Given information: The signed value of A is 5. The signed value of B is -7. Number Line: Number line is a line used to represent the real numbers in a horizontal line. Every point in a horizontal line represents a real number. Positive numbers are represented to the right of zero and negative numbers are represented to the left of zero. Number line is mainly used for the operation of basic addition and subtraction performed on negative numbers.

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Answer 1

Question

Chapter 3, Problem 35E

Program Plan Intro

Given information:

The signed value of A is 5.

The signed value of B is -7.

Number Line:

Number line is a line used to represent the real numbers in a horizontal line.

Every point in a horizontal line represents a real number.

Positive numbers are represented to the right of zero and negative numbers are represented to the left of zero.

Number line is mainly used for the operation of basic addition and subtraction performed on negative numbers.

Explanation of Solution

b.

Proving solution to the operation “A-B”:

To evaluate the result of the given expression “A-B”, substitute the value of A as 5 and B as -7 in the expression. The result is,

A−B=5−(−7)</

Explanation of Solution

c.

Proving solution to the operation “B+A”:

To evaluate the result of the given expression “B+A”, substitute the value of B as -7 and A as 5 in the expression. The result is,

B+A=(−7)+5=<

Explanation of Solution

d.

Proving solution to the operation “B-A”:

To evaluate the result of the given expression “B+A”, substitute the value of B as -7 and A as 5 in the expression. The result is,

B−A=(−7)−5<

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Answer 2

Question

Chapter 3, Problem 35E

Program Plan Intro

Given information:

The signed value of A is 5.

The signed value of B is -7.

Number Line:

Number line is a line used to represent the real numbers in a horizontal line.

Every point in a horizontal line represents a real number.

Positive numbers are represented to the right of zero and negative numbers are represented to the left of zero.

Number line is mainly used for the operation of basic addition and subtraction performed on negative numbers.

Explanation of Solution

b.

Proving solution to the operation “A-B”:

To evaluate the result of the given expression “A-B”, substitute the value of A as 5 and B as -7 in the expression. The result is,

A−B=5−(−7)</

Explanation of Solution

c.

Proving solution to the operation “B+A”:

To evaluate the result of the given expression “B+A”, substitute the value of B as -7 and A as 5 in the expression. The result is,

B+A=(−7)+5=<

Explanation of Solution

d.

Proving solution to the operation “B-A”:

To evaluate the result of the given expression “B+A”, substitute the value of B as -7 and A as 5 in the expression. The result is,

B−A=(−7)−5<

Expert Solution & Answer

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Answer 3

Question

Chapter 3, Problem 35E

Program Plan Intro

Given information:

The signed value of A is 5.

The signed value of B is -7.

Number Line:

Number line is a line used to represent the real numbers in a horizontal line.

Every point in a horizontal line represents a real number.

Positive numbers are represented to the right of zero and negative numbers are represented to the left of zero.

Number line is mainly used for the operation of basic addition and subtraction performed on negative numbers.

Explanation of Solution

b.

Proving solution to the operation “A-B”:

To evaluate the result of the given expression “A-B”, substitute the value of A as 5 and B as -7 in the expression. The result is,

A−B=5−(−7)</

Explanation of Solution

c.

Proving solution to the operation “B+A”:

To evaluate the result of the given expression “B+A”, substitute the value of B as -7 and A as 5 in the expression. The result is,

B+A=(−7)+5=<

Explanation of Solution

d.

Proving solution to the operation “B-A”:

To evaluate the result of the given expression “B+A”, substitute the value of B as -7 and A as 5 in the expression. The result is,

B−A=(−7)−5<

Expert Solution & Answer

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Answer 4

Question

Chapter 3, Problem 35E

Program Plan Intro

Given information:

The signed value of A is 5.

The signed value of B is -7.

Number Line:

Number line is a line used to represent the real numbers in a horizontal line.

Every point in a horizontal line represents a real number.

Positive numbers are represented to the right of zero and negative numbers are represented to the left of zero.

Number line is mainly used for the operation of basic addition and subtraction performed on negative numbers.

Explanation of Solution

b.

Proving solution to the operation “A-B”:

To evaluate the result of the given expression “A-B”, substitute the value of A as 5 and B as -7 in the expression. The result is,

A−B=5−(−7)</

Explanation of Solution

c.

Proving solution to the operation “B+A”:

To evaluate the result of the given expression “B+A”, substitute the value of B as -7 and A as 5 in the expression. The result is,

B+A=(−7)+5=<

Explanation of Solution

d.

Proving solution to the operation “B-A”:

To evaluate the result of the given expression “B+A”, substitute the value of B as -7 and A as 5 in the expression. The result is,

B−A=(−7)−5<

Expert Solution & Answer

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Answer 5

Chapter 3, Problem 35E

Program Plan Intro

Given information:

The signed value of A is 5.

The signed value of B is -7.

