(a) Interpretation: A formula for the density of the block should be derived. Concept introduction: It is given that a rectangular block floats at the interface between two immiscible liquids. The dimensions of the block are given as follows, Height of the block = L Cross sectional area of the block = A Density of the light liquid = ρ 1 Density of the heavy liquid = ρ 2 Height from top surface of light liquid to the top surface of the block = h 0 Height from the top of the block to the liquids interface = h 1 Height from liquid interface to the bottom of block = h 2 Archimedes' principle, According to Archimedes principle the upward buoyant force that is exerted on a body immersed in a fluid, is equal to the weight of the fluid that the body displaces.

Question

Want to see the full answer?

Answer 1

Question

Chapter 3, Problem 3.46P

Interpretation Introduction

(a)

Interpretation:

A formula for the density of the block should be derived.

Concept introduction:

It is given that a rectangular block floats at the interface between two immiscible liquids. The dimensions of the block are given as follows,

Height of the block = L

Cross sectional area of the block = A

Density of the light liquid = ρ1

Density of the heavy liquid = ρ2

Height from top surface of light liquid to the top surface of the block = h0

Height from the top of the block to the liquids interface = h1

Height from liquid interface to the bottom of block = h2

Archimedes' principle,

According to Archimedes principle the upward buoyant force that is exerted on a body immersed in a fluid, is equal to the weight of the fluid that the body displaces.

Interpretation Introduction

(b)

Interpretation:

Prove that the two approaches used to balance force on the block are correct.

Concept introduction:

It is given that a rectangular block floats at the interface between two immiscible liquids. The dimensions of the block are given as follows,

Height of the block = L

Cross sectional area of the block = A

Density of the light liquid = ρ1

Density of the heavy liquid = ρ2

Height from top surface of light liquid to the top surface of the block = h0

Height from the top of the block to the liquids interface = h1

Height from liquid interface to the bottom of block = h2

Archimedes' principle,

According to Archimedes principle the upward buoyant force that is exerted on a body immersed in a fluid, is equal to the weight of the fluid that the body displaces.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 2

Question

Chapter 3, Problem 3.46P

Interpretation Introduction

(a)

Interpretation:

A formula for the density of the block should be derived.

Concept introduction:

It is given that a rectangular block floats at the interface between two immiscible liquids. The dimensions of the block are given as follows,

Height of the block = L

Cross sectional area of the block = A

Density of the light liquid = ρ1

Density of the heavy liquid = ρ2

Height from top surface of light liquid to the top surface of the block = h0

Height from the top of the block to the liquids interface = h1

Height from liquid interface to the bottom of block = h2

Archimedes' principle,

According to Archimedes principle the upward buoyant force that is exerted on a body immersed in a fluid, is equal to the weight of the fluid that the body displaces.

Interpretation Introduction

(b)

Interpretation:

Prove that the two approaches used to balance force on the block are correct.

Concept introduction:

It is given that a rectangular block floats at the interface between two immiscible liquids. The dimensions of the block are given as follows,

Height of the block = L

Cross sectional area of the block = A

Density of the light liquid = ρ1

Density of the heavy liquid = ρ2

Height from top surface of light liquid to the top surface of the block = h0

Height from the top of the block to the liquids interface = h1

Height from liquid interface to the bottom of block = h2

Archimedes' principle,

According to Archimedes principle the upward buoyant force that is exerted on a body immersed in a fluid, is equal to the weight of the fluid that the body displaces.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 3, Problem 3.46P

Interpretation Introduction

(a)

Interpretation:

A formula for the density of the block should be derived.

Concept introduction:

It is given that a rectangular block floats at the interface between two immiscible liquids. The dimensions of the block are given as follows,

Height of the block = L

Cross sectional area of the block = A

Density of the light liquid = ρ1

Density of the heavy liquid = ρ2

Height from top surface of light liquid to the top surface of the block = h0

Height from the top of the block to the liquids interface = h1

Height from liquid interface to the bottom of block = h2

Archimedes' principle,

According to Archimedes principle the upward buoyant force that is exerted on a body immersed in a fluid, is equal to the weight of the fluid that the body displaces.

Interpretation Introduction

(b)

Interpretation:

Prove that the two approaches used to balance force on the block are correct.

Concept introduction:

It is given that a rectangular block floats at the interface between two immiscible liquids. The dimensions of the block are given as follows,

Height of the block = L

Cross sectional area of the block = A

Density of the light liquid = ρ1

Density of the heavy liquid = ρ2

Height from top surface of light liquid to the top surface of the block = h0

Height from the top of the block to the liquids interface = h1

Height from liquid interface to the bottom of block = h2

Archimedes' principle,

According to Archimedes principle the upward buoyant force that is exerted on a body immersed in a fluid, is equal to the weight of the fluid that the body displaces.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 3, Problem 3.46P

Interpretation Introduction

(a)

Interpretation:

A formula for the density of the block should be derived.

Concept introduction:

It is given that a rectangular block floats at the interface between two immiscible liquids. The dimensions of the block are given as follows,

Height of the block = L

Cross sectional area of the block = A

Density of the light liquid = ρ1

Density of the heavy liquid = ρ2

Height from top surface of light liquid to the top surface of the block = h0

Height from the top of the block to the liquids interface = h1

Height from liquid interface to the bottom of block = h2

Archimedes' principle,

According to Archimedes principle the upward buoyant force that is exerted on a body immersed in a fluid, is equal to the weight of the fluid that the body displaces.

