Concept explainers
(a)
Interpretation:
Lewis structure of
Concept Introduction:
Lewis structure represents covalent bonds and describes valence electrons configuration of atoms. The covalent bonds are depicted by lines and unshared electron pairs by pairs of dots. The sequence to write Lewis structure of some molecule is given as follows:
- The central atom is identified and various other atoms are arranged around it. This central atom so chosen is often the least electronegative.
- Total valence electrons are estimated for each atom.
- single bond is first placed between each atom pair.
- The electrons left can be allocated as unshared electron pairs or as multiple bonds around
symbol of element to satisfy the octet (or duplet) for each atom. - Add charge on overall structure in case of polyatomic cation or anion.
Hybridization is calculated by the hybrid orbitals and to calculate hybrid orbitals we need to know the steric number that is given by,
The relation of steric number with geometry or shape is depicted in the table below.
(a)

Explanation of Solution
The molecule
Electronic configuration of
Electronic configuration of
Thus total valence electrons are sum of the valence electrons for each atom in
The skeleton structure
Hence, 20 electrons are allocated as 3 lone pairs on each iodine atom and 1 lone pair on nitrogen. The Lewis structure of
As from the structure above, there are 3 bond pairs and 1 lone pair on central atom.
Substitute 3 for number of atoms bonded to central atom and 1 for number of lone pairs on central atom in equation (1) to determine steric number.
The shape of the molecule is defined by the lone pairs present on the central atom. Molecule
(b)
Interpretation:
Lewis structure of
Concept Introduction:
Refer to part (a).
(b)

Explanation of Solution
The molecule
Electronic configuration of
Electronic configuration of
Thus total valence electrons is sum of the valence electrons for each atom in
The skeleton structure
Hence, 18 electrons are allocated as 3 lone pairs on each iodine atom. The Lewis structure of
As from the structure above, there are 3 bond pairs and 0 lone pairs on central atom.
Substitute 3 for number of atoms bonded to central atom and 0 for number of lone pairs on central atom in equation (1) to determine steric number.
The shape of the molecule is defined by the lone pairs present on the central atom. Molecule
Want to see more full solutions like this?
Chapter 3 Solutions
ACHIEVE/CHEMICAL PRINCIPLES ACCESS 2TERM
- Q5: Label each chiral carbon in the following molecules as R or S. Make sure the stereocenter to which each of your R/S assignments belong is perfectly clear to the grader. (8pts) R OCH 3 CI H S 2pts for each R/S HO R H !!! I OH CI HN CI R Harrow_forwardCalculate the proton and carbon chemical shifts for this structurearrow_forwardA. B. b. Now consider the two bicyclic molecules A. and B. Note that A. is a dianion and B. is a neutral molecule. One of these molecules is a highly reactive compound first characterized in frozen noble gas matrices, that self-reacts rapidly at temperatures above liquid nitrogen temperature. The other compound was isolated at room temperature in the early 1960s, and is a stable ligand used in organometallic chemistry. Which molecule is the more stable molecule, and why?arrow_forward
- A mixture of C7H12O2, C9H9OCl, biphenyl and acetone was put together in a gas chromatography tube. Please decide from the GC resutls which correspond to the peak for C7,C9 and biphenyl and explain the reasoning based on GC results. Eliminate unnecessary peaks from Gas Chromatography results.arrow_forwardIs the molecule chiral, meso, or achiral? CI .CH3 H₂C CIarrow_forwardPLEASE HELP ! URGENT!arrow_forward
- Identify priority of the substituents: CH3arrow_forwardHow many chiral carbons are in the molecule? OH F CI Brarrow_forwardA mixture of three compounds Phen-A, Acet-B and Rin-C was analyzed using TLC with 1:9 ethanol: hexane as the mobile phase. The TLC plate showed three spots of R, 0.1 and 0.2 and 0.3. Which of the three compounds (Phen-A; Acet-B or Rin-C) would have the highest (Blank 1), middle (Blank 2) and lowest (Blank 3) spot respectively? 0 CH: 0 CH, 0 H.C OH H.CN OH Acet-B Rin-C phen-A A A <arrow_forward
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningChemistry by OpenStax (2015-05-04)ChemistryISBN:9781938168390Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark BlaserPublisher:OpenStaxChemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage Learning
- Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning





