Elementary Principles of Chemical Processes, Binder Ready Version
Elementary Principles of Chemical Processes, Binder Ready Version
4th Edition
ISBN: 9781118431221
Author: Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher: WILEY
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Chapter 3, Problem 3.64P
Interpretation Introduction

(a)

Interpretation:

The temperature of °F should be determined at which the bear will boil.

Concept introduction:

The inter conversion relation of the various measurement scales are given as follows:

T0C=T0F-321.8T0R=T0F+459.67TK=T0C+273

Further, the conversion between °C and °FB can be done by using the following equation:

T(0C)=0.0940 T(0FB)+4

Interpretation Introduction

(b)

Interpretation:

The temperature interval of 10.0 °FB degree which is equivalent to in °F, °C, 0R and K should be determined.

Concept introduction:

The inter conversion relation of the various measurement scales are given as follows:

T0C=T0F-321.8T0R=T0F+459.67TK=T0C+273

The inter conversion of temperature intervals in different scales are done as follows:

10C=1K10F=10R1.80R=1K10C=1.80F=1.80R

Interpretation Introduction

(c)

Interpretation:

The equations for T(°C) in terms of T(0L) and T(0L) in terms of T(°FB) should be derived.

Concept introduction:

The relation between two different scales is generated by establishing the correlation in per degree change temperature. In such procedure the upper and lower limits of both the temperature scales should be known.

The equation derivation formula is as follows:

T(0C)=aT(0L)+b

Interpretation Introduction

(d)

Interpretation:

The boiling point of ethane at 1atm in °F, °C, 0R, °FB and K should be determined.

Concept introduction:

The inter conversion of temperature intervals in different scales are done as follows:

10C=1K10F=10R1.80R=1K10C=1.80F=1.80R

Interpretation Introduction

(e)

Interpretation:

The temperature interval of 500L equivalent to °F, °C, 0R, °FB and K should be determined.

Concept introduction:

The inter conversion of temperature intervals in different scales are done as follows:

10C=1K10F=10R1.80R=1K10C=1.80F=1.80R

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Chapter 3 Solutions

Elementary Principles of Chemical Processes, Binder Ready Version

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