Interpretation Introduction

(b)

Interpretation:

Prove that the two approaches used to balance force on the block are correct.

Concept introduction:

It is given that a rectangular block floats at the interface between two immiscible liquids. The dimensions of the block are given as follows,

Height of the block = L

Cross sectional area of the block = A

Density of the light liquid = ρ1

Density of the heavy liquid = ρ2

Height from top surface of light liquid to the top surface of the block = h0

Height from the top of the block to the liquids interface = h1

Height from liquid interface to the bottom of block = h2

Archimedes' principle,

According to Archimedes principle the upward buoyant force that is exerted on a body immersed in a fluid, is equal to the weight of the fluid that the body displaces.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 3, Problem 3.46P

Interpretation Introduction

(a)

Interpretation:

A formula for the density of the block should be derived.

Concept introduction:

It is given that a rectangular block floats at the interface between two immiscible liquids. The dimensions of the block are given as follows,

Height of the block = L

Cross sectional area of the block = A

Density of the light liquid = ρ1

Density of the heavy liquid = ρ2

Height from top surface of light liquid to the top surface of the block = h0

Height from the top of the block to the liquids interface = h1

Height from liquid interface to the bottom of block = h2

Archimedes' principle,

According to Archimedes principle the upward buoyant force that is exerted on a body immersed in a fluid, is equal to the weight of the fluid that the body displaces.

Interpretation Introduction

(b)

Interpretation:

Prove that the two approaches used to balance force on the block are correct.

Concept introduction:

It is given that a rectangular block floats at the interface between two immiscible liquids. The dimensions of the block are given as follows,

Height of the block = L

Cross sectional area of the block = A

Density of the light liquid = ρ1

Density of the heavy liquid = ρ2

Height from top surface of light liquid to the top surface of the block = h0

Height from the top of the block to the liquids interface = h1

Height from liquid interface to the bottom of block = h2

Archimedes' principle,

According to Archimedes principle the upward buoyant force that is exerted on a body immersed in a fluid, is equal to the weight of the fluid that the body displaces.

Answer 6

Chapter 3, Problem 3.46P

Interpretation Introduction

(a)

Interpretation:

A formula for the density of the block should be derived.

Concept introduction:

It is given that a rectangular block floats at the interface between two immiscible liquids. The dimensions of the block are given as follows,

Height of the block = L

Cross sectional area of the block = A

Density of the light liquid = ρ1

Density of the heavy liquid = ρ2

Height from top surface of light liquid to the top surface of the block = h0

Height from the top of the block to the liquids interface = h1

Height from liquid interface to the bottom of block = h2

Archimedes' principle,

According to Archimedes principle the upward buoyant force that is exerted on a body immersed in a fluid, is equal to the weight of the fluid that the body displaces.

Answer 7

Chapter 3, Problem 3.46P

Interpretation Introduction

(a)

Interpretation:

A formula for the density of the block should be derived.

Concept introduction:

It is given that a rectangular block floats at the interface between two immiscible liquids. The dimensions of the block are given as follows,

Height of the block = L

Cross sectional area of the block = A

Density of the light liquid = ρ1

Density of the heavy liquid = ρ2

Height from top surface of light liquid to the top surface of the block = h0

Height from the top of the block to the liquids interface = h1

Height from liquid interface to the bottom of block = h2

Archimedes' principle,

According to Archimedes principle the upward buoyant force that is exerted on a body immersed in a fluid, is equal to the weight of the fluid that the body displaces.

Answer 8

Interpretation Introduction

(b)

Interpretation:

Prove that the two approaches used to balance force on the block are correct.

Concept introduction:

It is given that a rectangular block floats at the interface between two immiscible liquids. The dimensions of the block are given as follows,

Height of the block = L

Cross sectional area of the block = A

Density of the light liquid = ρ1

Density of the heavy liquid = ρ2

Height from top surface of light liquid to the top surface of the block = h0

Height from the top of the block to the liquids interface = h1

Height from liquid interface to the bottom of block = h2

Archimedes' principle,

According to Archimedes principle the upward buoyant force that is exerted on a body immersed in a fluid, is equal to the weight of the fluid that the body displaces.

Answer 9

Interpretation Introduction

(b)

Interpretation:

Prove that the two approaches used to balance force on the block are correct.

Concept introduction:

It is given that a rectangular block floats at the interface between two immiscible liquids. The dimensions of the block are given as follows,

Height of the block = L

Cross sectional area of the block = A

Density of the light liquid = ρ1

Density of the heavy liquid = ρ2

Height from top surface of light liquid to the top surface of the block = h0

Height from the top of the block to the liquids interface = h1

Height from liquid interface to the bottom of block = h2

Archimedes' principle,

According to Archimedes principle the upward buoyant force that is exerted on a body immersed in a fluid, is equal to the weight of the fluid that the body displaces.

Answer 10

Expert Solution & Answer

Answer 11

Expert Solution & Answer

Answer 12

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 13

Ch. 3 - Perform the following estimations without using a...Ch. 3 - Prob. 3.2P Ch. 3 - Prob. 3.3P Ch. 3 - Prob. 3.4P Ch. 3 - Prob. 3.5P Ch. 3 - Prob. 3.6P Ch. 3 - Prob. 3.7P Ch. 3 - Prob. 3.8P Ch. 3 - Prob. 3.9P Ch. 3 - A rectangular block of solid carbon (graphite)...

Concept explainers

Want to see the full answer?

Chapter 3 Solutions