
(a)
Interpretation:
The cations & anions derived from Barium & Bromine should be combined in order to get an electrically neutralized ionic compound.
Concept introduction:
An ionic compound forms by the mutual attraction of 2 oppositely charged ions called cation & anion. Cationis derived from Barium (Ba), while anion is derived from Bromine (Br).

Answer to Problem 3.60P
BaBr2
Explanation of Solution
Cations are derived from metals. A cation is formed by removing 1 or few electrons from a metal atom. As electrons are negatively charged, the removal of electrons (negative charges) gives a positive charge to the rest of the atom.
Oppositely anions are derived from non-metal elements. An anion is formed by gaining 1 or few electrons. As electrons are negatively charged, the gaining of electrons (negative charges) gives a negative charge to the rest of the atom.
So, in the given two elements metal is Barium (Ba). So cation is derived from Ba. The only cation derived from Ba is Ba2+. The cation is derived by removing 2 electrons from Ba.
Ba → Ba2+ + 2e (electrons are indicated as e)
Bromine is the non-metal which is forming anion, Br- / Bromide, by gaining 1 electron to a Br atom.
Br + e → Br-
From this cation & anion an ionic compound is formed. Usually a simple ionic compound is electrically neutral. So cation & anion combined in a way to neutralize opposite charges.
As Ba2+ is having +2 positive charge, 2 Br- ions should becombined.
So the ionic compound form from Barium & Bromine is BaBr2.
(b)
Interpretation:
The cations & anions derived from Aluminum&Sulfur should be combined in order to get an electrically neutralized ionic compound.
Concept introduction:
An ionic compound forms by the mutual attraction of 2 oppositely charged ions called cation & anion. Cation is derived from Aluminum (Al), while anion is derived from Sulfur(S).

Answer to Problem 3.60P
Al2S3
Explanation of Solution
Cations are derived from metals. A cation is formed by removing 1 or few electrons from a metal atom. As electrons are negatively charged, the removal of electrons (negative charges) gives a positive charge to the rest of the atom.
Oppositely anions are derived from non-metal elements. An anion is formed by gaining 1 or few electrons. As electrons are negatively charged, the gaining of electrons (negative charges) gives a negative charge to the rest of the atom.
In the given two elements metal is Aluminum (Al). So cation is derived from Al. The only cation derived from Al is Al3+. The cation is derived by removing 3 electrons from Al.
Al → Al3++ 3e (electrons are indicated as e)
Sulfur is the non-metal which is forming anion, S2-/Sulfide, by gaining 2 electrons.
S + 2e → S2-
From this cation & anion an ionic compound is formed. Usually a simple ionic compound is electrically neutral. So cation & anion combined in a way to neutralize opposite charges.
Al3+ has a +3 charge. S2-/ Sulfide ion has a -2 charge. So S2-: Al3+ should be combined in a ratio of 3: 2, to maintain the charge neutrality. This is the first ratio that the both values are integers.
The above ratio is proven correct by the following simple calculation to balance charges.
(Equals zero because the ionic compound should have no net charge)
So in the ionic compound form from Aluminum & Sulfur there should be 2 Al3+s & 3 S2- s. So the compound is Al2S3
(c)
Interpretation:
The cations & anions derived from Manganese&Chlorine should be combined in order to get an electrically neutralized ionic compound.
Concept introduction:
An ionic compound forms by the mutual attraction of 2 oppositely charged ions called cation & anion. Cation is derived from Manganese (Mn), while anion is derived from Chlorine (Cl).

Answer to Problem 3.60P
MnCl2
Explanation of Solution
Cations are derived from metals. A cation is formed by removing 1 or few electrons from a metal atom. As electrons are negatively charged, the removal of electrons (negative charges) gives a positive charge to the rest of the atom.
Oppositely anions are derived from non-metal elements. An anion is formed by gaining 1 or few electrons. As electrons are negatively charged, the gaining of electrons (negative charges) gives a negative charge to the rest of the atom.
So in the given two elements metal is Manganese (Mn). So cation is derived from Mn. Manganese has the ability to form several cations like Mn2+, Mn3+&Mn4+. Out of them the most stable cation is Mn2+. This cation is derived by removing 2 electrons from Mn.
Mn → Mn2+ + 2e (electrons are indicated as e)
Chlorine is the non-metal which is forming anion, Cl-/Chloride, by gaining 1 electron to a Cl atom.
Cl + e → Cl-
From this cation & anion an ionic compound is formed. Usually a simple ionic compound is electrically neutral. So cation & anion combined in a way to neutralize opposite charges.
As Mn2+ is having +2 positive charge, 2 Cl- ions should becombined.
So, the ionic compound form from Manganese&Chlorine is MnCl2.
(d)
Interpretation:
The cations & anions derived from Zinc&Sulfur should be combined in order to get an electrically neutralized ionic compound.
Concept introduction:
An ionic compound forms by the mutual attraction of 2 oppositely charged ions called cation & anion. Cation is derived from Zinc (Zn), while anion is derived from Sulfur (S).

