula of the compound will be:
(g)
Interpretation:
The formula of ammonium cyanide needs to be determined.
Concept Introduction:
When the number of electrons increases or decreases from the atomic number, ions are formed. Cation is a positively charged ion formed by losing electron/s and anion is a negatively charged ion formed by gaining electron/s. While writing name of the ionic compounds, the name of cation is always written first followed by the name of the anion. In order to form an ionic compound, the cation and anion combine in such a way that the total charge is zero.

Answer to Problem 3.82P
Explanation of Solution
The given name is ammonium cyanide.
Here, ammonium is cation and cyanide is anion. The cation and anion with their charges are represented as follows:
The ratio of charge of cation to anion is as follows:
Therefore, the formula of the compound will be:
(h)

Answer to Problem 3.82P
Explanation of Solution
The name of the compound is iron (II) nitrate.
Here, iron is cation and nitrate is anion. The cation and anion with their charges are represented as follows:
The ratio of charge of cation to anion is as follows:
Therefore, the formula of the compound will be:
Want to see more full solutions like this?
Chapter 3 Solutions
ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM
- 2Helparrow_forwardplease add appropriate arrows, and tell me clearly where to add arrows, or draw itarrow_forwardWhat I Have Learned Directions: Given the following reaction and the stress applied in each reaction, answer the question below. A. H2(g) + Cl2(g) 2 HCl(g) Stress applied: Decreasing the pressure 1. What is the Keq expression? 2. What will be the effect in the number of moles of HCl(g)? 3. What will be the Equilibrium Shift or the reaction? B. Fe3O4(s) + 4 H2(g) + heat 53 Fe(s) + 4 H₂O(g) Stress applied: Increasing the temperature 1. What is the Keq expression?. 2. What will be the effect in the volume of water vapor collected? 3. What will be the Equilibrium Shift or the reaction? C. 4 NH3(g) + 5 O2(g) 4 NO(g) + 6 H2O(g) + heat Stress applied: Increasing the volume of the container 1. What is the Keq expression?. 2. What will be the effect in the amount of H₂O? 3. What will be the Equilibrium Shift or the reaction?arrow_forward
- Consider the solubility products (Ksp values) for the following compounds:SrSO4 (Ksp = 7.6 x 10−7), BaSO4 (Ksp = 1.5 x 10−9), SrCO3 (Ksp = 7.0 x 10−10), BaCO3 (Ksp = 1.6 x 10−9)Which anion is the harder base, CO32− or SO42−? Justify your answer.arrow_forwardQ1: a) Arrange the compounds in order of decreasing pKa, highest first. ОН ΟΗ ῸΗ дон ОН ОН CI Brarrow_forward(4 pts - 2 pts each part) A route that can be taken to prepare a hydrophobic (water-repellent) aerogel is to start with trichloromethylsilane, CH3SiCl3 as the silicon source. a. What is the chemical reaction that this undergoes to form a product with Si-OH groups? Write as complete of a chemical equation as you can. CI CI-SI-CH3 CI b. The formation of a byproduct is what drives this reaction - what is the byproduct (if you didn't already answer it in part (a)) and how/why does it form?arrow_forward
- b) Circle the substrate that would not efficiently generate a Grignard reagent upon reaction with Mg in ether. CI Br ד c) Circle the Grignard reagents that contain incompatible functional groups. MgBr HO MgBr MgBr MgBr MgBr HO MgBrarrow_forwardQ2: Predict all organic product(s), including stereoisomers when applicable. PCC OH a) CH2Cl2 Page 2 of 5 Chem 0310 Organic Chemistry 1 HW Problem Sets b) .OH Na2Cr2O7, H+ OH PCC CH2Cl2 c) OHarrow_forwardd) Circle the substrates that will give an achiral product after a Grignard reaction with CH3MgBr. Harrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningIntroductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage Learning
- World of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage LearningChemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub CoGeneral Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning




