Concept explainers
(a)
Interpretation:
The molecular formula of the compound with empirical formula
Concept introduction:
An empirical formula gives the simplest whole number ratio of atoms of each element present in a compound. The molecular formula tells the exact number of atoms of each element present in a compound.
Following are the steps to determine the molecular formula of a compound.
Step 1: Add the molar mass of each element multiplied by its number of atoms present in the empirical formula to obtain the empirical formula mass for the compound.
Step 2: Divide the molar mass of the compound by its empirical formula mass to obtain the whole number. The formula to calculate the whole number multiple is as follows:
Step 3: Multiply the whole number with the subscript of each element present in the empirical formula. This gives the molecular formula of the compound.
(b)
Interpretation:
The molecular formula of the compound with empirical formula
Concept introduction:
An empirical formula gives the simplest whole number ratio of atoms of each element present in a compound. The molecular formula tells the exact number of atoms of each element present in a compound.
Following are the steps to determine the molecular formula of a compound.
Step 1: Add the molar mass of each element multiplied by its number of atoms present in the empirical formula to obtain the empirical formula mass for the compound.
Step 2: Divide the molar mass of the compound by its empirical formula mass to obtain the whole number. The formula to calculate the whole number multiple is as follows:
Step 3: Multiply the whole number with the subscript of each element present in the empirical formula. This gives the molecular formula of the compound.
(c)
Interpretation:
The molecular formula of the compound with empirical formula
Concept introduction:
An empirical formula gives the simplest whole number ratio of atoms of each element present in a compound. The molecular formula tells the exact number of atoms of each element present in a compound.
Following are the steps to determine the molecular formula of a compound.
Step 1: Add the molar mass of each element multiplied by its number of atoms present in the empirical formula to obtain the empirical formula mass for the compound.
Step 2: Divide the molar mass of the compound by its empirical formula mass to obtain the whole number. The formula to calculate the whole number multiple is as follows:
Step 3: Multiply the whole number with the subscript of each element present in the empirical formula. This gives the molecular formula of the compound.
(d)
Interpretation:
The molecular formula of the compound with empirical formula
Concept introduction:
An empirical formula gives the simplest whole number ratio of atoms of each element present in a molecule. The molecular formula tells the exact number of atoms of each element present in a molecule.
Following are the steps to determine the molecular formula of a compound.
Step 1: Add the molar mass of each element multiplied by its number of atoms present in the empirical formula to obtain the empirical formula mass for the compound.
Step 2: Divide the molar mass of the compound by its empirical formula mass to obtain the whole number. The formula to calculate the whole number multiple is as follows:
Step 3: Multiply the whole number with the subscript of each element present in the empirical formula. This gives the molecular formula of the compound.
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Chapter 3 Solutions
CHEMISTRY MOLECULAR NATURE OF MATTER
- 1. For an unknown compound with a molecular formula of C8H100: a. What is the DU? (show your work) b. Solve the structure and assign each of the following spectra. 8 6 2 ō (ppm) 4 2 0 200 150 100 50 ō (ppm) LOD D 4000 3000 2000 1500 1000 500 HAVENUMBERI -11arrow_forward16. The proton NMR spectral information shown in this problem is for a compound with formula CioH,N. Expansions are shown for the region from 8.7 to 7.0 ppm. The normal carbon-13 spec- tral results, including DEPT-135 and DEPT-90 results, are tabulated: 7 J Normal Carbon DEPT-135 DEPT-90 19 ppm Positive No peak 122 Positive Positive cus и 124 Positive Positive 126 Positive Positive 128 No peak No peak 4° 129 Positive Positive 130 Positive Positive (144 No peak No peak 148 No peak No peak 150 Positive Positive してしarrow_forward3. Propose a synthesis for the following transformation. Do not draw an arrow-pushing mechanism below, but make sure to draw the product of each proposed step (3 points). + En CN CNarrow_forward
- Label the spectrum with spectroscopyarrow_forwardLabel the spectrum with spectroscopyarrow_forwardQ1: Draw the most stable and the least stable Newman projections about the C2-C3 bond for each of the following isomers (A-C). Are the barriers to rotation identical for enantiomers A and B? How about the diastereomers (A versus C or B versus C)? enantiomers H Br H Br (S) CH3 H3C (S) (R) CH3 H3C H Br A Br H C H Br H3C (R) B (R)CH3 H Br H Br H3C (R) (S) CH3 Br H D identicalarrow_forward
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