Answer to Problem 3.60P
ZnS
Explanation of Solution
Cations are derived from metals. A cation is formed by removing 1 or few electrons from a metal atom. As electrons are negatively charged, the removal of electrons (negative charges) gives a positive charge to the rest of the atom.
Oppositely anions are derived from non-metal elements. An anion is formed by gaining 1 or few electrons. As electrons are negatively charged, the gaining of electrons (negative charges) gives a negative charge to the rest of the atom.
So in the given two elements metal is Zinc (Zn). So cation is derived from Zn. The most common & stable cation derived from Zn is Zn2+. The cation is derived by removing 2 electrons from Zn.
Zn → Zn2+ + 2e (electrons are indicated as e)
Sulfur is the non-metal which is forming anion, S2- / Sulfide, by gaining 2 electrons.
S + 2e → S2-
From this cation & anion an ionic compound is formed. Usually a simple ionic compound is electrically neutral. So cation & anion combined in a way to neutralize opposite charges.
As both Zn2+& S2-is having +2 & -2 charge, one cation & one anion are combined to form the Compound ZnS.
So, the ionic compound form from Zinc&Sulfur is ZnS.
(e)
Interpretation:
The cations & anions derived from Magnesium&Fluorine should be combined in order to get an electrically neutralized ionic compound.
Concept introduction:
An ionic compound forms by the mutual attraction of 2 oppositely charged ions called cation & anion. Cation is derived from Magnesium (Mg), while anion is derived from Fluorine (F).

Answer to Problem 3.60P
MgF2
Explanation of Solution
Cations are derived from metals. A cation is formed by removing 1 or few electrons from a metal atom. As electrons are negatively charged, the removal of electrons (negative charges) gives a positive charge to the rest of the atom.
Oppositely anions are derived from non-metal elements. An anion is formed by gaining 1 or few electrons. As electrons are negatively charged, the gaining of electrons (negative charges) gives a negative charge to the rest of the atom.
So in the given two elements metal is Magnesium (Mg). So cation is derived from Mg. The only cation derived from Mg is Mg2+. The cation is derived by removing 2 electrons from Mg.
Mg → Mg2+ + 2e (electrons are indicated as e)
Fluorine is the non-metal, which is forming anion, F- / Fluoride, by gaining 1 electron to a F atom.
F + e → F-
From this cation & anion an ionic compound is formed. Usually a simple ionic compound is electrically neutral. So cation & anion combined in a way to neutralize opposite charges.
As Mg2+ is having +2 positive charge, 2 F- ions should becombined.
So the ionic compound form from Magnesium&Fluorine is MgF2.
Want to see more full solutions like this?
Chapter 3 Solutions
EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM
- Correct each molecule in the drawing area below so that it has the skeletal ("line") structure it would have if it were dissolved in a 0.1 M aqueous solution of HCI. If there are no changes to be made, check the No changes box under the drawing area. No changes. HO Explanation Check NH, 2 W O :□ G ©2025 M unter Accessibilityarrow_forwardAn expression for the root mean square velocity, vrms, of a gas was derived. Using Maxwell’s velocity distribution, one can also calculate the mean velocity and the most probable velocity (mp) of a collection of molecules. The equations used for these two quantities are vmean=(8RT/πM)1/2 and vmp=(2RT/M)1/2 These values have a fixed relationship to each other.(a) Arrange these three quantities in order of increasing magnitude.(b) Show that the relative magnitudes are independent of the molar mass of the gas.(c) Use the smallest velocity as a reference for establishing the order of magnitude and determine the relationship between the larger and smaller values.arrow_forwardThe reaction of solid dimethylhydrazine, (CH3)2N2H2, and liquefied dinitrogen tetroxide, N2O4, has been investigated for use as rocket fuel. The reaction produces the gases carbon dioxide (CO2), nitrogen (N2), and water vapor (H2O), which are ejected in the exhaust gases. In a controlled experiment, solid dimethylhydrazine was reacted with excess dinitrogen tetroxide, and the gases were collected in a closed balloon until a pressure of 2.50 atm and a temperature of 400.0 K were reached.(a) What are the partial pressures of CO2, N2, and H2O?(b) When the CO2 is removed by chemical reaction, what are the partial pressures of the remaining gases?arrow_forward
- One liter of chlorine gas at 1 atm and 298 K reacts completely with 1.00 L of nitrogen gas and 2.00 L of oxygen gas at the same temperature and pressure. A single gaseous product is formed, which fills a 2.00 L flask at 1.00 atm and 298 K. Use this information to determine the following characteristics of the product:(a) its empirical formula;(b) its molecular formula;(c) the most favorable Lewis formula based on formal charge arguments (the central atom is N);(d) the shape of the molecule.arrow_forwardHow does the square root mean square velocity of gas molecules vary with temperature? Illustrate this relationship by plotting the square root mean square velocity of N2 molecules as a function of temperature from T=100 K to T=300 K.arrow_forwardDraw product B, indicating what type of reaction occurs. F3C CF3 NH2 Me O .N. + B OMearrow_forward
- Benzimidazole E. State its formula. sState the differences in the formula with other benzimidazoles.arrow_forwardDraw product A, indicating what type of reaction occurs. F3C CN CF3 K2CO3, DMSO, H₂O2 Aarrow_forward19) Which metal is most commonly used in galvanization to protect steel structures from oxidation? Lead a. b. Tin C. Nickel d. Zinc 20) The following molecule is an example of a: R₁ R2- -N-R3 a. Secondary amine b. Secondary amide c. Tertiary amine d. Tertiary amidearrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningLiving By Chemistry: First Edition TextbookChemistryISBN:9781559539418Author:Angelica StacyPublisher:MAC HIGHERChemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
- Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningGeneral, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage Learning





