All of the intermolecular interactions present in cis-1, 2-dichloroethene and trans-1, 2-dichloroethene are to be listed. Also using this information, the differences in their boiling points are to be compared. Concept introduction: The boiling point of a compound depends on the intermolecular forces of attraction. As the strength of intermolecular force of attraction increases, the energy required to overcome this barrier of force of attraction increases. The strength of the intermolecular interactions from the weakest to the strongest is as follows: Dispersion forces < Induced dipole-induced dipole < Dipole-dipole < Hydrogen bonding < Ion-dipole < Ion–ion. As the strength of intermolecular forces increases, the boiling point of the compound increases.

Question

Want to see the full answer?

Answer 1

Question

Chapter 3, Problem 3.22P

Interpretation Introduction

Interpretation:

All of the intermolecular interactions present in cis-1, 2-dichloroethene and trans-1, 2-dichloroethene are to be listed. Also using this information, the differences in their boiling points are to be compared.

Concept introduction:

The boiling point of a compound depends on the intermolecular forces of attraction. As the strength of intermolecular force of attraction increases, the energy required to overcome this barrier of force of attraction increases. The strength of the intermolecular interactions from the weakest to the strongest is as follows:

Dispersion forces < Induced dipole-induced dipole < Dipole-dipole < Hydrogen bonding < Ion-dipole < Ion–ion.

As the strength of intermolecular forces increases, the boiling point of the compound increases.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

3. Consider the compounds below and determine if they are aromatic, antiaromatic, or non-aromatic. In case of aromatic or anti-aromatic, please indicate number of I electrons in the respective systems. (Hint: 1. Not all lone pair electrons were explicitly drawn and you should be able to tell that the bonding electrons and lone pair electrons should reside in which hybridized atomic orbital 2. You should consider ring strain- flexibility and steric repulsion that facilitates adoption of aromaticity or avoidance of anti- aromaticity) H H N N: NH2 N Aromaticity (Circle) Aromatic Aromatic Aromatic Aromatic Aromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic nonaromatic nonaromatic nonaromatic nonaromatic nonaromatic aromatic TT electrons Me H Me Aromaticity (Circle) Aromatic Aromatic Aromatic Aromatic Aromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic nonaromatic nonaromatic nonaromatic nonaromatic nonaromatic aromatic πT electrons H HH…

A chemistry graduate student is studying the rate of this reaction: 2 HI (g) →H2(g) +12(g) She fills a reaction vessel with HI and measures its concentration as the reaction proceeds: time (minutes) [IH] 0 0.800M 1.0 0.301 M 2.0 0.185 M 3.0 0.134M 4.0 0.105 M Use this data to answer the following questions. Write the rate law for this reaction. rate = 0 Calculate the value of the rate constant k. k = Round your answer to 2 significant digits. Also be sure your answer has the correct unit symbol.

None