Chapter 3, Problem 3.127QP

Interpretation Introduction

Interpretation:

The number of grams of $\text{65\%}$ Sulfur required to produce $\text{87}\text{.0}\text{g}{\text{H}}_{\text{2}}\text{SO}$ has to be determined.

Concept introduction:

Mole:

Number of atoms present in gram atomic mass of element is known as Avogadro number.

Avogadro number is $6.022136\times {10}^{23}$

One mole equal of atom equal to Avogadro number $(6.022136\times {10}^{23})$ hence, 1 mole of Iron contain atom $6.022136\times {10}^{23}$ $\text{Fe}$ atoms.

The mole of taken gram mass of compound is given by ratio of given mass of compound to molar mass of compound.

$\text{Mole}\text{=}\frac{\text{Mass}}{\text{Molar}\text{mass}}$