(a) Interpretation: The empirical formula of benzo[a]pyrene needs to be determined. Concept introduction: The empirical formula of a compound represents the simplest ratio of atoms present in the compound. The number of moles of a substance can be calculated from mass and molar mass as follows: n = m M Here, m is mass and M is molar mass.
(a) Interpretation: The empirical formula of benzo[a]pyrene needs to be determined. Concept introduction: The empirical formula of a compound represents the simplest ratio of atoms present in the compound. The number of moles of a substance can be calculated from mass and molar mass as follows: n = m M Here, m is mass and M is molar mass.
Solution Summary: The author explains the empirical formula of benzo[a]pyrene. The percentage composition of the compound is 95.21% C and 4.79% H by mass.
16. The proton NMR spectral information shown in this problem is for a compound with formula
CioH,N. Expansions are shown for the region from 8.7 to 7.0 ppm. The normal carbon-13 spec-
tral results, including DEPT-135 and DEPT-90 results, are tabulated:
7
J
Normal Carbon
DEPT-135
DEPT-90
19 ppm
Positive
No peak
122
Positive
Positive
cus
и
124
Positive
Positive
126
Positive
Positive
128
No peak
No peak
4°
129
Positive
Positive
130
Positive
Positive
(144
No peak
No peak
148
No peak
No peak
150
Positive
Positive
してし
3. Propose a synthesis for the following transformation. Do not draw an arrow-pushing
mechanism below, but make sure to draw the product of each proposed step (3 points).
+ En
CN
CN
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Chapter 3 Solutions
General Chemistry: Principles And Modern Applications Plus Mastering Chemistry With Pearson Etext -- Access Card Package (11th Edition)
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Step by Step Stoichiometry Practice Problems | How to Pass ChemistryMole Conversions Made Easy: How to Convert Between Grams and Moles; Author: Ketzbook;https://www.youtube.com/watch?v=b2raanVWU6c;License: Standard YouTube License, CC-BY