(a)
Interpretation:
The group number of the given electron-dot symbol should be stated.
Concept Introduction:
In an electron-dot symbol, dots are used to represent valence electrons around the elemental symbol.
When drawing or understanding an electron-dot symbol of an element, one should consider below facts;
- Each dot represents 1 electron.
- The dots are placed on the four sides of the elemental symbol.
- For 1 to 4 valence electrons, single dots are used.
- For more than 4 electrons, the dots are paired.
Valence electrons are the most loosely bound electrons of an element. They are in the outermost shell, which is also called "valence shell". Chemical properties of an element and its place in the periodic table depend on the number of valence electrons of that element.
For main group elements, the group number is also the number of valence electrons of the element.
(b)
Interpretation:
The charge of the ion formed by the given element should be determined.
Concept Introduction:
An atom of a main group element loses or gains electrons to obtain the electronic configuration of the noble gas closest to it in the periodic table to form ions.
Cations are formed by losing electrons, thus they have fewer electrons than protons and are positively charged.
Anions are formed by gaining electrons, thus they have more electrons than protons and are negatively charged.
For example, Sodium (Na) atom has 11 electrons ( 1s22s22p63s1 ) and the valence shell ( 3s1 ) is not fully filled. In order to achieve the stable electronic configuration of the nearest noble gas, Na must lose one electron and become Na+ cation. Now, the electronic configuration of Na+ cation is similar to Ne, which is 1s22s22p6.
(c)
Interpretation:
The formula of an ionic compound formed from Q and fluorine should be determined.
Concept Introduction:
Ionic compounds are composed of cations and anions, which are tightly attracted to each other.
The sum of the charges in an ionic compound must always be zero.
The formula for an ionic compound shows the ratio of ions that combine to give zero charge.
When cations and anions have different charges, the number of cations and anions differ so that the overall charge of the ionic compound be zero.
As an example, see the formulae of NaCl and MgCl2.
Na+ + Cl− → NaClMg2+ + Cl−+ Cl− → MgCl2
(d)
Interpretation:
The formula of an ionic compound formed from Q and oxygen should be determined.
Concept Introduction:
Ionic compounds are composed of cations and anions, which are tightly attracted to each other.
The sum of the charges in an ionic compound must always be zero.
The formula for an ionic compound shows the ratio of ions that combine to give zero charge.
When cations and anions have different charges, the number of cations and anions differ so that the overall charge of the ionic compound be zero.
As an example, see the formulae of NaCl and MgCl2.
Na+ + Cl− → NaClMg2+ + Cl−+ Cl− → MgCl2

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Chapter 3 Solutions
CONNECT IA GENERAL ORGANIC&BIO CHEMISTRY
- dG = Vdp - SdT + μA dnA + μB dnB + ... so that under constant pressure and temperature conditions, the chemical potential of a component is the rate of change of the Gibbs energy of the system with respect to changing composition, μJ = (∂G / ∂nJ)p,T,n' Using first principles prove that under conditions of constant volume and temperature, the chemical potential is a measure of the partial molar Helmholtz energy (μJ = (∂A / ∂nJ)V,T,n')arrow_forwardThe vapor pressure of dichloromethane at 20.0 °C is 58.0 kPa and its enthalpy of vaporization is 32.7 kJ/mol. Estimate the temperature at which its vapor pressure is 66.0 kPa.arrow_forwardDraw the structure of A, the minor E1 product of the reaction. Cl Skip Part Check F1 esc CH_CH OH, D 3 2 Click and drag to start drawing a structure. 80 R3 F4 F2 F3 @ 2 # $ 4 3 Q W 95 % KO 5 F6 A F7 × G ☐ Save For Later Sub 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy C ►II A A F8 F9 F10 FL 6 7 88 & * 8 9 LLI E R T Y U A S D lock LL F G H 0 P J K L Z X C V B N M 9 Harrow_forward
- From the choices given, which two substances have the same crystal structure? (Select both) Group of answer choices ZnS (zincblende) Diamond TiO2 (rutile) ZnS (wurtzite)arrow_forwardPotassium (K) blends with germanium (Ge) to form a Zintl phase with a chemical formula of K4Ge4. Which of the following elements would you expect potassium to blend with to form an alloy? Electronegativities: As (2.0), Cl (3.0), Ge (1.8), K (0.8), S (2.5), Ti (1.5) Group of answer choices Arsenic (As) Sulfur (S) Chlorine (Cl) Titanium (Ti)arrow_forwardConsider two elements, X and Z. Both have cubic-based unit cells with the same edge lengths. X has a bcc unit cell while Z has a fcc unit cell. Which of the following statements is TRUE? Group of answer choices Z has a larger density than X X has more particles in its unit cell than Z does X has a larger density than Z Z has a larger unit cell volume than Xarrow_forward
- How many particles does a face-centered cubic (fcc) unit cell contain? Group of answer choices 2 14 8 4arrow_forwardV Highlight all of the carbon atoms that have at least one beta (B) hydrogen, using red for one ẞ hydrogen, blue for two ẞ hydrogens, and green for three ẞ hydrogens. If none of the carbon atoms have ẞ hydrogens, check the box underneath the molecule. ED X None of the carbon atoms have ẞ hydrogens. Explanation esc 2 Check * F1 F2 1 2 80 # 3 Q W tab A caps lock shift fn control F3 N S option O 694 $ F4 F5 F6 005 % E R D F LL 6 olo 18 Ar B © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility A DII F7 F8 87 & * 8 T Y U G H 4 F9 F10 ( 9 0 E F11 F12 உ J K L + || X C V B N M H H command option commandarrow_forwardConsider the reaction below and answer the following questions. Part 1 of 4 Br NaOCH2CH3 Identify the mechanisms involved. Check all that apply. SN 1 SN 2 E1 E2 None of the above Part 2 of 4 Skip Part Check esc F1 F2 lock 1 2 Q W A S #3 80 F3 F4 F5 F6 Save For © 2025 McGraw Hill LLC. All Rights Reserved. Terms ˇˇ % & 4 5 6 89 7 IK A 分 བ F7 F8 F9 F * E R T Y U 8 9 D F G H K V B N M 0 Oarrow_forward
- What kind of holes are not generated when solid-state particles adopt a close packing pattern? Group of answer choices tetrahedral cubic octahedral None of the other choices are correctarrow_forwardFor the reaction below: 1. Draw all reasonable elimination products to the right of the arrow. 2. In the box below the reaction, redraw any product you expect to be a major product. 田 Major Product: Check ☐ + I Na OH esc F1 F2 2 1 @ 2 Q W tab A caps lock S #3 80 F3 69 4 σ F4 % 95 S Click and drag to sta drawing a structure mm Save For Later 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use GO DII F5 F6 F7 F8 F9 F10 6 CO 89 & 7 LU E R T Y U 8* 9 0 D F G H J K L Z X C V B N M 36arrow_forwardProblem 7 of 10 Draw the major product of this reaction. Ignore inorganic byproducts. S' S 1. BuLi 2. ethylene oxide (C2H4O) Select to Draw a Submitarrow_forward
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