Number Line:

Number line is a line used to represent the real numbers in a horizontal line.

Every point in a horizontal line represents a real number.

Positive numbers are represented to the right of zero and negative numbers are represented to the left of zero.

Number line is mainly used for the operation of basic addition and subtraction performed on negative numbers.

Explanation of Solution

b.

Proving solution to the operation “A-B”:

To evaluate the result of the given expression “A-B”, substitute the value of A as 5 and B as -7 in the expression. The result is,

A−B=5−(−7)</

Explanation of Solution

c.

Proving solution to the operation “B+A”:

To evaluate the result of the given expression “B+A”, substitute the value of B as -7 and A as 5 in the expression. The result is,

B+A=(−7)+5=<

Explanation of Solution

d.

Proving solution to the operation “B-A”:

To evaluate the result of the given expression “B+A”, substitute the value of B as -7 and A as 5 in the expression. The result is,

B−A=(−7)−5<

Answer 6

Chapter 3, Problem 35E

Program Plan Intro

Given information:

The signed value of A is 5.

The signed value of B is -7.

Number Line:

Number line is a line used to represent the real numbers in a horizontal line.

Every point in a horizontal line represents a real number.

Positive numbers are represented to the right of zero and negative numbers are represented to the left of zero.

Number line is mainly used for the operation of basic addition and subtraction performed on negative numbers.

Answer 7

Chapter 3, Problem 35E

Program Plan Intro

Given information:

The signed value of A is 5.

The signed value of B is -7.

Number Line:

Number line is a line used to represent the real numbers in a horizontal line.

Every point in a horizontal line represents a real number.

Positive numbers are represented to the right of zero and negative numbers are represented to the left of zero.

Number line is mainly used for the operation of basic addition and subtraction performed on negative numbers.

Answer 8

Explanation of Solution

b.

Proving solution to the operation “A-B”:

To evaluate the result of the given expression “A-B”, substitute the value of A as 5 and B as -7 in the expression. The result is,

A−B=5−(−7)</

Answer 9

Explanation of Solution

b.

Proving solution to the operation “A-B”:

To evaluate the result of the given expression “A-B”, substitute the value of A as 5 and B as -7 in the expression. The result is,

A−B=5−(−7)</

Answer 10

Explanation of Solution

c.

Proving solution to the operation “B+A”:

To evaluate the result of the given expression “B+A”, substitute the value of B as -7 and A as 5 in the expression. The result is,

B+A=(−7)+5=<

Answer 11

Explanation of Solution

c.

Proving solution to the operation “B+A”:

To evaluate the result of the given expression “B+A”, substitute the value of B as -7 and A as 5 in the expression. The result is,

B+A=(−7)+5=<

Answer 12

Explanation of Solution

d.

Proving solution to the operation “B-A”:

To evaluate the result of the given expression “B+A”, substitute the value of B as -7 and A as 5 in the expression. The result is,

B−A=(−7)−5<

Answer 13

Explanation of Solution

d.

Proving solution to the operation “B-A”:

To evaluate the result of the given expression “B+A”, substitute the value of B as -7 and A as 5 in the expression. The result is,

B−A=(−7)−5<

Answer 14

Expert Solution & Answer

Answer 15

Expert Solution & Answer

Answer 16

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Answer 17

Ch. 3 - Prob. 1E Ch. 3 - Prob. 2E Ch. 3 - Prob. 3E Ch. 3 - Prob. 4E Ch. 3 - Prob. 5E Ch. 3 - Prob. 6E Ch. 3 - Prob. 7E Ch. 3 - Prob. 8E Ch. 3 - Prob. 9E Ch. 3 - Prob. 10E

Explanation of Solution

b. Proving solution to the operation “A-B”: To evaluate the result of the given expression “A-B”, substitute the value of A as 5 and B as -7 in the expression. The result is, A−B=5−(−7)</

Explanation of Solution

c. Proving solution to the operation “B+A”: To evaluate the result of the given expression “B+A”, substitute the value of B as -7 and A as 5 in the expression. The result is, B+A=(−7)+5=<

Explanation of Solution

d. Proving solution to the operation “B-A”: To evaluate the result of the given expression “B+A”, substitute the value of B as -7 and A as 5 in the expression. The result is, B−A=(−7)−5<

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Chapter 3 Solutions

b.

Proving solution to the operation “A-B”:

To evaluate the result of the given expression “A-B”, substitute the value of A as 5 and B as -7 in the expression. The result is,

A−B=5−(−7)</

c.

Proving solution to the operation “B+A”:

To evaluate the result of the given expression “B+A”, substitute the value of B as -7 and A as 5 in the expression. The result is,

B+A=(−7)+5=<

d.

Proving solution to the operation “B-A”:

To evaluate the result of the given expression “B+A”, substitute the value of B as -7 and A as 5 in the expression. The result is,

B−A=(−7)−5<